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How do you draw and interpret bar charts, pie charts, frequency polygons, histograms and box plots?

Draw and interpret statistical charts including bar charts, pie charts, frequency polygons, stem-and-leaf diagrams, box plots and histograms with unequal class widths (histograms at Higher tier).

A focused answer to the Eduqas GCSE Mathematics statistics content on charts and graphs, covering bar charts, pie charts, frequency polygons, stem-and-leaf diagrams, box plots, and histograms with unequal class widths and frequency density at Higher tier.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Bar charts and pie charts
  3. Frequency polygons and stem-and-leaf diagrams
  4. Box plots
  5. Histograms with frequency density (Higher)
  6. Why charts matter

What this dot point is asking

The Eduqas statistics content asks you to draw and interpret a range of statistical charts: bar charts, pie charts, frequency polygons, stem-and-leaf diagrams, box plots, and at Higher tier histograms with unequal class widths. Each display suits a different kind of data and answers a different question, so choosing and reading the right one is the core skill. Pie-chart angles and box-plot comparisons appear at both tiers, while the histogram with frequency density is a signature Higher-tier topic because of the unequal-width subtlety.

Bar charts and pie charts

These two are the most common displays for categorical or discrete data.

For a pie chart, the reliable method is to find the angle per item (360total\dfrac{360^\circ}{\text{total}}) and multiply by each frequency. To read a pie chart back, reverse this: a 9090^\circ sector is a quarter of the total.

Frequency polygons and stem-and-leaf diagrams

A frequency polygon plots the frequency against the midpoint of each class and joins the points with straight lines, which is useful for showing the shape of a distribution and comparing two distributions on the same axes. A stem-and-leaf diagram splits each value into a stem (the leading digits) and a leaf (the final digit), keeping the raw data while showing its shape; an ordered stem-and-leaf diagram makes the median and range easy to read directly.

Box plots

A box plot (box-and-whisker diagram) summarises a distribution using five numbers.

Box plots are ideal for comparing two distributions: a higher median means typically larger values, and a wider box (larger interquartile range) means more spread. As with all comparisons, describe the difference in context.

Histograms with frequency density (Higher)

A histogram looks like a bar chart but is fundamentally different when class widths are unequal.

The defining point is that area, not height, gives the frequency, which is why histograms (unlike bar charts) have no gaps and are used for continuous, unequally grouped data.

Why charts matter

Choosing and reading statistical displays is a practical skill used across science, geography and the media, and Eduqas tests both the construction (drawing accurately) and the interpretation (reading values, comparing distributions). The histogram is the conceptual high point because it forces the distinction between frequency and frequency density, so understanding that area represents frequency is the key to the Higher-tier marks.

Exam-style practice questions

Practice questions written in the style of WJEC Eduqas exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Eduqas 20183 marksIn a survey of 90 people's favourite drink, 30 chose tea. Work out the angle that represents tea on a pie chart. (Foundation, Component 2, calculator.)
Show worked answer →

A pie chart represents the whole data set as 360360^\circ.

Each person is worth 36090=4\dfrac{360^\circ}{90} = 4^\circ.

Tea was chosen by 30 people, so its angle is 30×4=12030 \times 4^\circ = 120^\circ.

Markers award a mark for the angle per person, a mark for the method, and a mark for the answer 120120^\circ. Using 100 instead of 360 (treating it as a percentage) is the standard error in pie-chart questions.

Eduqas 20224 marksA histogram has a class 10 to 30 (width 20) with frequency 40. Work out the frequency density for this class, and find the frequency of a class 30 to 35 (width 5) whose bar has frequency density 6. (Higher, Component 1, non-calculator.)
Show worked answer →

Frequency density is frequency divided by class width.

For 10 to 30: 4020=2\dfrac{40}{20} = 2 per unit.

For 30 to 35, rearrange to frequency == frequency density ×\times class width =6×5=30= 6 \times 5 = 30.

Markers give marks for the first frequency density 2, for rearranging the relationship, and for the frequency 30. Reading the bar height as the frequency itself, instead of the frequency density, is the central histogram error.

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