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How do the trends in reactivity of Group 2 metals and the halogens follow from their electron structures?

Group 2 reactivity and reducing power, reactions of Group 2 elements and their oxides and hydroxides, the halogens as oxidising agents, halide displacement, disproportionation of chlorine, and tests for halide ions.

An OCR H432 module 3 answer on Group 2 and the halogens: reactivity trends, reactions with water and oxygen, halogen displacement, disproportionation of chlorine, and halide ion tests.

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  1. What this topic is asking
  2. Group 2: reactivity as reducing agents
  3. Group 2 oxides and hydroxides
  4. The halogens: reactivity as oxidising agents
  5. Disproportionation of chlorine
  6. Testing for halide ions
  7. Examples in context
  8. Try this

What this topic is asking

OCR specification point 3.1.2 wants you to describe the reactions and reactivity trends of the Group 2 elements (as reducing agents) and of the halogens (as oxidising agents). You must cover Group 2 reactions with water and oxygen, the use of their oxides and hydroxides, halogen-halide displacement, the disproportionation of chlorine, and the silver nitrate test for halide ions. These trends all follow from how easily electrons are lost or gained.

Group 2: reactivity as reducing agents

The metals react with water to form a hydroxide and hydrogen, the reaction becoming more vigorous down the group:

Group 2 oxides and hydroxides

The oxides react with water to form alkaline hydroxide solutions, and hydroxide solubility increases down the group, so the solutions become more strongly alkaline. Group 2 compounds have practical uses as bases: Mg(OH)2\text{Mg(OH)}_2 in antacids and Ca(OH)2\text{Ca(OH)}_2 (lime) to raise the pH of acidic soils and to treat flue gases.

The halogens: reactivity as oxidising agents

A more reactive halogen displaces the ions of a less reactive one from solution. For example, chlorine displaces bromine:

Disproportionation of chlorine

Testing for halide ions

Adding dilute nitric acid then silver nitrate solution gives a precipitate whose colour identifies the halide: chloride white, bromide cream, iodide yellow. The colours are confirmed by solubility in ammonia: AgCl\text{AgCl} dissolves in dilute ammonia, AgBr\text{AgBr} only in concentrated ammonia, and AgI\text{AgI} in neither. The nitric acid first removes carbonate ions, which would otherwise give a false positive.

Examples in context

Example 1. Water treatment. The disproportionation of chlorine in water produces chloric(I) acid, the active disinfectant, balancing the benefit of clean water against the toxicity of chlorine itself, a classic application of redox.

Example 2. Agricultural lime. Farmers spread calcium hydroxide to neutralise acidic soils; because hydroxide solubility increases down Group 2, the choice of base is tuned to how much alkalinity is needed.

Try this

Q1. Write an equation for the reaction of strontium with water. [1 mark]

  • Cue. Sr+2H2Oβ†’Sr(OH)2+H2\text{Sr} + 2\text{H}_2\text{O} \rightarrow \text{Sr(OH)}_2 + \text{H}_2.

Q2. Explain why chlorine displaces iodide ions but iodine does not displace chloride ions. [2 marks]

  • Cue. Chlorine is a stronger oxidising agent than iodine, so it can take electrons from iodide, but iodine is too weak an oxidiser to remove electrons from chloride.

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20194 marksChlorine reacts with cold dilute sodium hydroxide. (a) Write the equation for this reaction. (b) Explain, using oxidation numbers, why this is a disproportionation reaction.
Show worked answer β†’

(a) Cl2+2NaOH→NaCl+NaClO+H2O\text{Cl}_2 + 2\text{NaOH} \rightarrow \text{NaCl} + \text{NaClO} + \text{H}_2\text{O} (1).

(b) In Cl2\text{Cl}_2 the oxidation number of chlorine is 00 (1). In NaCl\text{NaCl} it falls to βˆ’1-1 (reduction) and in NaClO\text{NaClO} it rises to +1+1 (oxidation) (1). The same element is both oxidised and reduced, which is the definition of disproportionation (1).

Markers reward the balanced equation, the three oxidation numbers, and the statement that one element is simultaneously oxidised and reduced.

OCR 20213 marksDescribe how you would use aqueous silver nitrate, followed by dilute and concentrated ammonia, to distinguish between aqueous solutions of sodium chloride, sodium bromide and sodium iodide.
Show worked answer β†’

Add dilute nitric acid then aqueous silver nitrate to each solution. Chloride gives a white precipitate of AgCl\text{AgCl}, bromide a cream precipitate of AgBr\text{AgBr}, and iodide a yellow precipitate of AgI\text{AgI} (1).

Confirm with ammonia: AgCl\text{AgCl} dissolves in dilute ammonia, AgBr\text{AgBr} dissolves only in concentrated ammonia, and AgI\text{AgI} is insoluble in both (1). The acid first removes carbonate ions that would otherwise give a false precipitate (1).

Markers reward the three colours, the differing solubilities in ammonia, and the role of the acid.

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