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How are atoms held together and what shapes do molecules take?

Ionic, covalent, dative and metallic bonding, electronegativity and polarity, intermolecular forces, and the shapes of simple molecules from electron-pair repulsion.

A focused answer to WJEC A-Level Chemistry Unit 1, covering ionic, covalent, dative and metallic bonding, electronegativity and bond polarity, the three intermolecular forces, and predicting molecular shapes from electron-pair repulsion theory.

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  1. What this dot point is asking
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  3. Examples in context
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What this dot point is asking

WJEC wants you to describe the four bonding types, explain electronegativity and polarity, identify the intermolecular forces between molecules, and predict molecular shapes and bond angles using electron-pair repulsion theory.

The answer

The bonding types

Electronegativity and polarity

Electronegativity is the power of an atom to attract the bonding electrons in a covalent bond. It increases across a period and up a group, with fluorine the most electronegative. When two bonded atoms differ in electronegativity, the bond is polar, carrying partial charges δ+\delta+ and δ\delta-.

Intermolecular forces

Three forces act between molecules, in increasing strength: London (dispersion) forces from instantaneous dipoles, present in all molecules and stronger with more electrons; permanent dipole-dipole forces between polar molecules; and hydrogen bonds, the strongest, between an H\text{H} attached to N\text{N}, O\text{O} or F\text{F} and a lone pair on an adjacent N\text{N}, O\text{O} or F\text{F}.

Predicting molecular shapes

Electron-pair repulsion theory states that electron pairs around a central atom repel and arrange themselves as far apart as possible. Lone pairs repel more strongly than bonding pairs (lone-lone > lone-bond > bond-bond).

Common shapes: 2 pairs linear 180180 degrees; 3 pairs trigonal planar 120120 degrees; 4 pairs tetrahedral 109.5109.5 degrees; 5 pairs trigonal bipyramidal; 6 pairs octahedral 9090 degrees.

Examples in context

Hydrogen bonding and ice. Water expands on freezing because hydrogen bonds hold molecules in an open hexagonal lattice, making ice less dense than liquid water, which is why ice floats and lakes freeze from the top down. Dative bonds in catalysis. Transition-metal complexes form dative bonds from ligand lone pairs into empty metal dd orbitals, the basis of much of inorganic and biological chemistry covered later in Unit 3.

Try this

Q1. State the shape and bond angle of a methane molecule. [1 mark]

  • Cue. Tetrahedral, 109.5109.5 degrees.

Q2. Name the strongest intermolecular force present in liquid hydrogen fluoride. [1 mark]

  • Cue. Hydrogen bonding.

Q3. Explain why carbon dioxide is non-polar but sulfur dioxide is polar. [2 marks]

  • Cue. CO2\text{CO}_2 is linear so bond dipoles cancel; SO2\text{SO}_2 is bent (a lone pair on sulfur) so dipoles do not cancel.

Exam-style practice questions

Practice questions written in the style of WJEC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

WJEC 20184 marksState the shape and bond angle of a molecule of ammonia, and explain why this shape differs from that of methane.
Show worked answer →

Ammonia (NH3\text{NH}_3) is pyramidal with a bond angle of about 107107 degrees. Methane (CH4\text{CH}_4) is tetrahedral with a bond angle of 109.5109.5 degrees.

Both nitrogen and carbon have four electron pairs around the central atom. In methane all four are bonding pairs, giving a regular tetrahedron at 109.5109.5 degrees.

In ammonia, one of the four pairs is a lone pair. A lone pair repels more strongly than a bonding pair, so it compresses the three bonding pairs closer together, reducing the angle to about 107107 degrees and giving a pyramidal shape.

Markers reward both shapes, both angles, and the lone-pair repulsion argument.

WJEC 20203 marksExplain why the boiling point of water is much higher than that of hydrogen sulfide, even though both are Group 6 hydrides.
Show worked answer →

Water molecules form hydrogen bonds because oxygen is highly electronegative and bears a lone pair, so a hydrogen bonded to oxygen is strongly attracted to a lone pair on a neighbouring oxygen.

Hydrogen sulfide cannot hydrogen bond effectively because sulfur is much less electronegative, so its strongest intermolecular force is the weaker permanent dipole and London force.

More energy is needed to overcome the hydrogen bonds in water, so its boiling point is far higher.

Markers reward identifying hydrogen bonding in water, its absence in H2S\text{H}_2\text{S}, and linking stronger forces to higher boiling point.

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