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How do you work out percentage change, reverse percentages and compound interest using a multiplier?

Calculate percentage increase and decrease, find the percentage change between two values, solve reverse percentage problems, and apply repeated percentage change including compound interest using multipliers.

A focused answer to the OCR GCSE Mathematics ratio content on percentage change and interest, covering percentage increase and decrease, percentage change between values, reverse percentages, and compound interest with multipliers.

Generated by Claude Opus 4.812 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Percentage increase and decrease with multipliers
  3. Percentage change between two values
  4. Reverse percentages
  5. Compound interest and repeated change
  6. Why this matters

What this dot point is asking

OCR references R9 and R16 cover percentage change and interest: percentage increase and decrease, the percentage change between two values, reverse percentages, and repeated percentage change including compound interest. The unifying tool is the multiplier, a single decimal that performs a percentage change in one step. This content appears on every tier and the calculator paper especially, and reverse percentages and compound interest are reliably high-value, frequently misanswered questions.

Percentage increase and decrease with multipliers

The multiplier method does any percentage change in one multiplication.

So increasing £250250 by 12%12\% gives 250×1.12=250 \times 1.12 = £280280, and decreasing 4040 kg by 35%35\% gives 40×0.65=2640 \times 0.65 = 26 kg. The multiplier is faster and less error-prone than finding the percentage and then adding or subtracting, and it is essential for the repeated changes that follow.

Percentage change between two values

A "find the percentage change" question compares a new value with the original.

If a share bought for £4040 is sold for £4646, the change is £66, so the percentage profit is 640×100=15%\dfrac{6}{40} \times 100 = 15\%. Dividing by the wrong value (the new price) is the classic mistake, so always anchor the calculation to the original.

Reverse percentages

A reverse percentage works backwards from the value after a change.

The decisive idea is that the final amount is not 100%100\%; it is 100%100\% plus or minus the change. Dividing by the multiplier recovers the original. Taking the percentage of the final amount and adjusting it is wrong because the percentage was applied to the original, not the final, value.

Compound interest and repeated change

Compound interest applies the same multiplier every period.

So £50005000 at 4%4\% for 33 years becomes 5000×1.043=5000×1.124864=5000 \times 1.04^3 = 5000 \times 1.124864 = £5624.325624.32. Compound interest differs from simple interest, where the same fixed amount is added each year; compound interest grows because each year's interest itself earns interest. The compound interest formula is given on the OCR Higher formulae sheet, but you must know how to set up the multiplier and the power.

Why this matters

Percentages model prices, taxes, savings, depreciation and population change, so OCR sets these questions in authentic financial contexts that test AO3. The multiplier is the single most useful technique, turning awkward chains of increases and decreases into one calculation, and reverse percentages are exactly the skill needed to "work back" to an original price, a common real-world task.

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20193 marksA jacket costs £7272 after a 10%10\% reduction. Work out the original price of the jacket. (Higher, Paper 4, calculator.)
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This is a reverse percentage. After a 10%10\% reduction, £7272 represents 90%90\% of the original price.

So 90%=90\% = £7272, meaning 1%=72÷90=0.81\% = 72 \div 90 = 0.8, and 100%=0.8×100=100\% = 0.8 \times 100 = £8080.

Alternatively, divide by the multiplier: 72÷0.9=8072 \div 0.9 = 80.

Markers award a mark for identifying that £7272 is 90%90\% of the original, a mark for the method, and a mark for £8080. The standard error is taking 10%10\% of £7272 and adding it, which gives £79.2079.20, not the true original.

OCR 20214 marks£20002000 is invested at 3%3\% compound interest per year. Find the value of the investment after 44 years, to the nearest penny. (Higher, Paper 4, calculator.)
Show worked answer →

Compound interest multiplies by the same factor each year. A 3%3\% increase has multiplier 1.031.03.

After 44 years, the value is 2000×1.0342000 \times 1.03^4.

1.034=1.125508811.03^4 = 1.12550881, so 2000×1.12550881=2251.01762000 \times 1.12550881 = 2251.0176\ldots

To the nearest penny, the investment is worth £2251.022251.02.

Markers give a mark for the multiplier 1.031.03, a mark for raising it to the power 44, a mark for the calculation, and a mark for £2251.022251.02. Using simple interest (4×3%=12%4 \times 3\% = 12\%, giving £22402240) is the usual error.

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