Skip to main content
EnglandMathsSyllabus dot point

How do you find and compare the mean, median, mode and range, including from frequency tables?

Calculate the mean, median, mode and range; find the mean from a frequency table and an estimated mean from grouped data; and compare distributions using an average and the range (and quartiles at Higher tier).

A focused answer to the Eduqas GCSE Mathematics statistics content on averages and spread, covering the mean median mode and range, the mean from a frequency table, the estimated mean from grouped data, and comparing distributions with quartiles at Higher tier.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. The four measures
  3. The mean from a frequency table
  4. The estimated mean from grouped data
  5. Comparing distributions
  6. Choosing the right average

What this dot point is asking

The Eduqas statistics content asks you to find the four summary measures, the mean, median, mode and range, and to calculate the mean from a frequency table and an estimated mean from grouped data. At Higher tier you also compare distributions using an average and a measure of spread, including quartiles. Averages summarise a data set in a single value, and spread measures how varied it is, so together they describe the whole distribution. These are core statistics, tested at both tiers, with the grouped-data estimated mean being a reliable multi-step question.

The four measures

Each summary measure captures a different feature of the data.

So for 3,5,5,8,93, 5, 5, 8, 9: the mean is 305=6\dfrac{30}{5} = 6, the median is 55, the mode is 55, and the range is 93=69 - 3 = 6. The mean uses every value but is affected by extreme values (outliers); the median is more robust to them, which is why house prices are often quoted as a median.

The mean from a frequency table

When data is given as values with frequencies, multiply each value by its frequency.

So if 00 goals occurred 55 times, 11 goal 88 times and 22 goals 77 times: fx=(0×5)+(1×8)+(2×7)=22\sum fx = (0 \times 5) + (1 \times 8) + (2 \times 7) = 22, and f=20\sum f = 20, so the mean is 2220=1.1\dfrac{22}{20} = 1.1 goals. The frequent error is dividing by the number of rows instead of the total frequency.

The estimated mean from grouped data

When data is grouped into class intervals, the exact values are unknown, so the midpoint of each class represents it.

It is an estimate because the midpoint assumes the values in each class are evenly spread, which they may not be.

Comparing distributions

To compare two data sets, quote both a typical value and a measure of spread.

A comparison needs an average (mean or median) to say which set is typically higher, and a measure of spread to say which is more consistent. So "Class A had a higher mean mark (6868 versus 6161) but a larger range (4040 versus 2525), so A scored higher on average but was less consistent." At Higher tier, the interquartile range (upper quartile minus lower quartile) is a better measure of spread than the range because it ignores extreme values, focusing on the middle 50%50\% of the data. Always make the comparison in context, naming what the figures mean.

Choosing the right average

Each average suits different data. The mean is the best summary for fairly symmetric data with no extreme values, because it uses every data point. The median is preferred when there are outliers or the data is skewed, since it is not dragged towards an extreme value; this is why incomes and house prices are usually quoted as medians. The mode is the only average that works for qualitative (categorical) data, such as the most popular colour, and it is useful for finding the most common value. Eduqas sometimes asks which average is most appropriate and why, so being able to justify the choice in context, not just calculate each one, is part of the skill.

Exam-style practice questions

Practice questions written in the style of WJEC Eduqas exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Eduqas 20193 marksFind the mean, median and range of the data set: 4, 7, 7, 9, 13. (Foundation, Component 1, non-calculator.)
Show worked answer →

Mean: add the values and divide by how many there are. 4+7+7+9+135=405=8\dfrac{4 + 7 + 7 + 9 + 13}{5} = \dfrac{40}{5} = 8.

Median: the middle value when ordered. The data is already ordered, and the middle of 5 values is the 3rd, which is 7.

Range: largest minus smallest =134=9= 13 - 4 = 9.

Markers award a mark for the mean, a mark for the median, and a mark for the range. Forgetting to order the data before finding the median (not needed here, but a habit) and confusing the range with the mean are the usual errors.

Eduqas 20224 marksThe table shows the time, in minutes, that 40 students spent on homework, grouped as 0 to 20, 20 to 40 and 40 to 60, with frequencies 10, 22 and 8. Estimate the mean time. (Higher, Component 2, calculator.)
Show worked answer →

Use the midpoint of each class as a representative value: 10, 30 and 50 minutes.

Multiply each midpoint by its frequency: 10×10=10010 \times 10 = 100, 30×22=66030 \times 22 = 660, 50×8=40050 \times 8 = 400.

Total of these =100+660+400=1160= 100 + 660 + 400 = 1160. Divide by the total frequency 40: 116040=29\dfrac{1160}{40} = 29 minutes.

Markers give marks for the midpoints, for the sum of midpoint times frequency, and for dividing by 40. Using the class boundaries instead of midpoints, or dividing by the number of classes instead of 40, are the common slips.

Related dot points

Sources & how we know this