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What are the fundamental building blocks of matter and the rules that govern their reactions?

Quarks and leptons, antiparticles, baryons and mesons, conservation laws of charge, baryon and lepton number, and beta decay at the quark level.

A focused answer to WJEC A-Level Physics Unit 1 particles and nuclear structure, covering quarks and leptons, antiparticles, the classification of hadrons into baryons and mesons, conservation laws, and beta-minus and beta-plus decay described at the quark level.

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What this dot point is asking

WJEC wants you to describe quarks and leptons and their antiparticles, classify hadrons as baryons or mesons, apply conservation laws to test whether a reaction is allowed, and explain beta-minus and beta-plus decay in terms of quarks. The standard model of particle physics looks intimidating, but at AS level it reduces to a small set of building blocks and three bookkeeping rules that the examiners test again and again.

The answer

Quarks and leptons

The antiparticle of the up quark is the anti-up with charge 23e-\frac{2}{3}e, and the antiparticle of the electron is the positron with charge +e+e. When a particle meets its antiparticle they can annihilate, converting their rest mass into energy (typically gamma photons) in line with E=mc2E = mc^2.

Baryons and mesons

Particles made of quarks are hadrons. A baryon is made of three quarks: a proton is uud (charge +e+e) and a neutron is udd (charge 00). A meson is a quark and an antiquark, for example a pion. Because mesons contain one quark and one antiquark, their baryon number is zero, which matters when you apply the conservation rules below.

Conservation laws

Baryon number is +1+1 for a baryon, 1-1 for an antibaryon and 00 for a meson or lepton. Lepton number is +1+1 for a lepton, 1-1 for an antilepton, and 00 for a hadron. Checking a proposed reaction is then a matter of adding these numbers up on each side, as in the worked example below.

Beta decay at the quark level

In beta-minus decay, a down quark changes into an up quark, so a neutron (udd) becomes a proton (uud), emitting an electron and an electron-antineutrino. In beta-plus decay, an up quark changes into a down quark, so a proton becomes a neutron, emitting a positron and an electron-neutrino. Both are mediated by the weak interaction.

Examples in context

Example 1. Carbon-14 dating. A carbon-14 nucleus is unstable because it has too many neutrons. One neutron undergoes beta-minus decay, np+e+νˉen \rightarrow p + e^- + \bar{\nu}_e, turning the nucleus into nitrogen-14. At the quark level a single down quark inside that neutron flips to an up quark. The steady rate of this decay is what makes radiocarbon dating possible.

Example 2. The PET scanner. Positron emission tomography uses a beta-plus emitter such as fluorine-18. A proton becomes a neutron, pn+e++νep \rightarrow n + e^+ + \nu_e, emitting a positron. The positron travels a few millimetres, meets an electron, and they annihilate into two gamma photons that fly off in opposite directions. Detecting these back-to-back photons lets the scanner reconstruct where the tracer is concentrated.

Try this

Q1. Write the quark composition of a proton and a neutron. [2 marks]

  • Cue. Proton uud; neutron udd.

Q2. Explain, in terms of quarks, what happens in beta-minus decay. [2 marks]

  • Cue. A down quark changes to an up quark, so a neutron becomes a proton, emitting an electron and an antineutrino.

Exam-style practice questions

Practice questions written in the style of WJEC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

WJEC 20204 marksThe following proposed reaction is written: p+en+νep + e^- \rightarrow n + \nu_e. By considering charge, baryon number and lepton number, deduce whether this reaction is allowed.
Show worked answer →

Test each conserved quantity on both sides.

Charge: left side is (+1)+(1)=0(+1) + (-1) = 0; right side is 0+0=00 + 0 = 0. Charge is conserved.

Baryon number: the proton and neutron are baryons with B=+1B = +1; the electron and neutrino are leptons with B=0B = 0. Left =+1= +1, right =+1= +1. Baryon number is conserved.

Lepton number: the electron has L=+1L = +1 and the electron-neutrino has L=+1L = +1; the proton and neutron have L=0L = 0. Left =+1= +1, right =+1= +1. Lepton number is conserved.

All three quantities balance, so the reaction is allowed (this is electron capture). Markers reward a clear table or list checking each quantity and a conclusion tied to the results.

WJEC 20183 marksState the quark composition of a proton and show that its charge is +e+e.
Show worked answer →

A proton is a baryon made of two up quarks and one down quark (uud).

The up quark has charge +23e+\tfrac{2}{3}e and the down quark has charge 13e-\tfrac{1}{3}e.

Total charge: (+23e)+(+23e)+(13e)=+43e13e=+e\left(+\tfrac{2}{3}e\right) + \left(+\tfrac{2}{3}e\right) + \left(-\tfrac{1}{3}e\right) = +\tfrac{4}{3}e - \tfrac{1}{3}e = +e.

The three fractional charges add to exactly +e+e, the observed proton charge. Markers reward the uud composition and the explicit sum of fractional charges.

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