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How do unstable nuclei decay and how fast?

Alpha, beta and gamma radiation and their properties, the random nature of decay, the decay constant and activity, the exponential decay law, and half-life.

A focused answer to the Edexcel 9PH0 radioactivity content, covering alpha, beta and gamma radiation, the random nature of decay, the decay constant and activity, the exponential decay law, and half-life.

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  1. What this dot point is asking
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What this dot point is asking

Edexcel wants you to describe alpha, beta and gamma radiation and their properties, explain the random and spontaneous nature of decay, define the decay constant and activity, use the exponential decay law, and work with half-life.

The answer

Types of radiation

The more ionising a radiation, the more rapidly it loses energy and the shorter its range. In magnetic and electric fields, alpha and beta deflect in opposite directions (opposite charges) and gamma is undeflected (no charge).

Random and spontaneous decay

Because decay is random, we work with the average behaviour of huge numbers of nuclei, which gives smooth exponential statistics even though each individual decay is unpredictable. The fluctuations seen on a count-rate meter are direct evidence of this randomness.

Decay constant, activity and the decay law

A larger decay constant means faster decay and a shorter half-life. The exponential form arises because the rate of decay is proportional to the number of nuclei present, dNdt=λN\frac{dN}{dt} = -\lambda N. Plotting lnA\ln A against tt gives a straight line of gradient λ-\lambda, the standard way to find the decay constant experimentally.

Half-life

After nn half-lives the activity is A0×(12)nA_0 \times (\frac{1}{2})^n. Half-lives range from fractions of a second to billions of years, which is what makes some isotopes useful for dating and others for medical imaging.

Examples in context

Carbon-14 dating measures the residual activity of ancient organic material against its known half-life. Smoke detectors use a tiny alpha source (americium-241) whose short range makes it safe behind a screen. Medical tracers such as technetium-99m have short half-lives so they decay away quickly after imaging. Radiotherapy uses penetrating gamma sources to target tumours, and nuclear power monitoring tracks the activity of fission products.

Try this

Q1. State which type of radiation is the most ionising. [1 mark]

  • Cue. Alpha radiation.

Q2. A source has a half-life of 4.04.0 days and an initial activity of 640640 Bq. Find its activity after 1212 days. [2 marks]

  • Cue. Twelve days is three half-lives: 64032016080640 \rightarrow 320 \rightarrow 160 \rightarrow 80 Bq.

Q3. A sample has decay constant λ=0.10\lambda = 0.10 per year. Find its half-life. [2 marks]

  • Cue. t1/2=ln2λ=0.6930.10=6.9t_{1/2} = \frac{\ln 2}{\lambda} = \frac{0.693}{0.10} = 6.9 years.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20174 marksA radioactive source has a decay constant of 2.5×1032.5 \times 10^{-3} per second. Calculate its half-life and the activity of a sample containing 4.0×10184.0 \times 10^{18} undecayed nuclei.
Show worked answer →

Half-life: t1/2=ln2λ=0.6932.5×103=2.8×102t_{1/2} = \frac{\ln 2}{\lambda} = \frac{0.693}{2.5 \times 10^{-3}} = 2.8 \times 10^{2} s.

Activity: A=λN=2.5×103×4.0×1018=1.0×1016A = \lambda N = 2.5 \times 10^{-3} \times 4.0 \times 10^{18} = 1.0 \times 10^{16} Bq.

Markers reward t1/2=ln2λt_{1/2} = \frac{\ln 2}{\lambda}, A=λNA = \lambda N, and the values about 280280 s and 1.0×10161.0 \times 10^{16} Bq.

Edexcel 20205 marksA sample of a radioactive isotope has an initial activity of 800800 Bq and a half-life of 6.06.0 hours. Determine the activity after 1818 hours and explain what is meant by the random nature of radioactive decay.
Show worked answer →

Eighteen hours is three half-lives, so the activity halves three times: 800400200100800 \rightarrow 400 \rightarrow 200 \rightarrow 100 Bq. (Equivalently A=A0(12)3=800×18=100A = A_0 (\frac{1}{2})^{3} = 800 \times \frac{1}{8} = 100 Bq.)

Random nature: it is impossible to predict which nucleus will decay next or when a given nucleus will decay; each undecayed nucleus has the same constant probability of decaying per unit time, independent of its history and of other nuclei.

Markers reward the three-half-life reasoning, the value 100100 Bq, and a clear statement of randomness and constant probability.

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