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How do you estimate probability from experiments using relative frequency, and predict expected numbers of outcomes?

Estimating probability from experimental data using relative frequency, comparing experimental and theoretical probability, and calculating the expected number of outcomes from a probability.

A focused answer to the Edexcel GCSE Mathematics probability content on relative frequency and expected outcomes, covering estimating probability from experiments, comparing experimental and theoretical probability, and predicting the expected number of outcomes.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Relative frequency
  3. Experimental versus theoretical probability
  4. Expected number of outcomes
  5. Why more trials matter
  6. Try this

What this dot point is asking

Edexcel expects you to estimate probability from experimental data using relative frequency, to compare experimental results with theoretical probability to judge fairness, and to calculate the expected number of times an outcome should occur. This is where probability meets data: theory predicts, experiments test, and the two are compared.

Relative frequency

When outcomes are not equally likely, or when we cannot calculate a theoretical probability, we estimate it from an experiment.

So if a drawing pin lands "point up" 7272 times in 120120 drops, the relative frequency is 72120=0.6\dfrac{72}{120} = 0.6, our best estimate of the probability. A single small experiment gives a rough estimate; thousands of trials give a much better one, because relative frequency settles towards the true probability over many trials.

Experimental versus theoretical probability

Theoretical probability comes from the structure of the situation (a fair die gives 16\tfrac{1}{6} for each face). Experimental probability comes from data. Comparing them is how we test fairness.

If a coin is flipped 10001000 times and lands heads 720720 times, the relative frequency 0.720.72 is far from the theoretical 0.50.5, suggesting the coin is biased. Small differences are expected from chance, so the judgement should be cautious: a relative frequency close to the theoretical value supports fairness, while a large gap over many trials suggests bias.

Expected number of outcomes

The expected number predicts how many times an outcome should occur, given its probability.

The expected value is also used the other way round: given an expected count and the number of trials, you can find the probability by dividing.

Why more trials matter

A key idea Edexcel tests is that relative frequency becomes a better estimate as the number of trials grows. With only ten spins of a spinner, a relative frequency of 0.30.3 could easily be out by a lot; with ten thousand spins, a relative frequency of 0.30.3 is strong evidence that the true probability is close to 0.30.3. This is the "law of large numbers" in plain terms, and it is why an experiment to test fairness should use many trials. A question may give two experiments of different sizes and ask which estimate to trust; the larger experiment is the more reliable.

Try this

Q1. A coin is flipped 8080 times and lands heads 3636 times. Work out the relative frequency of heads. [2 marks]

  • Cue. 3680=0.45\dfrac{36}{80} = 0.45.

Q2. The probability a train is late is 0.10.1. Over 250250 journeys, how many are expected to be late? [2 marks]

  • Cue. 0.1×250=250.1 \times 250 = 25 journeys.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20182 marksA spinner is spun 200200 times and lands on red 6666 times. Work out the relative frequency of landing on red, and use it to estimate how many reds you would expect in 500500 spins. (Paper 2, calculator.)
Show worked answer →

Relative frequency is the number of successes over the number of trials.

66200=0.33\dfrac{66}{200} = 0.33.

Expected reds in 500500 spins =0.33×500=165= 0.33 \times 500 = 165.

Markers award a mark for the relative frequency 0.330.33 and a mark for the expected value 165165. Forgetting to multiply by the new number of trials, or using 200200 again, are the usual errors.

Edexcel 20213 marksA dice is rolled 300300 times. The relative frequency of a six is recorded as 0.220.22. Explain whether the dice is likely to be fair, and calculate the expected number of sixes for a fair dice. (Paper 2, calculator.)
Show worked answer →

For a fair dice, P(six)=160.167P(\text{six}) = \dfrac{1}{6} \approx 0.167.

The experimental relative frequency 0.220.22 is noticeably higher than 0.1670.167, so the dice may be biased towards six.

Expected sixes for a fair dice =16×300=50= \dfrac{1}{6} \times 300 = 50.

Markers award a mark for the theoretical probability, a mark for the reasoned comparison, and a mark for the expected 5050. Saying it is "definitely biased" overstates the case; the language should be tentative.

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