Skip to main content
Northern IrelandMathsSyllabus dot point

How do you calculate with fractions, decimals and percentages and convert freely between them?

Carry out the four operations with fractions, convert between fractions, decimals and percentages, find percentages of amounts, work with percentage change, reverse percentages, compound interest and depreciation.

A CCEA GCSE Mathematics answer on fractions, decimals and percentages, covering the four operations with fractions, conversions between the three forms, percentage of an amount, percentage change, reverse percentages, and compound interest and depreciation.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. The four operations with fractions
  3. Converting between the three forms
  4. Percentages of amounts and percentage change
  5. Reverse percentages, compound interest and depreciation
  6. Why this matters

What this dot point is asking

Fractions, decimals and percentages are three ways of writing the same kind of quantity, and CCEA expects you to calculate with each and switch freely between them. You must add, subtract, multiply and divide fractions, convert between the three forms, find a percentage of an amount, handle percentage increase and decrease, solve reverse-percentage problems, and apply compound interest and depreciation. This material runs from M1 to M8 and appears on both the non-calculator and calculator work, where reverse percentages and compound growth are the higher-value question types.

The four operations with fractions

Multiplying and dividing are the easiest. Multiply two fractions by multiplying numerators and multiplying denominators: 23×45=815\tfrac{2}{3} \times \tfrac{4}{5} = \tfrac{8}{15}. Divide by multiplying by the reciprocal (turn the second fraction upside down): 23÷45=23×54=1012=56\tfrac{2}{3} \div \tfrac{4}{5} = \tfrac{2}{3} \times \tfrac{5}{4} = \tfrac{10}{12} = \tfrac{5}{6}.

Addition and subtraction need a common denominator. Rewrite both fractions over the lowest common multiple of the denominators, then add or subtract the numerators only: 12+13=36+26=56\tfrac{1}{2} + \tfrac{1}{3} = \tfrac{3}{6} + \tfrac{2}{6} = \tfrac{5}{6}. With mixed numbers, either convert to improper fractions first or deal with the whole parts and fractional parts separately.

Converting between the three forms

A percentage is "out of 100", so divide by 100 to make a decimal: 42%=0.4242\% = 0.42. A decimal becomes a fraction using its place value: 0.42=42100=21500.42 = \tfrac{42}{100} = \tfrac{21}{50}. A fraction becomes a decimal by dividing the numerator by the denominator: 38=3÷8=0.375\tfrac{3}{8} = 3 \div 8 = 0.375, and then ×100\times 100 gives 37.5%37.5\%.

These conversions let you choose the easiest form for a calculation and are essential for ordering a mixed list such as 0.60.6, 58\tfrac{5}{8} and 62%62\%.

Percentages of amounts and percentage change

To find a percentage of an amount, convert to a decimal multiplier and multiply: 35%35\% of 240240 is 0.35×240=840.35 \times 240 = 84. For an increase or decrease, adjust the multiplier: a 15%15\% increase multiplies by 1.151.15, and a 20%20\% decrease multiplies by 0.80.8.

Reverse percentages, compound interest and depreciation

A reverse percentage gives you the final amount and asks for the original. The final amount equals a known percentage of the original, so find 1%1\% and scale, or divide by the multiplier. If a price including 20 percent VAT is £60, the original is 60÷1.2=£5060 \div 1.2 = \pounds 50.

Compound interest and depreciation apply the same multiplier repeatedly.

Depreciation works the same way but with a multiplier below 1; a car losing 12 percent of its value each year is multiplied by 0.880.88 per year.

Why this matters

Percentages are the most common real-life maths in the exam, covering prices, interest, growth and decay, while fraction fluency underpins algebra, probability and ratio. CCEA reuses the reverse-percentage and compound-growth structures every year, so recognising which type of problem you face is what separates a secure answer from a lost one.

Exam-style practice questions

Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

CCEA 20183 marksWork out 3423\dfrac{3}{4} - \dfrac{2}{3}, giving your answer as a fraction in its simplest form. (Non-calculator.)
Show worked answer →

Find a common denominator. The lowest common multiple of 44 and 33 is 1212.

Convert both: 34=912\dfrac{3}{4} = \dfrac{9}{12} and 23=812\dfrac{2}{3} = \dfrac{8}{12}.

Subtract the numerators: 912812=112\dfrac{9}{12} - \dfrac{8}{12} = \dfrac{1}{12}.

The mark scheme gives a mark for the common denominator, a mark for the converted fractions and a mark for 112\dfrac{1}{12}. Subtracting numerators and denominators separately to get 11=1\dfrac{1}{1} = 1 is a frequent error and scores nothing.

CCEA 20223 marksA coat costs £63 in a sale after a 30 percent reduction. Work out the original price. (Calculator.)
Show worked answer →

This is a reverse percentage, so do not take 30 percent of £63.

After a 30 percent reduction the sale price is 100%30%=70%100\% - 30\% = 70\% of the original, so £63 represents 70%70\%.

Find 1%1\%: 63÷70=0.963 \div 70 = 0.9. Then the original is 100%100\%: 0.9×100=£900.9 \times 100 = \pounds 90.

A mark is for recognising £63 as 70 percent, a mark for the unitary step and a mark for £90. Check: 30%30\% of £90 is £27, and £90£27=£63\pounds 90 - \pounds 27 = \pounds 63.

Related dot points

Sources & how we know this