How do the structure of the periodic table and the periodic trends in properties follow from electron configuration?
The periodic table arranged by atomic number into periods and groups, the s, p and d blocks, and the periodic trends in atomic radius, first ionisation energy and melting point across Periods 2 and 3.
An OCR H432 module 3 answer on periodicity: the structure of the periodic table, the s, p and d blocks, and the trends in ionisation energy, atomic radius and melting point across Periods 2 and 3.
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What this topic is asking
OCR specification point 3.1.1 wants you to explain how the modern periodic table is arranged by atomic number into periods and groups, to assign elements to the s, p and d blocks from their electron configuration, and to describe and explain the periodic trends in atomic radius, first ionisation energy and melting point across Periods 2 and 3. Periodicity is the repeating pattern of properties that follows directly from electron structure.
Structure of the periodic table
Elements are placed in blocks named after the sub-shell that holds the highest-energy electron: the s-block (Groups 1 and 2), the p-block (Groups 13 to 18), and the d-block (the transition metals). Knowing the block lets you write the electron configuration directly from an element's position.
Trend in first ionisation energy
The first ionisation energy is the energy to remove one electron from each atom in one mole of gaseous atoms:
Across a period the nuclear charge increases while the electrons enter the same shell with similar shielding, so the outer electrons are held more tightly. Down a group the outer electron is in a higher shell, further from the nucleus and better shielded, so it is easier to remove.
Successive ionisation energies
Removing electrons one after another gives successive ionisation energies that always rise, because each electron is pulled from an increasingly positive ion. Large jumps mark the move to a new, inner shell, which is evidence for shell structure and lets you identify the group of an element.
Trend in atomic radius
Atomic radius decreases across a period because the rising nuclear charge pulls the same outer shell inward. It increases down a group because each new period adds a shell, and the extra shielding outweighs the higher nuclear charge.
Trend in melting point
Examples in context
Example 1. Predicting reactivity. Because first ionisation energy falls down Group 1, caesium loses its outer electron far more readily than lithium, which is why the Group 1 metals get more reactive down the group.
Example 2. Identifying an element from data. A jump between the second and third successive ionisation energies tells you the element is in Group 2, because the third electron must come from a stable inner shell.
Try this
Q1. State the block of the periodic table that contains iron and explain your answer. [2 marks]
- Cue. The d-block, because iron's highest-energy electrons fill the sub-shell ().
Q2. Explain why the first ionisation energy of sulfur is lower than that of phosphorus. [2 marks]
- Cue. Sulfur's has a paired electron in one orbital; the pair repulsion makes one electron easier to remove than from phosphorus's half-filled .
Exam-style practice questions
Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
OCR 20185 marksExplain why the first ionisation energy of sodium is lower than that of magnesium, but the first ionisation energy of aluminium is lower than that of magnesium.Show worked answer →
Magnesium has one more proton than sodium, so a greater nuclear charge attracts the outer electrons more strongly, giving a higher first ionisation energy than sodium (1). Both lose an electron from the same sub-shell with similar shielding (1).
Aluminium loses an electron from a sub-shell, which is higher in energy and slightly further from the nucleus than the sub-shell of magnesium (1). The electron is therefore less strongly attracted and easier to remove (1), so aluminium has a lower first ionisation energy than magnesium despite the extra proton (1).
Markers reward nuclear charge for the Na to Mg step, and the to sub-shell change for the Mg to Al dip.
OCR 20203 marksDescribe and explain the trend in atomic radius across Period 3 from sodium to chlorine.Show worked answer →
The atomic radius decreases across the period (1). The nuclear charge increases as protons are added, but the electrons are added to the same outer shell with similar shielding (1). The increasing attraction pulls the outer shell closer to the nucleus, so the atoms get smaller from Na to Cl (1).
Markers reward the direction of the trend, the rising nuclear charge with constant shielding, and the resulting stronger attraction.
Related dot points
- Group 2 reactivity and reducing power, reactions of Group 2 elements and their oxides and hydroxides, the halogens as oxidising agents, halide displacement, disproportionation of chlorine, and tests for halide ions.
An OCR H432 module 3 answer on Group 2 and the halogens: reactivity trends, reactions with water and oxygen, halogen displacement, disproportionation of chlorine, and halide ion tests.
- Qualitative tests for carbonate, sulfate, halide and ammonium ions, the correct sequence of tests to avoid interference, and the observations and ionic equations for each test.
An OCR H432 module 3 answer on qualitative analysis: tests for carbonate, sulfate, halide and ammonium ions, the order of testing to avoid false results, and the relevant ionic equations.
- Sub-atomic particles and their relative masses and charges, atomic number and mass number, isotopes and their identical chemical properties, and the determination of relative atomic mass from mass spectra.
An OCR H432 module 2 answer covering protons, neutrons and electrons, atomic and mass number, isotopes, and calculating relative atomic and isotopic mass from mass spectrometry data.
- Electron configuration in shells, sub-shells and orbitals, ionic, covalent (including dative) and metallic bonding, electronegativity and bond polarity, electron-pair repulsion and molecular shapes, and the properties of the four crystal structures.
An OCR H432 module 2 answer covering electron configuration in sub-shells and orbitals, ionic, covalent, dative and metallic bonding, electronegativity and polarity, electron-pair repulsion shapes, and crystal structures.
Sources & how we know this
- OCR A-Level Chemistry A (H432) specification — OCR (2015)