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How do we know the atom has a tiny dense nucleus?

The alpha-particle scattering experiment, the nuclear model of the atom, the proton and neutron, nuclide notation, and estimating nuclear radius and density.

A focused answer to the Edexcel 9PH0 nuclear atom content, covering the alpha-particle scattering experiment, the nuclear model, the proton and neutron, nuclide notation, and estimating nuclear radius and density.

Generated by Claude Opus 4.811 min answer

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What this dot point is asking

Edexcel wants you to describe the alpha-particle scattering experiment and the nuclear model it established, identify the proton and neutron, use nuclide notation, and estimate nuclear radius (through R=r0A1/3R = r_0 A^{1/3}) and the very high density of nuclear matter.

The answer

The alpha-particle scattering experiment

The Geiger-Marsden experiment, interpreted by Rutherford, fired alpha particles at a thin gold foil and recorded where they went. Most passed straight through, a small fraction were deflected through large angles, and about one in 80008000 bounced almost straight back. The "mostly straight through" result shows the atom is largely empty space; the rare large-angle and back-scattering events show that the positive charge and nearly all the mass are concentrated in a tiny central nucleus that strongly repels an incoming positive alpha particle.

Protons, neutrons and nuclide notation

A nuclide is written with AA as a superscript and ZZ as a subscript before the element symbol. Isotopes of an element have the same ZZ but different AA (different numbers of neutrons), so they share chemical behaviour but differ in mass and nuclear stability.

Nuclear radius and density

Electron-diffraction and scattering experiments show that nuclear radius depends on nucleon number through a simple law:

The cube-root law means the nucleus behaves like a drop of incompressible fluid: doubling the number of nucleons doubles the volume, not the radius. The resulting density, around 101710^{17} kg per cubic metre, is fantastically larger than everyday matter and matches the density of a neutron star.

Examples in context

The nuclear model underpins all of nuclear physics and chemistry, explaining the periodic table through proton number. Electron-scattering measurements of nuclear radius confirm the A1/3A^{1/3} law and feed into models of nuclear stability. The extreme nuclear density reappears in astrophysics: a neutron star is essentially nuclear matter on a stellar scale, where gravity has crushed protons and electrons together. Isotope identification by mass spectrometry relies on the proton-neutron picture established here.

Try this

Q1. State what the back-scattering of a few alpha particles told Rutherford. [1 mark]

  • Cue. That the atom has a tiny, dense, positively charged nucleus containing most of its mass.

Q2. A nucleus has nucleon number A=27A = 27 and r0=1.2×1015r_0 = 1.2 \times 10^{-15} m. Find its radius. [2 marks]

  • Cue. R=r0A1/3=1.2×1015×271/3=1.2×1015×3.0=3.6×1015R = r_0 A^{1/3} = 1.2 \times 10^{-15} \times 27^{1/3} = 1.2 \times 10^{-15} \times 3.0 = 3.6 \times 10^{-15} m.

Q3. Explain why all nuclei have approximately the same density. [2 marks]

  • Cue. Volume is proportional to AA (since RA1/3R \propto A^{1/3} so R3AR^3 \propto A), and mass is also proportional to AA, so mass per unit volume stays roughly constant.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20184 marksDescribe the results of the alpha-particle scattering experiment and explain what each result reveals about the structure of the atom.
Show worked answer →

Result 1: most alpha particles passed straight through with little or no deflection. This shows the atom is mostly empty space.

Result 2: a small number were deflected through large angles, and a very few (about one in 80008000) bounced almost straight back. This shows the positive charge and almost all the mass are concentrated in a tiny, dense central nucleus that repels the positive alpha particles.

Together the results led Rutherford to the nuclear model: a small, dense, positive nucleus surrounded by mostly empty space in which electrons move.

Markers reward both observations linked to their conclusions (mostly empty space, and a tiny dense positive nucleus).

Edexcel 20225 marksThe nuclear radius is given by R=r0A1/3R = r_0 A^{1/3} with r0=1.2×1015r_0 = 1.2 \times 10^{-15} m. Calculate the radius of a nucleus with nucleon number A=64A = 64 and estimate the density of nuclear matter. Take the nucleon mass as 1.67×10271.67 \times 10^{-27} kg.
Show worked answer →

Radius: R=r0A1/3=1.2×1015×641/3=1.2×1015×4.0=4.8×1015R = r_0 A^{1/3} = 1.2 \times 10^{-15} \times 64^{1/3} = 1.2 \times 10^{-15} \times 4.0 = 4.8 \times 10^{-15} m.

Mass of nucleus: m=A×1.67×1027=64×1.67×1027=1.07×1025m = A \times 1.67 \times 10^{-27} = 64 \times 1.67 \times 10^{-27} = 1.07 \times 10^{-25} kg.

Volume: V=43πR3=43π(4.8×1015)3=4.63×1043V = \frac{4}{3}\pi R^3 = \frac{4}{3}\pi (4.8 \times 10^{-15})^3 = 4.63 \times 10^{-43} cubic metres.

Density: ρ=mV=1.07×10254.63×1043=2.3×1017\rho = \frac{m}{V} = \frac{1.07 \times 10^{-25}}{4.63 \times 10^{-43}} = 2.3 \times 10^{17} kg per cubic metre.

Markers reward R=4.8×1015R = 4.8 \times 10^{-15} m, the volume of a sphere, and a density of order 101710^{17} kg per cubic metre.

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