How do complex numbers extend the real numbers, and how do you add, multiply, divide and represent them geometrically?
Solving quadratic, cubic and quartic equations with complex roots, arithmetic of complex numbers, the Argand diagram, modulus-argument form, de Moivre's theorem and loci.
A focused answer to the AQA A-Level Further Mathematics complex numbers content, covering the arithmetic of complex numbers, the Argand diagram, modulus-argument and exponential form, de Moivre's theorem, complex roots of polynomials, roots of unity and loci.
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What this dot point is asking
AQA wants you to work fluently with complex numbers in Cartesian, modulus-argument and exponential form, plot them on an Argand diagram, use de Moivre's theorem to find powers and roots, solve polynomial equations with complex roots, and sketch loci defined by modulus and argument conditions.
Arithmetic and the conjugate
For the complex conjugate is . Multiplying gives , which is always real and non-negative. To divide, multiply numerator and denominator by the conjugate of the denominator.
The Argand diagram and modulus-argument form
The modulus is and the argument is the angle from the positive real axis, measured in . Always sketch the point first so you pick the correct quadrant for .
De Moivre's theorem
For any integer , . This is the engine for powers, for the th roots of a complex number, and for deriving multiple-angle identities such as .
Roots of polynomials
For a polynomial with real coefficients, complex roots occur in conjugate pairs. If is a root then so is , and their sum and product give a real quadratic factor.
Roots of unity and the nth roots of a complex number
To find all th roots of a complex number , write in modulus-argument form, take the real th root of the modulus, and divide the argument (with all its equivalents) by . The roots are
They all share the modulus and are equally spaced by around a circle, so on an Argand diagram they form the vertices of a regular -gon. The th roots of unity in particular are powers of , and they sum to zero because they are the roots of , whose coefficient is zero. This geometric picture is examined directly: AQA often asks you to mark the roots on a diagram and comment on their symmetry.
Loci on the Argand diagram
Conditions on describe curves, and the marks come from translating the algebra into a labelled sketch. is a circle of radius centred at the point , because is the distance from to . is the perpendicular bisector of the segment joining and , the set of points equidistant from the two. is a half-line (ray) starting at and making angle with the positive real direction, with the start point itself excluded since is undefined. Inequalities such as shade a region (here the closed disc), and intersections of two loci pick out the points or arcs satisfying both conditions at once.
These tools combine on every paper: arithmetic and the conjugate for division, de Moivre for powers and roots, the conjugate-pair fact for polynomials, and the Argand diagram for loci and the geometry of roots of unity.
Exam-style practice questions
Practice questions written in the style of AQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
AQA 20195 marksThe equation has as one root. Find the other two roots, giving your answers in the form .Show worked answer →
Method markers reward: factor out the known real root, then solve the remaining quadratic.
Since is a root, is a factor. Dividing gives .
Solve by the quadratic formula: .
So the other two roots are and , a conjugate pair as expected for a real polynomial.
AO1 method marks: 1 for the factor, 1 for the quadratic factor, 1 for using the discriminant, 2 for both roots correct in form.
AQA 20216 marksUse de Moivre's theorem to express in terms of powers of .Show worked answer →
By de Moivre, .
Expand with the binomial theorem, writing , :
.
Take the real part: .
Replace : .
Collecting, .
Markers reward de Moivre stated, a correct binomial expansion, taking the real part, and the Pythagorean substitution to eliminate .
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Sources & how we know this
- AQA A-level Further Mathematics (7367) specification — AQA (2017)