Skip to main content
EnglandMathsSyllabus dot point

How do you use the probability scale, calculate probabilities of single and combined events, and use sample spaces?

The probability scale and notation, probabilities of single events, mutually exclusive and exhaustive events, the AND and OR rules for combined events, and listing outcomes using sample space diagrams.

A focused answer to the Edexcel GCSE Mathematics probability content on the basics, covering the probability scale and notation, single-event probabilities, mutually exclusive and exhaustive events, the AND and OR rules, and sample space diagrams.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. The probability scale and notation
  3. Mutually exclusive and exhaustive events
  4. The AND and OR rules
  5. Sample space diagrams
  6. Try this

What this dot point is asking

Edexcel expects you to use the probability scale and notation, find probabilities of single events, understand mutually exclusive and exhaustive events, combine events with the AND and OR rules, and list outcomes systematically using sample space diagrams. Probability rewards careful, organised listing and a clear sense of when to add and when to multiply.

The probability scale and notation

Every probability is a number between 00 and 11, written as a fraction, decimal or percentage.

So rolling a 44 on a fair die has probability 16\tfrac{1}{6}, and rolling an even number has probability 36=12\tfrac{3}{6} = \tfrac{1}{2}. The complement rule is essential: the probability that an event does not happen is 11 minus the probability that it does, so P(not a 4)=116=56P(\text{not a } 4) = 1 - \tfrac{1}{6} = \tfrac{5}{6}.

Mutually exclusive and exhaustive events

Two events are mutually exclusive if they cannot both happen at once, such as rolling a 22 and rolling a 55 on one die. A set of events is exhaustive if together they cover every possibility.

This is why, in the exam question above, the three counter colours (the only possibilities) have probabilities summing to 11.

The AND and OR rules

The two combining rules are the heart of probability, and choosing the right one is the key skill.

So the probability of rolling a 11 OR a 22 is 16+16=13\tfrac{1}{6} + \tfrac{1}{6} = \tfrac{1}{3}, while the probability of rolling a 66 on one die AND a head on a coin is 16×12=112\tfrac{1}{6} \times \tfrac{1}{2} = \tfrac{1}{12}. A simple way to remember which is which: "or" widens the chance, so probabilities get bigger (you add), while "and" narrows it to a more specific outcome, so probabilities get smaller (you multiply two numbers below 11).

Sample space diagrams

A sample space lists every possible outcome, making it easy to count favourable ones. For two dice, a 6×66 \times 6 grid shows all 3636 equally likely outcomes, and you count those meeting the condition.

Try this

Q1. A fair die is rolled. Work out the probability of scoring a prime number. [2 marks]

  • Cue. The primes on a die are 2,3,52, 3, 5, so 36=12\dfrac{3}{6} = \dfrac{1}{2}.

Q2. The probability that a light is green is 0.70.7. Work out the probability that it is not green. [1 mark]

  • Cue. 10.7=0.31 - 0.7 = 0.3.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20182 marksA bag contains red, blue and green counters. The probability of picking a red counter is 0.350.35 and the probability of picking a blue counter is 0.40.4. Work out the probability of picking a green counter. (Paper 2, calculator.)
Show worked answer →

The three outcomes are exhaustive (one must happen), so their probabilities add to 11.

P(green)=1P(red)P(blue)=10.350.4=0.25P(\text{green}) = 1 - P(\text{red}) - P(\text{blue}) = 1 - 0.35 - 0.4 = 0.25.

Markers award a mark for using "probabilities sum to 11" and a mark for the answer 0.250.25. Adding 0.350.35 and 0.40.4 but forgetting to subtract from 11 is the usual error.

Edexcel 20213 marksTwo fair six-sided dice are rolled and their scores added. Use a sample space to find the probability that the total is 99. (Paper 1, non-calculator.)
Show worked answer →

List the outcomes that give a total of 99 in a sample space (a grid of all 3636 equally likely outcomes).

The pairs are (3,6),(4,5),(5,4),(6,3)(3,6), (4,5), (5,4), (6,3), which is 44 outcomes.

P(total=9)=436=19P(\text{total} = 9) = \dfrac{4}{36} = \dfrac{1}{9}.

Markers award a mark for the total number of outcomes (3636), a mark for the four favourable outcomes, and a mark for the simplified probability. Forgetting that (3,6)(3,6) and (6,3)(6,3) are different outcomes is the common error.

Related dot points

Sources & how we know this