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What are atoms made of and how are their electrons arranged?

Sub-atomic particles, isotopes, mass spectrometry and relative atomic mass, electron configurations in s, p and d sub-shells, and successive ionisation energies.

A focused answer to WJEC A-Level Chemistry Unit 1, covering sub-atomic particles, isotopes, the time-of-flight mass spectrometer, relative atomic mass, electron configurations in s, p and d sub-shells, and the evidence from successive ionisation energies.

Generated by Claude Opus 4.812 min answer

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What this dot point is asking

WJEC wants you to describe the three sub-atomic particles and isotopes, explain how a time-of-flight mass spectrometer works, calculate relative atomic mass from abundance data, write electron configurations using ss, pp and dd sub-shells, and interpret successive ionisation energy patterns as evidence for shell structure.

The answer

Sub-atomic particles and isotopes

An atom has a dense central nucleus of protons (relative charge +1+1, relative mass 11) and neutrons (charge 00, mass 11), surrounded by electrons (charge 1-1, mass 1/18361/1836). The atomic number ZZ is the number of protons; the mass number AA is protons plus neutrons.

For example, chlorine exists as Cl35\text{Cl}^{35} and Cl37\text{Cl}^{37}, which react identically but have different masses.

The mass spectrometer and relative atomic mass

A time-of-flight (TOF) mass spectrometer measures isotopic masses and abundances in four stages: ionisation (the sample is vaporised and ionised, often by electron impact, forming X+\text{X}^+), acceleration (ions are accelerated by an electric field to constant kinetic energy), drift (ions travel a field-free region, lighter ions arriving first), and detection (each ion gains an electron at the detector, generating a current proportional to abundance).

Electron configurations

Electrons occupy sub-shells in order of increasing energy: 1s,2s,2p,3s,3p,4s,3d,4p1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p. The 4s4s sub-shell fills before 3d3d because it is slightly lower in energy.

Successive ionisation energies

The first ionisation energy is the energy to remove one mole of electrons from one mole of gaseous atoms: X(g)X(g)++e\text{X}_{(g)} \rightarrow \text{X}^+_{(g)} + e^-. Successive ionisation energies always rise because each electron is pulled from an increasingly positive ion. A large jump appears when the next electron comes from a shell closer to the nucleus, which reveals how many electrons are in each shell, and so which group the element is in.

Examples in context

Mass spectrometry in dating and forensics. TOF mass spectrometers identify trace isotopes in archaeology (carbon dating) and detect doping agents in sport, applying exactly the abundance-to-mass-spectrum logic above. Ionisation energy and the periodic table. The pattern of successive ionisation energies for sodium (one easy electron, then a huge jump) was historical evidence that placed it in Group 1, confirming the shell model that underpins the modern periodic table.

Try this

Q1. Write the full electron configuration of an iron atom. [1 mark]

  • Cue. 1s22s22p63s23p63d64s21s^2 2s^2 2p^6 3s^2 3p^6 3d^6 4s^2.

Q2. A sample of boron is 20.0 percent boron-10 and 80.0 percent boron-11. Calculate its relative atomic mass. [2 marks]

  • Cue. Ar=(0.200×10)+(0.800×11)=2.0+8.8=10.8A_r = (0.200 \times 10) + (0.800 \times 11) = 2.0 + 8.8 = 10.8.

Q3. Outline the four stages by which a time-of-flight mass spectrometer separates ions. [4 marks]

  • Cue. Ionisation, acceleration to constant kinetic energy, drift through a field-free region (lighter ions faster), detection generating a current proportional to abundance.

Exam-style practice questions

Practice questions written in the style of WJEC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

WJEC 20193 marksA sample of magnesium contains the isotopes magnesium-24, magnesium-25 and magnesium-26 with relative abundances of 79.0 percent, 10.0 percent and 11.0 percent respectively. Calculate the relative atomic mass of this sample of magnesium, giving your answer to one decimal place.
Show worked answer →

Relative atomic mass is the weighted mean of the isotopic masses, where each mass is multiplied by its fractional abundance and the products are summed.

Set up the weighted mean:
Ar=(0.790×24)+(0.100×25)+(0.110×26)A_r = (0.790 \times 24) + (0.100 \times 25) + (0.110 \times 26).

Evaluate each term: 0.790×24=18.960.790 \times 24 = 18.96, 0.100×25=2.500.100 \times 25 = 2.50, 0.110×26=2.860.110 \times 26 = 2.86.

Sum: Ar=18.96+2.50+2.86=24.32=24.3A_r = 18.96 + 2.50 + 2.86 = 24.32 = 24.3 to one decimal place.

Markers reward the weighted-mean method (not a simple average), correct arithmetic, and rounding to the stated precision.

WJEC 20212 marksExplain why there is a large increase between the second and third successive ionisation energies of magnesium.
Show worked answer →

The first two electrons are removed from the outer 3s3s sub-shell. The third electron must be removed from the 2p2p sub-shell, which is in a shell closer to the nucleus.

This inner electron experiences a greater effective nuclear attraction and has less shielding, so much more energy is needed to remove it, producing the large jump.

Markers reward identifying that the third electron comes from a principal shell nearer the nucleus and linking this to stronger nuclear attraction and reduced shielding.

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