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How do you use the probability scale, find probabilities of single and combined events, and use sample space diagrams?

Use the probability scale from 0 to 1; calculate probabilities of single events from equally likely outcomes; use the fact that probabilities sum to 1; and list combined outcomes using sample space diagrams.

A focused answer to the OCR GCSE Mathematics probability content on the basics, covering the probability scale, single-event probability from equally likely outcomes, the sum of probabilities, and sample space diagrams for combined events.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The probability scale
  3. Single events from equally likely outcomes
  4. Probabilities sum to 1
  5. Sample space diagrams
  6. Why the basics matter

What this dot point is asking

OCR references P1 to P7 cover the foundations of probability: the 00-to-11 scale, calculating single-event probabilities from equally likely outcomes, the fact that all probabilities sum to 11, and listing combined outcomes with sample space diagrams. These ideas are the basis of every probability question, and they appear on every tier, often on the non-calculator paper where fractions must be handled by hand.

The probability scale

Every probability is a number between 00 and 11.

So an event with probability 14\tfrac{1}{4} is unlikely but possible, and an event with probability 0.90.9 is very likely. Words such as "impossible", "unlikely", "even chance", "likely" and "certain" map onto positions on this scale, and a question may ask you to place an event's probability with a cross on a 00-to-11 line.

Single events from equally likely outcomes

When outcomes are equally likely, probability is a simple ratio.

So the probability of rolling an even number on a fair die is 36=12\dfrac{3}{6} = \dfrac{1}{2} (three even faces out of six). For a bag of counters, the total is all the counters and the favourable count is those of the chosen colour. The assumption of "fair" or "at random" is what makes the outcomes equally likely, which the formula requires.

Probabilities sum to 1

The probabilities of all outcomes of an event add to 11.

Because something must happen, the probabilities of all the mutually exclusive outcomes total 11. This gives the useful complement rule: P(not A)=1P(A)P(\text{not } A) = 1 - P(A). So if the probability of rain is 0.30.3, the probability of no rain is 0.70.7. When a question lists probabilities for several outcomes and leaves one blank, the missing probability is 11 minus the sum of the rest. This is a frequent two-step exam question.

Sample space diagrams

A sample space diagram lists every combined outcome.

For two events, a two-way grid shows all the outcomes. Rolling two dice gives a 6×66 \times 6 grid of 3636 equally likely totals; flipping two coins gives four outcomes (HH, HT, TH, TT). Once every outcome is listed, counting the favourable ones and dividing by the total gives the probability. The diagram prevents missed or double-counted outcomes, which is why OCR rewards drawing it. Reading the wording precisely ("greater than" excludes the boundary, "at least" includes it) decides exactly which cells to count.

Why the basics matter

These foundations support tree diagrams, Venn diagrams and relative frequency, and they connect to the expected-outcomes idea used in modelling. OCR sets them in everyday contexts (dice, cards, spinners, bags) and rewards exact fractions, correct use of the complement rule, and complete sample spaces. Precision with the wording of an event is an AO2 skill that often separates full marks from partial ones.

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20183 marksA bag contains 55 red, 33 blue and 22 green counters. One counter is taken at random. Work out the probability that it is (a) red, (b) not blue. (Foundation, Paper 2, non-calculator.)
Show worked answer →

There are 5+3+2=105 + 3 + 2 = 10 counters in total.

(a) Probability red =510=12= \dfrac{5}{10} = \dfrac{1}{2}.

(b) Not blue means red or green: 5+210=710\dfrac{5 + 2}{10} = \dfrac{7}{10}. Alternatively, 1310=7101 - \dfrac{3}{10} = \dfrac{7}{10}.

Markers award a mark for the total of 1010, a mark for 12\dfrac{1}{2}, and a mark for 710\dfrac{7}{10}. Using the "not blue = 11 - P(blue)" shortcut is a neat method that OCR credits.

OCR 20214 marksTwo fair dice are rolled and their scores are added. Use a sample space diagram to find the probability that the total is (a) 77, (b) greater than 99. (Higher, Paper 4, calculator.)
Show worked answer →

A sample space diagram lists all 6×6=366 \times 6 = 36 equally likely totals.

(a) The total 77 occurs for (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)(1,6), (2,5), (3,4), (4,3), (5,2), (6,1), which is 66 outcomes, so 636=16\dfrac{6}{36} = \dfrac{1}{6}.

(b) Greater than 99 means 1010, 1111 or 1212: that is 3+2+1=63 + 2 + 1 = 6 outcomes, so 636=16\dfrac{6}{36} = \dfrac{1}{6}.

Markers give a mark for 3636 outcomes, a mark for counting the total-77 cases, a mark for 16\dfrac{1}{6}, and a mark for part (b). Counting "99 or greater" instead of "greater than 99" is the standard error.

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