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How do you round to significant figures, estimate a calculation, and find the upper and lower bounds of a rounded quantity?

Round to a given number of decimal places or significant figures; estimate calculations; and find and use upper and lower bounds, including in calculations (Higher tier).

A focused answer to the OCR GCSE Mathematics number content on rounding, estimation and bounds, covering decimal places and significant figures, estimating calculations, and finding and using upper and lower bounds.

Generated by Claude Opus 4.810 min answer

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  1. What this dot point is asking
  2. Rounding to decimal places and significant figures
  3. Estimating calculations
  4. Bounds (Higher)
  5. Why bounds matter

What this dot point is asking

OCR references N5 and N15 cover rounding to decimal places and significant figures, estimating calculations by rounding, and at Higher tier finding and using upper and lower bounds. These are the tools for handling measurement and approximation: real quantities are never exact, and a measured value carries a margin of error you can quantify. Estimation is tested on the non-calculator paper as a check on calculator answers, while bounds are a reliably tricky Higher topic.

Rounding to decimal places and significant figures

Both kinds of rounding use the same decision rule but count from a different place.

So 3.141593.14159 to 22 d.p. is 3.143.14, and to 33 s.f. is also 3.143.14. But 0.0040720.004072 to 22 s.f. is 0.00410.0041 (the first significant figure is the 44), and 4862048\,620 to 22 s.f. is 4900049\,000 (the trailing zeros hold place value). Watch the carry: 9.979.97 to 11 d.p. rounds to 10.010.0, because the 99 tenths round up.

Estimating calculations

Estimation gives a quick sanity check and is examined in its own right.

To estimate, round every number to one significant figure and work with the friendly values. This catches calculator slips: if your machine says a bill is £12401240 but the estimate is £120120, you have a factor-of-ten error somewhere. The notation \approx ("approximately equal to") signals an estimate. The awkward case is dividing by a small decimal: dividing by 0.20.2 multiplies by 55, so estimates involving small divisors get large.

Bounds (Higher)

Every rounded measurement hides a range of true values.

To get the extreme value of a calculation, choose bounds carefully. A sum or product is largest when both inputs are at their upper bound. A difference aba - b is largest when aa is at its upper bound and bb at its lower bound. A quotient ab\tfrac{a}{b} is largest when aa is at its upper bound and bb at its lower bound, because dividing by a smaller number gives more.

Why bounds matter

Bounds turn "measured roughly" into a precise statement about the possible answer, which OCR uses to test reasoning (AO2) as much as calculation. They tie directly into compound measures such as speed and density, where each measured quantity carries its own margin. A frequent Higher question asks you to find both bounds of an answer and then state it "to a suitable degree of accuracy", which means quoting the digits the upper and lower bounds agree on.

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20183 marksEstimate the value of 59.3×4.180.21\dfrac{59.3 \times 4.18}{0.21} by rounding each number to one significant figure. (Foundation, Paper 2, non-calculator.)
Show worked answer →

Round each number to one significant figure: 59.36059.3 \approx 60, 4.1844.18 \approx 4, 0.210.20.21 \approx 0.2.

The estimate is 60×40.2=2400.2=1200\dfrac{60 \times 4}{0.2} = \dfrac{240}{0.2} = 1200.

Markers award a mark for rounding all three numbers to one significant figure, a mark for the calculation, and a mark for the answer 12001200. Dividing by 0.20.2 trips students up: dividing by 0.20.2 is the same as multiplying by 55, so 240÷0.2=1200240 \div 0.2 = 1200, not 4848.

OCR 20224 marksA rectangle has length 8.48.4 cm and width 3.63.6 cm, each measured to the nearest 0.10.1 cm. Calculate the upper bound for the area of the rectangle. (Higher, Paper 4, calculator.)
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Each measurement is to the nearest 0.10.1 cm, so the bounds are half of 0.10.1, that is 0.050.05 cm, either side.

Upper bound of length: 8.4+0.05=8.458.4 + 0.05 = 8.45 cm. Upper bound of width: 3.6+0.05=3.653.6 + 0.05 = 3.65 cm.

For the largest area, multiply the two upper bounds: 8.45×3.65=30.84258.45 \times 3.65 = 30.8425 cm2^2.

Markers give a mark for the half-unit 0.050.05, a mark for each upper bound, and a mark for the area 30.842530.8425 cm2^2. Using 8.58.5 and 3.73.7 (rounding up by a whole 0.10.1 instead of 0.050.05) is the standard error.

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