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How do you find circumference, area, arc length and sector area, and use circle theorems?

Circumference and area of a circle, arc length and sector area, and the circle theorems at Higher tier.

A focused answer to the AQA GCSE Mathematics geometry content on circles and arcs, covering circumference and area, arc length and sector area, and the circle theorems at Higher tier.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Circumference and area
  3. Arc length and sector area
  4. Circle theorems at Higher tier
  5. Chaining circle theorems with reasons
  6. Working in terms of pi and exact answers
  7. Segments and the area between shapes

What this dot point is asking

AQA wants you to find the circumference and area of a circle, the length of an arc and the area of a sector, and at Higher tier to apply the circle theorems with reasons. Circle questions appear at both tiers, and the Higher circle theorems are a reliable source of "state the reason" marks, so learning the theorem names precisely matters.

Circumference and area

A circle of radius 5cm5\,\text{cm} has circumference 2π×5=10π31.4cm2\pi \times 5 = 10\pi \approx 31.4\,\text{cm} and area π×52=25π78.5cm2\pi \times 5^2 = 25\pi \approx 78.5\,\text{cm}^2. To work backward, a circle of area 36πcm236\pi\,\text{cm}^2 has r2=36r^2 = 36, so r=6cmr = 6\,\text{cm}. Keep answers in terms of π\pi when the question asks, otherwise round as instructed.

Arc length and sector area

An arc is part of the circumference and a sector is a pie-slice of the area. Both are the same fraction θ360\dfrac{\theta}{360} of the whole circle, where θ\theta is the angle at the centre in degrees.

Circle theorems at Higher tier

The circle theorems give angle relationships for points on a circle. Learn each name as the reason:

  • Angle at the centre is twice the angle at the circumference (subtended by the same arc).
  • Angle in a semicircle is 9090^\circ (a special case where the chord is a diameter).
  • Angles in the same segment are equal (subtended by the same arc).
  • Opposite angles of a cyclic quadrilateral sum to 180180^\circ.
  • A tangent is perpendicular to the radius at the point of contact.
  • Tangents from an external point are equal in length, and the alternate segment theorem links a tangent-chord angle to the angle in the alternate segment.

For example, if the angle at the centre subtended by an arc is 130130^\circ, the angle at the circumference subtended by the same arc is 6565^\circ, because the centre angle is twice the circumference angle.

Chaining circle theorems with reasons

Higher questions often need two or three theorems in sequence, each justified. A typical chain: a cyclic quadrilateral has one angle of 9595^\circ, so the opposite angle is 18095=85180^\circ - 95^\circ = 85^\circ (opposite angles of a cyclic quadrilateral sum to 180180^\circ); then if a radius meets a tangent at a labelled vertex, that angle is 9090^\circ (tangent perpendicular to radius). Write each step with its reason on the same line, because the reasoning marks are awarded per theorem used. Building the answer one justified step at a time, rather than jumping to the final number, is what secures full marks.

Working in terms of pi and exact answers

Many circle questions ask for answers "in terms of π\pi", meaning you leave π\pi as a symbol rather than evaluating it. A circle of radius 7cm7\,\text{cm} has area 49πcm249\pi\,\text{cm}^2 and circumference 14πcm14\pi\,\text{cm} exactly. Leaving π\pi in keeps the answer precise and is often quicker on a non-calculator paper. Only replace π\pi with 3.141593.14159\ldots when the question asks for a decimal or a rounded value, and then round at the very end to avoid accumulating rounding errors through the calculation.

Segments and the area between shapes

A segment is the region between a chord and the arc it cuts off, found by subtracting the area of the triangle from the area of the sector. Composite area questions, such as the area inside a square but outside an inscribed circle, are solved by finding each area and subtracting. These combine the circle formulae with the area work from other shapes, so a clear plan (which areas to add, which to subtract) is the key to not losing track.

Exam-style practice questions

Practice questions written in the style of AQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AQA 20194 marksA sector of a circle has radius 9cm9\,\text{cm} and angle 4040^\circ. Work out the area of the sector, giving your answer to 3 significant figures. (Higher tier, Paper 2, calculator.)
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A sector is a fraction 40360\dfrac{40}{360} of the full circle.

Full circle area: πr2=π×92=81πcm2\pi r^2 = \pi \times 9^2 = 81\pi\,\text{cm}^2.

Sector area: 40360×81π=19×81π=9π28.3cm2\dfrac{40}{360} \times 81\pi = \dfrac{1}{9} \times 81\pi = 9\pi \approx 28.3\,\text{cm}^2.

Markers reward the fraction of the circle, the full-circle area, and the rounded answer. Using the diameter instead of the radius is the standard error.

AQA 20213 marksAA, BB and CC are points on the circumference of a circle. ABAB is a diameter. State, with a reason, the size of angle ACBACB. (Higher tier, Paper 1, non-calculator.)
Show worked answer →

The angle in a semicircle is a right angle, because ABAB is a diameter and CC lies on the circumference.

So angle ACB=90ACB = 90^\circ.

Markers award a mark for 9090^\circ and a mark for the reason ("angle in a semicircle is 9090^\circ"). Stating only the value loses the reasoning mark.

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