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EnglandPhysicsSyllabus dot point

How do capacitors store charge and energy?

Capacitance as charge per unit potential difference, the energy stored on a capacitor, and the exponential charge and discharge of a capacitor through a resistor with the time constant.

A focused answer to the Edexcel 9PH0 capacitance content, covering capacitance as charge per unit voltage, the energy stored, and the exponential charging and discharging of a capacitor through a resistor with the time constant.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
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What this dot point is asking

Edexcel wants you to define capacitance as charge per unit potential difference, calculate the energy stored on a charged capacitor, and analyse the exponential charging and discharging of a capacitor through a resistor using the time constant τ=RC\tau = RC.

The answer

Capacitance

A larger capacitance stores more charge at a given voltage. Practical capacitors are measured in microfarads or smaller because a farad is enormous. Capacitors in parallel add (C=C1+C2+C = C_1 + C_2 + \ldots) since they share the same voltage and the charges add; capacitors in series combine reciprocally (1C=1C1+1C2+\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_2} + \ldots) since they carry the same charge and the voltages add.

Energy stored

The factor of one half appears because the potential difference grows from zero to its final value as charge is added; the average voltage during charging is half the final voltage. On a VV against QQ graph the stored energy is the triangular area 12QV\frac{1}{2}QV. When a capacitor charges through a resistor, exactly half the energy delivered by the supply is dissipated as heat in the resistor, regardless of the resistance, with the other half stored on the capacitor.

Charging and discharging

When a capacitor discharges through a resistor, the current is proportional to the charge remaining, which gives exponential decay:

The time constant τ=RC\tau = RC has units of seconds and sets the timescale: after one time constant the discharging quantity has fallen to 1e0.37\frac{1}{e} \approx 0.37 of its start value, and after 5τ5\tau the capacitor is essentially fully discharged or charged. A larger RR or CC slows the process. Taking natural logs of the discharge equation gives lnV=lnV0tRC\ln V = \ln V_0 - \frac{t}{RC}, so a graph of lnV\ln V against tt is a straight line of gradient 1RC-\frac{1}{RC}, the standard way to find τ\tau experimentally.

Examples in context

A camera flash stores energy on a large capacitor and dumps it rapidly through the flash tube, the short RCRC giving a brief, intense pulse. Smoothing capacitors in a power supply charge during voltage peaks and discharge into the load between them, reducing ripple. Defibrillators store hundreds of joules on a capacitor and release it in milliseconds. The long RCRC time of a backup capacitor keeps a clock running through a brief power cut.

Try this

Q1. Define capacitance. [1 mark]

  • Cue. The charge stored per unit potential difference, C=QVC = \frac{Q}{V}, in farads.

Q2. A 5050 microfarad capacitor is charged to 2020 V. Find the energy stored. [2 marks]

  • Cue. W=12CV2=12×50×106×202=1.0×102W = \frac{1}{2}CV^2 = \frac{1}{2} \times 50 \times 10^{-6} \times 20^2 = 1.0 \times 10^{-2} J.

Q3. A capacitor discharges through a resistor with time constant τ=4.0\tau = 4.0 s. Find the fraction of charge remaining after 4.04.0 s. [2 marks]

  • Cue. QQ0=et/τ=e1=0.37\frac{Q}{Q_0} = e^{-t/\tau} = e^{-1} = 0.37, so about 37%37\% remains.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20194 marksA 470470 microfarad capacitor is charged to 1212 V. Calculate the charge stored and the energy stored.
Show worked answer →

Charge: Q=CV=470×106×12=5.6×103Q = CV = 470 \times 10^{-6} \times 12 = 5.6 \times 10^{-3} C.

Energy: W=12CV2=12×470×106×122=12×470×106×144=3.4×102W = \frac{1}{2}CV^2 = \frac{1}{2} \times 470 \times 10^{-6} \times 12^2 = \frac{1}{2} \times 470 \times 10^{-6} \times 144 = 3.4 \times 10^{-2} J.

Markers reward Q=CVQ = CV, the half in the energy formula, and consistent conversion of microfarads to farads.

Edexcel 20225 marksA 100100 microfarad capacitor charged to 9.09.0 V discharges through a 5050 k-ohm resistor. Determine the time constant and calculate the potential difference across the capacitor after 1010 s.
Show worked answer →

Time constant: τ=RC=50×103×100×106=5.0\tau = RC = 50 \times 10^{3} \times 100 \times 10^{-6} = 5.0 s.

Discharge follows V=V0et/τV = V_0 e^{-t/\tau}, so V=9.0×e10/5.0=9.0×e2=9.0×0.135=1.2V = 9.0 \times e^{-10/5.0} = 9.0 \times e^{-2} = 9.0 \times 0.135 = 1.2 V.

Markers reward τ=RC=5.0\tau = RC = 5.0 s, the correct exponential form, and the value about 1.21.2 V.

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