How do you integrate harder functions using substitution, integration by parts, and partial fractions?
Integration by substitution, integration by parts, integration using partial fractions, and integrating expressions of the form f prime over f and products reducible by a trigonometric identity.
A focused answer to the OCR A-Level Mathematics A advanced integration content, covering integration by substitution, integration by parts, integrating with partial fractions, the f prime over f logarithm pattern, and using trigonometric identities to integrate products such as sine squared.
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What this dot point is asking
OCR wants you to integrate harder expressions using substitution (including changing the limits for a definite integral), integration by parts, and partial fractions, to recognise the pattern that integrates to a logarithm, and to use trigonometric identities to integrate squared functions such as .
The answer
Integration by substitution
Substitution reverses the chain rule. Pick an inner expression as , replace using , rewrite the whole integral in , integrate, and (for an indefinite integral) substitute back.
For a definite integral it is cleaner to change the limits to values of rather than substituting back.
The logarithm pattern
When the numerator is the derivative of the denominator, the integral is a logarithm. If the numerator is a constant multiple of the derivative, adjust by that constant. This pattern is worth spotting before reaching for a full substitution, because it gives the answer in one line.
Integration by parts
Integration by parts reverses the product rule. Choose to be the factor that simplifies when differentiated, and to be the factor you can integrate.
A useful guide for choosing : logarithms and powers of simplify on differentiating, so they make good choices for ; exponentials and sines stay manageable when integrated, so they make good choices for .
Partial fractions
A rational function with a factorised denominator is integrated by splitting it into partial fractions first, after which each piece becomes a logarithm.
Choosing the right technique
With several techniques available, a quick decision tree helps. If you spot , write down the logarithm immediately. If the integrand is a product where one factor is the derivative of the inside of the other, use substitution. If it is a product of two unrelated functions (such as times an exponential or a trigonometric function), use parts. If it is a rational function, split into partial fractions. If it contains or , apply a double angle identity first. Recognising the form quickly is worth as much as the technique itself in a timed paper.
Examples in context
A trigonometric identity first
You cannot integrate directly, but the double angle identity turns it into something you can.
Integrating with partial fractions
Try this
Q1. Find . [2 marks]
- Cue. Numerator is twice the derivative of the denominator: .
Q2. Find by parts. [3 marks]
- Cue. , , so .
Exam-style practice questions
Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
OCR 20195 marksUse integration by parts to find .Show worked answer →
Choose (simplifies on differentiating) and (M1), so and (A1).
Apply (M1): (A1).
The remaining integral gives (A1).
Markers reward a sensible choice of and , applying the by-parts formula, integrating the second term, and the constant.
OCR 20216 marksUse the substitution to find , then evaluate .Show worked answer →
With , , so (M1). The integral becomes (A1).
Integrate: (A1).
For the definite integral, change the limits: and (M1).
(M1, A1).
Markers reward the substitution and , the integral in , changing the limits, and the final value.
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Sources & how we know this
- OCR A Level Mathematics A (H240) specification — OCR (2017)