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How do you calculate with compound measures such as speed, density and pressure, including unit conversions?

Use compound measures including speed, density and pressure; rearrange the defining formulae; and convert between units such as m/s and km/h.

A focused answer to the OCR GCSE Mathematics ratio content on compound measures, covering speed, density and pressure, rearranging the defining formulae, and converting between compound units.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Speed, distance and time
  3. Density and pressure
  4. Converting compound units
  5. Why compound measures matter

What this dot point is asking

OCR references R1 and R11 cover compound measures: quantities built from two others, such as speed (distance per time), density (mass per volume) and pressure (force per area). You must use and rearrange the defining formulae and convert between compound units like m/s and km/h. Compound measures connect ratio to science and to real-life contexts, and they appear on every tier, frequently on the calculator paper, often as multi-step problems that reward AO3.

Speed, distance and time

Speed is the most common compound measure.

The unit of time matters: for km/h, the time must be in hours. A journey of 9090 km in 11 hour 3030 minutes uses 1.51.5 hours, giving 901.5=60\dfrac{90}{1.5} = 60 km/h. "Average speed" assumes constant speed over the whole journey, so total distance over total time, even if the actual speed varied. Distance-time graphs link to this directly, where the gradient is the speed.

Density and pressure

Density and pressure follow the same pattern.

So a block of mass 480480 g and volume 6060 cm3^3 has density 48060=8\dfrac{480}{60} = 8 g/cm3^3, and a force of 200200 N on an area of 0.50.5 m2^2 gives a pressure of 2000.5=400\dfrac{200}{0.5} = 400 N/m2^2. A common link is that the same material has the same density, so finding one block's density lets you find another block's mass or volume.

Pressure questions often involve a shape resting on a surface, where the area is the area of contact. A heavier object spread over a larger area can exert less pressure than a lighter object on a small point, which is why a drawing pin pierces easily (tiny area, high pressure) while a person on snowshoes does not sink (large area, low pressure). Reading the question to identify which quantity is force and which is area, then choosing the right rearrangement of P=FAP = \tfrac{F}{A}, is the key step that OCR rewards with method marks.

Converting compound units

Converting between m/s and km/h is a classic Higher skill.

The same care applies to density (g/cm3^3 to kg/m3^3 multiplies by 10001000) and to areas and volumes, where the conversion factor is squared or cubed. Always write the units alongside the number, because a compound measure without its units is incomplete.

Why compound measures matter

Compound measures are where mathematics meets physics and everyday life: speed limits, fuel economy, material density, tyre pressure. OCR rewards correct units and clear rearrangement, and the formula-triangle approach makes the algebra reliable under exam pressure. Because the questions are usually multi-step (find one quantity, then use it), method marks are available throughout even if the final figure slips.

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20183 marksA car travels 150150 km in 22 hours 3030 minutes. Work out its average speed in km/h. (Foundation, Paper 1, calculator.)
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Speed is distance divided by time, and the time must be in hours.

Convert 22 hours 3030 minutes to 2.52.5 hours (since 3030 minutes is 0.50.5 of an hour).

Speed =1502.5=60= \dfrac{150}{2.5} = 60 km/h.

Markers award a mark for converting the time to 2.52.5 hours, a mark for the correct formula, and a mark for 6060 km/h. Using 2.302.30 hours instead of 2.52.5 hours is the standard error, because 3030 minutes is half an hour, not 0.300.30 of an hour.

OCR 20214 marksA metal block has a mass of 780780 g and a volume of 100100 cm3^3. Work out its density in g/cm3^3, then find the mass of a second block of the same metal with volume 250250 cm3^3. (Higher, Paper 4, calculator.)
Show worked answer →

Density is mass divided by volume: 780100=7.8\dfrac{780}{100} = 7.8 g/cm3^3.

For the second block, rearrange to mass == density ×\times volume: 7.8×250=19507.8 \times 250 = 1950 g.

Markers give a mark for the density formula, a mark for 7.87.8 g/cm3^3, a mark for rearranging to find mass, and a mark for 19501950 g. The same metal has the same density, which is the key link between the two parts.

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