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How do you calculate and interpret the mean, median, mode and range, including from frequency and grouped frequency tables?

Calculate and interpret the mean, median, mode and range for lists and frequency tables, estimate the mean and identify the modal class from grouped data, and compare distributions using an average and a measure of spread.

A focused answer to the WJEC GCSE Mathematics statistics content on averages and spread, covering the mean, median, mode and range for lists and frequency tables, estimating the mean and modal class from grouped data, and comparing distributions.

Generated by Claude Opus 4.812 min answer

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  1. What this dot point is asking
  2. The three averages and the range
  3. Averages from a frequency table
  4. Grouped data (Higher)
  5. Comparing distributions
  6. Why this matters

What this dot point is asking

This is the calculation core of WJEC statistics. You are asked to find and interpret the three averages (mean, median and mode) and the range as a measure of spread, to work them out from a list, from a frequency table and, at Higher tier, from a grouped frequency table where you estimate the mean and identify the modal class. The final, examined skill is to compare two sets of data using one average and one measure of spread, written in context. Choosing the right average for the situation is also assessed.

The three averages and the range

Each average summarises the data differently.

So for 2,4,4,92, 4, 4, 9: the mean is 194=4.75\tfrac{19}{4} = 4.75, the median is 4+42=4\tfrac{4+4}{2} = 4, the mode is 44, and the range is 92=79 - 2 = 7.

Averages from a frequency table

A frequency table records how many times each value occurs.

To find the mean, multiply each value xx by its frequency ff, add these products to get fx\sum fx, then divide by the total frequency f\sum f. The mode is the value with the highest frequency. The median is the value of the middle item: find its position n+12\tfrac{n+1}{2} and read across the cumulative count. Reading the table carefully (frequencies, not values, are summed for the count) is where care is needed.

Grouped data (Higher)

When data is grouped into classes, individual values are lost, so the mean can only be estimated.

The mean is an estimate because the midpoint stands in for every value in the class, and the true values are unknown. The modal class is a class, not a single number, so name the interval rather than a value.

Comparing distributions

Comparing two data sets is the highest-value skill here.

Why this matters

Averages and spread are among the most frequently examined statistics topics, appearing in short calculation questions and in extended "compare" questions that carry AO2 and AO3 marks for reasoning in context. The grouped-data mean estimate is a classic Higher technique, and choosing the appropriate average (the median resists extreme values, the mean uses all the data, the mode suits categories) is itself assessed. The discipline of always pairing an average with a measure of spread in a comparison is the habit that secures full marks.

Exam-style practice questions

Practice questions written in the style of WJEC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

WJEC 20183 marksThe numbers of goals scored in 77 matches are 1,3,0,2,3,5,11, 3, 0, 2, 3, 5, 1. Work out the mean, the median and the mode. (Foundation and Higher, Unit 1, non-calculator.)
Show worked answer →

Mean: add and divide by the count. Sum =1+3+0+2+3+5+1=15= 1 + 3 + 0 + 2 + 3 + 5 + 1 = 15, and 15÷7=2.1415 \div 7 = 2.14 (to 2 decimal places).

Median: order the values 0,1,1,2,3,3,50, 1, 1, 2, 3, 3, 5; the middle (4th) value is 22.

Mode: the most frequent values are 11 and 33 (each appears twice), so the data is bimodal with modes 11 and 33.

Markers award a mark for the mean, a mark for ordering and reading the median, and a mark for the mode. Forgetting to order before finding the median is the usual error.

WJEC 20214 marksThe table gives the times, tt minutes, of 4040 runners in grouped classes: 0<t100 < t \le 10 (frequency 66), 10<t2010 < t \le 20 (frequency 1818), 20<t3020 < t \le 30 (frequency 1616). Estimate the mean time. (Higher, Unit 2, calculator.)
Show worked answer →

Use the midpoint of each class: 55, 1515 and 2525.

Multiply each midpoint by its frequency: 5×6=305\times 6 = 30, 15×18=27015\times 18 = 270, 25×16=40025\times 16 = 400.

Total =30+270+400=700= 30 + 270 + 400 = 700, and there are 4040 runners, so the estimated mean is 700÷40=17.5700 \div 40 = 17.5 minutes.

Markers give marks for the midpoints, for the products, for the total and for dividing by 4040. Using the class boundaries instead of the midpoints, or dividing by the number of classes, are the common slips.

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