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How do we count atoms by weighing them using the mole?

Relative formula mass, the mole as a counting unit, the relationship between moles, mass and relative formula mass, and calculating percentage composition by mass.

A CCEA GCSE Chemistry answer on relative formula mass and the mole, covering how to calculate relative formula mass, the meaning of the mole, the equation linking moles, mass and relative formula mass, and how to find the percentage composition of a compound by mass.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Relative formula mass
  3. The mole
  4. The moles, mass and Mr equation
  5. Percentage composition
  6. Worked example
  7. Examples in context
  8. Why relative masses have no units
  9. Try this

What this dot point is asking

CCEA wants you to calculate relative formula mass, understand the mole as a counting unit, use the equation linking moles, mass and relative formula mass, and find the percentage composition of a compound by mass.

Relative formula mass

To work it out, multiply each element's ArA_r by the number of its atoms in the formula, then add. Remember to apply subscripts and brackets, so calcium hydroxide Ca(OH)2\text{Ca(OH)}_2 is 40+2×(16+1)=7440 + 2 \times (16 + 1) = 74.

The mole

The mole lets chemists count atoms by weighing, because atoms are far too small and numerous to count directly. This is the bridge between the mass we measure on a balance and the number of particles that react.

The moles, mass and Mr equation

A formula triangle with mass on top and moles and MrM_r below helps you rearrange: cover the quantity you want to find. Always state units (mol for moles, g for mass).

Percentage composition

This tells you how much of a compound's mass comes from a given element, which is useful for comparing fertilisers by their nitrogen content, for example.

Worked example

Examples in context

Example 1. Choosing a fertiliser
Farmers compare fertilisers by their percentage of nitrogen by mass, calculated exactly as above. Ammonium nitrate's 35 percent nitrogen makes it a concentrated source, so the percentage composition directly informs a real purchasing decision.
Example 2. Weighing out a reaction
A chemist who needs 0.1 mol of a reactant simply multiplies 0.1 by the relative formula mass to find the mass to weigh out. The mole turns a particle count into a balance reading, which is how every quantitative experiment is set up.
Example 3. Counting particles
Because one mole contains Avogadro's number of particles, two moles of water contain twice as many molecules as one mole, even though they are different substances by mass. This is why the mole, not the gram, is the fair way to compare amounts in a reaction: equal moles mean equal numbers of particles.

Why relative masses have no units

Relative atomic mass and relative formula mass are ratios: they compare the mass of an atom or formula unit with one twelfth of a carbon-12 atom. Because they compare one mass with another, the units cancel and the values are just numbers. This is why you never write a unit after an ArA_r or MrM_r value. The mass in grams of one mole, however, does have units (grams), and equals the relative formula mass numerically. Keeping this distinction clear stops the common error of attaching grams to a relative mass, and it explains why the same number 18 describes both the relative formula mass of water and the mass in grams of one mole of it.

Try this

Q1. Calculate the relative formula mass of carbon dioxide, CO2\text{CO}_2. (Ar: C = 12, O = 16) [1 mark]

  • Cue. 12 plus (2 times 16) equals 44.

Q2. Calculate the number of moles in 36 g of water. (Mr = 18) [1 mark]

  • Cue. 36 divided by 18 equals 2 mol.

Exam-style practice questions

Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

CCEA 20183 marksCalculate the number of moles in 8.0 g of methane, CH4. (Ar: C = 12, H = 1)
Show worked answer →

Markers want the relative formula mass, then the moles.

First find the relative formula mass of CH4\text{CH}_4: carbon 12 plus 4 hydrogens (4 times 1) equals 12+4=1612 + 4 = 16.

Then use moles equals mass divided by relative formula mass:

n=massMr=8.016=0.50 moln = \frac{\text{mass}}{M_r} = \frac{8.0}{16} = 0.50 \text{ mol}

Markers reward the relative formula mass of 16, the correct equation, and the answer 0.50 mol.

CCEA 20213 marksCalculate the percentage by mass of nitrogen in ammonium nitrate, NH4NO3. (Ar: N = 14, H = 1, O = 16)
Show worked answer →

The marks are for the relative formula mass and the percentage.

Relative formula mass of NH4NO3\text{NH}_4\text{NO}_3: two N (2 times 14 equals 28), four H (4 times 1 equals 4), three O (3 times 16 equals 48), total 28+4+48=8028 + 4 + 48 = 80.

The mass due to nitrogen is 28 (the two N atoms). So:

% N=2880×100=35%\% \text{ N} = \frac{28}{80} \times 100 = 35\%

Markers reward relative formula mass 80, nitrogen mass 28, and the answer 35 percent.

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