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What features of the d-block electron configuration give transition metals their variable oxidation states, coloured ions and catalytic activity?

The definition of a transition metal in terms of an incomplete d sub-shell. The characteristic properties of transition metals: complex formation, coloured ions, variable oxidation states and catalytic activity. The shapes of complex ions and the meaning of coordination number and ligand. Stereoisomerism in complexes. Ligand substitution reactions and the chelate effect. The origin of colour in transition metal ions and its use in colorimetry. The role of transition metals as homogeneous and heterogeneous catalysts.

A focused answer to the AQA A-Level Chemistry 3.2.5 specification points on transition metals. Covers the d-sub-shell definition, complex ions, ligands and coordination number, the shapes and stereoisomerism of complexes, ligand substitution and the chelate effect, the origin of colour and colorimetry, variable oxidation states and homogeneous and heterogeneous catalysis.

Generated by Claude Opus 4.812 min answer

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  1. What this dot point is asking
  2. Definition
  3. Complex ions, ligands and coordination number
  4. Stereoisomerism in complexes
  5. Ligand substitution and the chelate effect
  6. The origin of colour and colorimetry
  7. Variable oxidation states and catalysis
  8. Try this

What this dot point is asking

AQA wants you to define a transition metal by its d sub-shell, explain the four characteristic properties (complex formation, coloured ions, variable oxidation states and catalysis), describe the shapes and stereoisomerism of complex ions, explain ligand substitution and the chelate effect, account for colour and its use in colorimetry, and describe transition metals as catalysts.

Definition

Complex ions, ligands and coordination number

Ligands can be monodentate (one lone pair, e.g. H2OH_2O, NH3NH_3, ClCl^-), bidentate (two, e.g. ethanedioate) or multidentate (e.g. EDTA, with six).

Stereoisomerism in complexes

Octahedral complexes with two different ligands can show cis-trans isomerism (e.g. cisplatin, used as an anti-cancer drug, is the cis isomer of [Pt(NH3)2Cl2][Pt(NH_3)_2Cl_2]). Octahedral complexes with three bidentate ligands can show optical isomerism (non-superimposable mirror images).

Ligand substitution and the chelate effect

One ligand can replace another. For example adding excess ammonia to aqueous copper(II):

[Cu(H2O)6]2++4NH3[Cu(NH3)4(H2O)2]2++4H2O[Cu(H_2O)_6]^{2+} + 4NH_3 \rightarrow [Cu(NH_3)_4(H_2O)_2]^{2+} + 4H_2O

The origin of colour and colorimetry

When ligands bond, the 3d orbitals split into two energy levels separated by an energy gap ΔE\Delta E. An electron absorbs visible light of frequency matching ΔE\Delta E and is promoted to the higher level; the complementary colour is transmitted, so the ion appears coloured. The relationship is:

ΔE=hν=hcλ\Delta E = h\nu = \frac{hc}{\lambda}

Changing the oxidation state, ligand, or coordination number changes ΔE\Delta E and so the colour. Ions with d0d^0 or d10d^{10} (e.g. Sc3+Sc^{3+}, Zn2+Zn^{2+}) are colourless. Colorimetry uses the depth of colour to find an unknown concentration against a calibration curve.

Variable oxidation states and catalysis

Transition metals show variable oxidation states because the 3d and 4s energies are similar, so a variable number of electrons can be lost.

  • Heterogeneous catalysts are in a different phase from the reactants and work by adsorbing reactants onto active sites on their surface (e.g. iron in the Haber process, vanadium(V) oxide in the Contact process).
  • Homogeneous catalysts are in the same phase and work by forming an intermediate, cycling between oxidation states (e.g. Fe2+/Fe3+Fe^{2+}/Fe^{3+} catalysing the reaction between iodide and peroxodisulfate ions).

Try this

Q1. State the shape and coordination number of [Cu(H2O)6]2+[Cu(H_2O)_6]^{2+}. [1 mark]

  • Cue. Octahedral, coordination number 6.

Q2. Explain why Zn2+Zn^{2+} solutions are colourless. [2 marks]

  • Cue. Zn2+Zn^{2+} is 3d103d^{10} (full d sub-shell), so no d-to-d electron promotion can occur, so no visible light is absorbed.

Q3. Name one heterogeneous and one homogeneous transition-metal catalyst and the reaction each catalyses. [2 marks]

  • Cue. Iron in the Haber process (heterogeneous); Fe2+Fe^{2+} catalysing iodide and peroxodisulfate (homogeneous).

Exam-style practice questions

Practice questions written in the style of AQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AQA Paper 1 (style)2 marksDefine the term transition metal and explain why zinc is not classed as one.
Show worked answer →

A 2-mark answer needs the d-sub-shell definition applied to an ion.

A transition metal is a d-block element that forms at least one stable ion with an incomplete d sub-shell. Zinc only forms Zn2+Zn^{2+}, which has a full 3d103d^{10} sub-shell, so it does not form an ion with a partially filled d sub-shell and is therefore not a transition metal. (Scandium is the other exception, forming only Sc3+Sc^{3+} with an empty 3d.)

Markers reward incomplete d sub-shell in an ion, and Zn2+Zn^{2+} being 3d103d^{10} (full).

AQA Paper 1 (style)3 marksExplain why aqueous copper(II) ions are blue.
Show worked answer →

A 3-mark answer needs the d-orbital splitting argument.

In [Cu(H2O)6]2+[Cu(H_2O)_6]^{2+} the ligands cause the 3d orbitals to split into two energy levels. An electron absorbs light of a particular frequency and is promoted from the lower to the higher d level. The complementary colour to the light absorbed is transmitted, so the solution appears blue.

Markers reward d-orbital splitting, electron promotion by absorbed light, and the transmitted complementary colour.

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