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How do you use relative frequency to estimate probability and calculate expected outcomes?

Use relative frequency (experimental probability) to estimate probabilities from data, understand how more trials improve the estimate, and calculate expected numbers of outcomes.

A focused answer to the Eduqas GCSE Mathematics probability content on relative frequency and expected outcomes, covering experimental probability, how more trials improve the estimate, and calculating expected numbers of outcomes.

Generated by Claude Opus 4.810 min answer

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  1. What this dot point is asking
  2. Relative frequency
  3. Why more trials give a better estimate
  4. Expected outcomes
  5. Why this matters

What this dot point is asking

The Eduqas probability content asks you to use relative frequency (experimental probability) to estimate a probability from collected data, to understand why a larger number of trials gives a better estimate, and to calculate expected numbers of outcomes. Where theoretical probability comes from counting equally likely outcomes, relative frequency comes from an experiment, which is essential when a spinner or dice is biased. It appears at both tiers, and the "how many would you expect" calculation is a dependable question, with the explanation of why more trials help being a common AO2 reasoning task.

Relative frequency

When outcomes are not equally likely, or you do not know the theoretical probability, you estimate it from an experiment.

So if a drawing pin lands "point up" 6363 times in 100100 drops, the relative frequency of "point up" is 63100=0.63\dfrac{63}{100} = 0.63. This is an estimate of the true probability, which cannot be found by counting equally likely outcomes because the pin is not symmetrical.

Why more trials give a better estimate

The reliability of a relative-frequency estimate grows with the number of trials.

This is why, when comparing a spinner result over 2020 spins with one over 500500 spins, the larger experiment gives the better estimate. A good exam explanation must link the larger number of trials to the smaller effect of chance variation, not just assert that "more is better".

Expected outcomes

Once you have a probability, you can predict how many times an event should occur in a given number of trials.

The expected number is a prediction, not a certainty: you would expect about 5050 sixes, but any particular set of 300300 rolls might give a few more or fewer. The probability used can be theoretical (for a fair die) or a relative frequency (for a biased one).

Why this matters

Relative frequency is how probability is measured in the real world, from quality control to medical trials, where theoretical probabilities are unknown and must be estimated from data. Expected outcomes connect probability to prediction, which is the practical payoff of the whole topic. Because Eduqas asks you both to calculate and to explain (why more trials help, what an expected value means), clear reasoning alongside the arithmetic is essential for full marks.

Exam-style practice questions

Practice questions written in the style of WJEC Eduqas exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Eduqas 20183 marksA spinner is spun 200 times and lands on blue 50 times. Estimate the probability of blue, and work out how many blues you would expect in 360 spins. (Foundation, Component 2, calculator.)
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The relative frequency estimates the probability: 50200=0.25\dfrac{50}{200} = 0.25.

Expected outcomes are probability times the number of trials: 0.25×360=900.25 \times 360 = 90.

So you would expect about 90 blues in 360 spins.

Markers award a mark for the relative frequency 0.25, a mark for the method, and a mark for the expected 90. Using the raw count 50 as the probability, or forgetting to multiply by the new number of spins, are the common errors.

Eduqas 20224 marksA biased dice is rolled and the relative frequency of a six settles near 0.3 after many rolls. Explain why a larger number of rolls gives a better estimate, and find the expected number of sixes in 500 rolls. (Higher, Component 2, calculator.)
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As the number of trials increases, the relative frequency settles closer to the true probability, because random variation has a smaller effect over many rolls (the law of large numbers).

Expected sixes: 0.3×500=1500.3 \times 500 = 150.

Markers give marks for explaining that more trials reduce random variation and improve the estimate, and for the expected value 150. A vague explanation that does not link more trials to a more stable relative frequency loses the reasoning mark.

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