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How do you find the mean, median, mode and range, including from frequency tables and grouped data?

The mean, median, mode and range; finding averages from frequency tables and from grouped data using the midpoint and an estimated mean; and comparing distributions using an average and the range.

A focused answer to the Edexcel GCSE Mathematics statistics content on averages and spread, covering the mean, median, mode and range, finding averages from frequency tables and grouped data, and comparing distributions.

Generated by Claude Opus 4.810 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The four measures
  3. Averages from a frequency table
  4. Estimating the mean of grouped data
  5. Comparing distributions
  6. Choosing the right average
  7. Try this

What this dot point is asking

Edexcel expects you to find the four key measures (mean, median, mode and range), to calculate them from frequency tables, to estimate the mean of grouped data using midpoints, and to compare two distributions using an average and the range. Knowing which average suits which situation, and handling grouped data carefully, are the main skills.

The four measures

Each measure summarises data differently, and each has strengths.

The mean uses all the data but is affected by extreme values (outliers). The median is resistant to outliers, which is why it is preferred for skewed data such as house prices or incomes. The mode is the only average for qualitative data (the most popular colour, say). The range measures spread but, like the mean, is sensitive to a single extreme value.

Averages from a frequency table

When data is in a frequency table, multiply each value by its frequency to find the mean efficiently.

For a table of shoe sizes with frequencies, the mean shoe size is the sum of (size ×\times frequency) divided by the total number of people, not the average of the sizes alone.

Estimating the mean of grouped data

Grouped data hides the exact values, so the mean can only be estimated using the midpoint of each class as a stand-in.

For grouped data you also identify the modal class (the class with the highest frequency) and the class containing the median, rather than a single value.

Comparing distributions

To compare two sets of data, use one measure of average (to compare typical values) and one measure of spread (to compare consistency). For example, "Team A has a higher mean score, so they tend to score more, but Team B has a smaller range, so they are more consistent." Edexcel rewards a comparison in context, not just two numbers.

Choosing the right average

Part of the skill is knowing which average to use. The mean is best when the data is fairly symmetric with no extreme values, because it uses every value. The median is better for skewed data or data with outliers, such as salaries, where a few very large values would drag the mean up and misrepresent the typical case. The mode is the right choice for categorical data, where "average" can only mean "most common", such as the most popular shoe size a shop should stock. A question may give a context and ask which average is most appropriate and why, so be ready to justify the choice, not just calculate it.

Try this

Q1. Find the median of 7,3,9,4,7,2,87, 3, 9, 4, 7, 2, 8. [2 marks]

  • Cue. Order them: 2,3,4,7,7,8,92, 3, 4, 7, 7, 8, 9. The middle (4th) value is 77.

Q2. Five numbers have a mean of 1212. Four of them are 10,11,13,1510, 11, 13, 15. Find the fifth. [2 marks]

  • Cue. The total must be 5×12=605 \times 12 = 60; the four given sum to 4949, so the fifth is 1111.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20193 marksThe numbers of goals scored in 1010 matches are: 1,0,2,3,1,2,0,4,1,21, 0, 2, 3, 1, 2, 0, 4, 1, 2. Work out the mean, median and mode. (Paper 1, non-calculator.)
Show worked answer →

Mean: add all values and divide by how many. Sum =1+0+2+3+1+2+0+4+1+2=16= 1+0+2+3+1+2+0+4+1+2 = 16, so mean =1610=1.6= \dfrac{16}{10} = 1.6.

Median: order them (0,0,1,1,1,2,2,2,3,40, 0, 1, 1, 1, 2, 2, 2, 3, 4) and take the middle. With 1010 values, average the 55th and 66th: 1+22=1.5\dfrac{1 + 2}{2} = 1.5.

Mode: the most common value is 11 (appears three times).

Markers award a mark for each correct average. Forgetting to order the data before finding the median is the usual error.

Edexcel 20214 marksThe grouped table shows the times tt (minutes) for 4040 runners. Use the midpoints to estimate the mean time. The groups are 0<t100 < t \le 10 (frequency 66), 10<t2010 < t \le 20 (frequency 1818), 20<t3020 < t \le 30 (frequency 1212), 30<t4030 < t \le 40 (frequency 44). (Paper 2, calculator.)
Show worked answer →

Use the midpoint of each group as a representative value, multiply by the frequency, sum and divide by the total frequency.

Midpoints: 5,15,25,355, 15, 25, 35. Products: 5×6=305 \times 6 = 30, 15×18=27015 \times 18 = 270, 25×12=30025 \times 12 = 300, 35×4=14035 \times 4 = 140.

Sum of products =30+270+300+140=740= 30 + 270 + 300 + 140 = 740. Total frequency =40= 40.

Estimated mean =74040=18.5= \dfrac{740}{40} = 18.5 minutes.

Markers award marks for the midpoints, the f×xf \times x products, the totals, and the final mean. Using the group boundaries instead of midpoints is the common error.

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