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How do the structure of the periodic table and the periodic trends in properties follow from electron configuration?

The periodic table arranged by atomic number into periods and groups, the s, p and d blocks, and the periodic trends in atomic radius, first ionisation energy and melting point across Periods 2 and 3.

An OCR H432 module 3 answer on periodicity: the structure of the periodic table, the s, p and d blocks, and the trends in ionisation energy, atomic radius and melting point across Periods 2 and 3.

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  1. What this topic is asking
  2. Structure of the periodic table
  3. Trend in first ionisation energy
  4. Successive ionisation energies
  5. Trend in atomic radius
  6. Trend in melting point
  7. Examples in context
  8. Try this

What this topic is asking

OCR specification point 3.1.1 wants you to explain how the modern periodic table is arranged by atomic number into periods and groups, to assign elements to the s, p and d blocks from their electron configuration, and to describe and explain the periodic trends in atomic radius, first ionisation energy and melting point across Periods 2 and 3. Periodicity is the repeating pattern of properties that follows directly from electron structure.

Structure of the periodic table

Elements are placed in blocks named after the sub-shell that holds the highest-energy electron: the s-block (Groups 1 and 2), the p-block (Groups 13 to 18), and the d-block (the transition metals). Knowing the block lets you write the electron configuration directly from an element's position.

Trend in first ionisation energy

The first ionisation energy is the energy to remove one electron from each atom in one mole of gaseous atoms:

Across a period the nuclear charge increases while the electrons enter the same shell with similar shielding, so the outer electrons are held more tightly. Down a group the outer electron is in a higher shell, further from the nucleus and better shielded, so it is easier to remove.

Successive ionisation energies

Removing electrons one after another gives successive ionisation energies that always rise, because each electron is pulled from an increasingly positive ion. Large jumps mark the move to a new, inner shell, which is evidence for shell structure and lets you identify the group of an element.

Trend in atomic radius

Atomic radius decreases across a period because the rising nuclear charge pulls the same outer shell inward. It increases down a group because each new period adds a shell, and the extra shielding outweighs the higher nuclear charge.

Trend in melting point

Examples in context

Example 1. Predicting reactivity. Because first ionisation energy falls down Group 1, caesium loses its outer electron far more readily than lithium, which is why the Group 1 metals get more reactive down the group.

Example 2. Identifying an element from data. A jump between the second and third successive ionisation energies tells you the element is in Group 2, because the third electron must come from a stable inner shell.

Try this

Q1. State the block of the periodic table that contains iron and explain your answer. [2 marks]

  • Cue. The d-block, because iron's highest-energy electrons fill the 3d3\text{d} sub-shell ([Ar]3d64s2[\text{Ar}]3\text{d}^6 4\text{s}^2).

Q2. Explain why the first ionisation energy of sulfur is lower than that of phosphorus. [2 marks]

  • Cue. Sulfur's 3p43\text{p}^4 has a paired electron in one 3p3\text{p} orbital; the pair repulsion makes one electron easier to remove than from phosphorus's half-filled 3p33\text{p}^3.

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20185 marksExplain why the first ionisation energy of sodium is lower than that of magnesium, but the first ionisation energy of aluminium is lower than that of magnesium.
Show worked answer →

Magnesium has one more proton than sodium, so a greater nuclear charge attracts the outer 3s3\text{s} electrons more strongly, giving a higher first ionisation energy than sodium (1). Both lose an electron from the same 3s3\text{s} sub-shell with similar shielding (1).

Aluminium loses an electron from a 3p3\text{p} sub-shell, which is higher in energy and slightly further from the nucleus than the 3s3\text{s} sub-shell of magnesium (1). The 3p3\text{p} electron is therefore less strongly attracted and easier to remove (1), so aluminium has a lower first ionisation energy than magnesium despite the extra proton (1).

Markers reward nuclear charge for the Na to Mg step, and the 3s3\text{s} to 3p3\text{p} sub-shell change for the Mg to Al dip.

OCR 20203 marksDescribe and explain the trend in atomic radius across Period 3 from sodium to chlorine.
Show worked answer →

The atomic radius decreases across the period (1). The nuclear charge increases as protons are added, but the electrons are added to the same outer shell with similar shielding (1). The increasing attraction pulls the outer shell closer to the nucleus, so the atoms get smaller from Na to Cl (1).

Markers reward the direction of the trend, the rising nuclear charge with constant shielding, and the resulting stronger attraction.

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