Skip to main content
EnglandMathsSyllabus dot point

How do you use the probability scale, find probabilities of single and combined events, and use sample space diagrams?

Use the probability scale from 0 to 1; calculate probabilities of single events from equally likely outcomes; use the fact that probabilities sum to 1; and list combined outcomes using sample space diagrams.

A focused answer to the Eduqas GCSE Mathematics probability content on the basics, covering the probability scale, single events from equally likely outcomes, the sum of probabilities, and listing combined outcomes with sample space diagrams.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. The probability scale
  3. Single events from equally likely outcomes
  4. The sum of probabilities and the complement
  5. Sample space diagrams
  6. Why the basics matter

What this dot point is asking

The Eduqas probability content begins with the basics: using the probability scale from 00 to 11, finding the probability of a single event from equally likely outcomes, using the fact that probabilities sum to 11 (so the complement is 11 - the probability), and listing the outcomes of two combined events with a sample space diagram. These ideas underpin every later probability topic, and Eduqas tests them at both tiers with bags of counters, dice, spinners and cards. The sample space diagram for two dice is a recurring, reliable question.

The probability scale

Every probability is a number between 00 and 11, which can be written as a fraction, decimal or percentage.

A probability can never be negative or greater than 11, which is a useful check: an answer outside that range signals an error. Eduqas may give the scale and ask you to mark an event's likelihood on it, or to convert between a fraction, a decimal and a percentage.

Single events from equally likely outcomes

When all outcomes are equally likely, probability is a simple ratio.

The phrase "at random" or "fair" tells you the outcomes are equally likely. From a bag of 33 red and 77 blue counters, P(red) =310= \dfrac{3}{10}. Always count the total carefully, including every category, before forming the fraction.

The sum of probabilities and the complement

Because some outcome must occur, all the probabilities add to 11.

This is one of the most useful tools, because the complement is often far easier to count than the event itself. To find the probability of "at least one" of something, it is usually quicker to find the probability of "none" and subtract from 11.

Sample space diagrams

A sample space diagram lists every outcome of two combined events, making counting systematic.

For two dice, the grid has 3636 cells, and many questions ask about the total of the two scores, so listing the totals in the grid lets you count outcomes for "total of 7", "an even total", and so on.

Why the basics matter

These foundations support tree diagrams, Venn diagrams and expected outcomes, all of which build on counting equally likely outcomes and using the sum-to-one rule. Because Eduqas weights reasoning across the paper, probability questions often ask you to interpret a result or justify a fairness claim, so understanding the scale and the complement, not just the arithmetic, is what secures full marks.

Exam-style practice questions

Practice questions written in the style of WJEC Eduqas exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Eduqas 20183 marksA bag contains 5 red, 3 blue and 2 green counters. One counter is taken at random. Work out the probability that it is red, and the probability that it is not green. (Foundation, Component 2, calculator.)
Show worked answer →

There are 5+3+2=105 + 3 + 2 = 10 counters in total.

The probability of red is 510=12\dfrac{5}{10} = \dfrac{1}{2}.

The probability of green is 210=15\dfrac{2}{10} = \dfrac{1}{5}, so the probability of not green is 115=451 - \dfrac{1}{5} = \dfrac{4}{5}.

Markers award a mark for the total, a mark for P(red), and a mark for P(not green). Using 12101 - \dfrac{2}{10} for the complement is the key step, and forgetting to subtract from 1 is the usual error.

Eduqas 20224 marksTwo fair six-sided dice are rolled and their scores are added. Use a sample space diagram to find the probability that the total is 8, and the probability that the total is at least 10. (Higher, Component 2, calculator.)
Show worked answer →

A sample space diagram lists all 6×6=366 \times 6 = 36 equally likely totals.

The total of 8 occurs for (2,6),(3,5),(4,4),(5,3),(6,2)(2,6), (3,5), (4,4), (5,3), (6,2), which is 5 outcomes, so P(8) =536= \dfrac{5}{36}.

A total of at least 10 means 10, 11 or 12: that is (4,6),(5,5),(6,4)(4,6),(5,5),(6,4) for 10, (5,6),(6,5)(5,6),(6,5) for 11, and (6,6)(6,6) for 12, giving 3+2+1=63 + 2 + 1 = 6 outcomes, so 636=16\dfrac{6}{36} = \dfrac{1}{6}.

Markers give marks for the 36 outcomes, for P(8), and for P(at least 10). Counting 36 outcomes wrongly, or missing an outcome in the "at least" count, are the common slips.

Related dot points

Sources & how we know this