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AQA A-Level Biology 3.7 Genetics, populations, evolution and ecosystems: a complete deep dive

A deep-dive AQA A-Level Biology guide to section 3.7. Covers inheritance and the chi-squared test, the Hardy-Weinberg principle, natural selection, genetic drift and speciation, populations and carrying capacity, mark-release-recapture, and succession and conservation, with the calculations and answer structures AQA repeats.

Generated by Claude Opus 4.824 min readAQA-7402-3.7

Reviewed by: AI editorial process; not yet individually human-reviewed

Jump to a section
  1. What section 3.7 actually demands
  2. Inheritance and predicting offspring
  3. The chi-squared test
  4. Populations, gene pools and Hardy-Weinberg
  5. Natural selection, drift and speciation
  6. Populations in ecosystems
  7. Succession and conservation
  8. How section 3.7 is examined
  9. Check your knowledge

What section 3.7 actually demands

Section 3.7 is the capstone genetics-and-ecology topic of AQA A-Level Biology. It pulls together the genetics you met earlier and applies it at the level of whole populations: how alleles are inherited and tested statistically, how their frequencies are described and change, how that change produces new species, and how populations behave inside ecosystems that themselves change over time.

The topic rewards two distinct skills. The first is quantitative: three calculations (chi-squared, Hardy-Weinberg and mark-release-recapture) appear almost every year and are pure marks if you drill the steps. The second is structured explanation: natural selection, speciation and succession are each a fixed logical sequence that markers reward when you lay it out in order. Train both deliberately.

Inheritance and predicting offspring

A genotype is the alleles an organism carries; a phenotype is the observable trait produced by the genotype interacting with the environment. Most phenotypes are affected by more than one gene.

For a monohybrid cross of two heterozygotes (Aa×AaAa \times Aa) the genotypic ratio is 1:2:11:2:1 and the phenotypic ratio is 3:13:1. For an unlinked dihybrid cross (AaBb×AaBbAaBb \times AaBb) the phenotypic ratio is 9:3:3:19:3:3:1. Modified versions of these ratios are the exam's signal that something more is going on:

  • Codominance: both alleles expressed fully in the heterozygote (roan cattle, blood group AB).
  • Multiple alleles: more than two alleles in the population (ABO blood groups, with IAI^A and IBI^B codominant and IOI^O recessive).
  • Sex-linkage: genes on the X chromosome; males (XY) are hemizygous so express X-linked recessives more often than females.
  • Autosomal linkage: two genes on the same autosome inherited together, reducing recombinants and distorting the 9:3:3:19:3:3:1 ratio.
  • Epistasis: one gene masks another, giving modified ratios such as 9:3:49:3:4 (recessive epistasis) or 12:3:112:3:1 (dominant epistasis).

The chi-squared test

The chi-squared (X2X^2) test decides whether the difference between observed and expected counts is significant or just chance. It works only on raw counts with a clear expected ratio.

X2=∑(O−E)2EX^2 = \sum \frac{(O - E)^2}{E}

The method is always the same: state a null hypothesis (no significant difference), calculate expected counts from the ratio and the total, compute X2X^2, find degrees of freedom (categories minus 1), and compare to the critical value at p=0.05p = 0.05. If X2X^2 is below the critical value, accept the null hypothesis (the data fit the ratio); if it is at or above it, reject the null hypothesis (the difference is significant).

Populations, gene pools and Hardy-Weinberg

A population is interbreeding organisms of one species in one place at one time. Its gene pool is all the alleles of all the genes present, and an allele frequency is the proportion of a gene's copies that are a particular allele. Phenotypic variation within a population comes from genetic and environmental factors together.

The Hardy-Weinberg principle models a population in which allele frequencies do not change between generations:

p+q=1p2+2pq+q2=1p + q = 1 \qquad p^2 + 2pq + q^2 = 1

Here pp and qq are the dominant and recessive allele frequencies, and p2p^2, 2pq2pq, q2q^2 are the homozygous dominant, heterozygous and homozygous recessive genotype frequencies. Equilibrium holds only when all five conditions are met: no mutation, no migration, no natural selection, no genetic drift (a large population) and random mating. Because these are rarely all true, real allele frequencies usually change, and that change is the evidence of evolution.

The reliable calculation route starts from the recessive phenotype, the only phenotype that maps to a single genotype:

Natural selection, drift and speciation

Variation (from mutation) plus a selection pressure gives some individuals greater reproductive success; they pass on the advantageous allele, whose frequency rises over generations. This differential reproductive success is natural selection.

  • Directional selection shifts the mean toward one extreme when the environment changes (antibiotic resistance in bacteria).
  • Stabilising selection favours the intermediate and selects against extremes in a stable environment, reducing variation (human birth weight).

Genetic drift is random change in allele frequency, important in small populations where chance can fix or lose alleles. The founder effect is drift when a small, unrepresentative group founds a new population with reduced genetic diversity.

Speciation occurs when two populations become reproductively isolated so their gene pools can no longer mix and they diverge:

  • Allopatric speciation follows geographic isolation (a physical barrier separates the populations).
  • Sympatric speciation occurs in the same area through reproductive isolating mechanisms (seasonal, behavioural, or polyploidy in plants).

Populations in ecosystems

An ecosystem is all the living organisms plus the abiotic conditions in an area; a community is all its populations. The carrying capacity is the maximum stable population the ecosystem can support, set by:

  • Abiotic factors: temperature, light, water, pH, oxygen, mineral availability.
  • Biotic factors: intraspecific competition (within a species, the key density-dependent control that returns a population to carrying capacity), interspecific competition (between species), and predation.

Predator-prey populations cycle with the predator peak lagging the prey peak: abundant prey lets predators increase, more predators reduce prey, scarce prey starves predators, fewer predators let prey recover.

To estimate population size you sample and scale up: random quadrats for non-motile organisms, transects for distribution along an environmental gradient, and mark-release-recapture for mobile animals.

population estimate=n1×n2nm\text{population estimate} = \frac{n_1 \times n_2}{n_m}

where n1n_1 is the number first marked, n2n_2 the second sample size, and nmn_m the marked individuals recaptured. The method assumes marked individuals mix randomly, the mark does not affect survival or get lost, and there is no major birth, death or migration between samples.

Succession and conservation

Succession is the change in a community over time. Primary succession starts on bare ground with no soil; secondary succession starts on disturbed land that retains soil and is faster. Pioneer species adapted to harsh conditions colonise first and change the abiotic environment (building soil, retaining water, reducing harshness), letting more competitive species replace them through seres until a stable climax community forms. Diversity rises through the intermediate stages and may fall at the climax, where dominant competitors prevail.

Conservation frequently manages succession. Because succession tends toward a low-diversity climax, conserving diverse early-stage habitats (chalk grassland, heathland) often means deliberately halting succession by grazing, mowing, controlled burning or coppicing, holding the community at a plagioclimax. AQA also expects you to evaluate conflicting evidence in conservation, weighing ecological, economic and social interests to reach a justified conclusion.

How section 3.7 is examined

A typical AQA 3.7 profile across the papers:

  • Multiple choice and short answer: identifying inheritance patterns and modified ratios, naming selection types, distinguishing allopatric and sympatric speciation, reading predator-prey and succession data.
  • Calculations: chi-squared on offspring data, Hardy-Weinberg allele and genotype frequencies, mark-release-recapture estimates. These are the most reliable marks in the topic.
  • Extended response: explaining natural selection (for example antibiotic resistance) as a sequence, describing succession from pioneer to climax, or evaluating conservation evidence.
  • Synoptic essay (Paper 3): variation, selection and evolution are recurring essay themes that draw on 3.7.

Check your knowledge

A mix of definitional, calculation and exam-style questions covering the whole of section 3.7. Attempt all under timed conditions, then check against the solutions block.

  1. Define genotype, phenotype and gene pool, and explain why the dominant phenotype cannot be mapped to a single genotype. (4 marks)
  2. A dihybrid self-cross expected to give a 9:3:3:1 ratio produces offspring counts of 90, 28, 32 and 10 (total 160). Carry out a chi-squared test and state your conclusion. Critical value at p = 0.05 and 3 degrees of freedom = 7.815. (5 marks)
  3. A recessive allele causes a metabolic condition affecting 1 in 400 people. Use Hardy-Weinberg to calculate (a) the frequency of the recessive allele, (b) the frequency of carriers, and (c) the percentage of the population that are homozygous dominant. (4 marks)
  4. (a, 3) Explain how directional selection has led to a population of insects becoming resistant to an insecticide. (b, 2) State how stabilising selection differs, with a named example. (5 marks)
  5. (a, 3) Describe the role of geographic isolation in allopatric speciation. (b, 2) Explain how sympatric speciation can occur without a geographic barrier. (5 marks)
  6. A researcher captures and marks 64 grasshoppers, releases them, and later captures 48, of which 16 are marked. (a, 2) Estimate the population size. (b, 3) State and explain two assumptions of the method. (5 marks)
  7. Using the concept of succession, explain why a heathland nature reserve carries out controlled burning and grazing. (6 marks)
  • biology
  • a-level-aqa
  • aqa-biology
  • populations
  • a-level
  • inheritance
  • hardy-weinberg
  • speciation
  • ecosystems
  • succession