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How do we calculate the total resistance of combined resistors and read a resistor's value and tolerance?

Calculating the total resistance of resistors in series and in parallel, and identifying a resistor's value, tolerance and power rating from its colour code or the E24 preferred-value series.

A focused answer to WJEC Eduqas GCSE Electronics on combining resistors, covering the total resistance of series and parallel resistors and reading a resistor's value, tolerance and power rating from colour codes and the E24 series.

Generated by Claude Opus 4.89 min answer

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  1. What this topic is asking
  2. Resistors in series
  3. Resistors in parallel
  4. Resistor values, codes and the E24 series
  5. Tolerance and power rating
  6. Try this

What this topic is asking

WJEC Eduqas wants you to calculate the total resistance of resistors connected in series and in parallel, and to identify a resistor's value, tolerance and power rating from its colour code or from the E24 preferred-value series. These skills feed directly into potential dividers and into choosing real components for a circuit.

Resistors in series

Adding resistors in series is like making a wire longer: the charge meets more opposition, so the total resistance rises. Because the current is the same through each, the voltages across them add to the supply (the series voltage rule), and they share the supply voltage in proportion to their resistance. Two 100Ω100\,\Omega resistors in series give 200Ω200\,\Omega.

Resistors in parallel

Adding resistors in parallel is like widening a wire: the charge gains extra paths, so the total resistance falls and more current flows from the supply. Remember to take the reciprocal at the end: the sum of the reciprocals gives 1Rtotal\dfrac{1}{R_{\text{total}}}, not RtotalR_{\text{total}}. A quick shortcut for two resistors is Rtotal=R1R2R1+R2R_{\text{total}} = \dfrac{R_1 R_2}{R_1 + R_2} (product over sum).

Resistor values, codes and the E24 series

The first colour bands give the significant figures and the next band the multiplier (the power of ten). For example, bands of red (2), red (2) and brown (multiplier ×10\times 10) give 22×10=220Ω22 \times 10 = 220\,\Omega. The E24 values are spaced so that, allowing for ±5%\pm 5\% tolerance, every possible resistance is covered without gaps. You select the nearest preferred value to a calculated resistance.

Tolerance and power rating

Tolerance matters because a ±5%\pm 5\% 220Ω220\,\Omega resistor could really be anywhere from about 209Ω209\,\Omega to 231Ω231\,\Omega; for a precise potential divider you might need a tighter tolerance. Power rating matters because a resistor that dissipates more power than its rating will overheat and may fail; calculate the power with P=I2RP = I^2R or P=VIP = VI and choose a standard rating safely above it.

Try this

Q1. Calculate the total resistance of three 300Ω300\,\Omega resistors in parallel. [2 marks]

  • Cue. 1R=3300=1100\dfrac{1}{R} = \dfrac{3}{300} = \dfrac{1}{100}, so R=100ΩR = 100\,\Omega.

Q2. A resistor has bands brown, black, red. State its resistance. [1 mark]

  • Cue. Brown (1), black (0), red (multiplier ×100\times 100): 10×100=1000Ω=1.0kΩ10 \times 100 = 1000\,\Omega = 1.0\,\text{k}\Omega.

Exam-style practice questions

Practice questions written in the style of WJEC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Eduqas style3 marksCalculate the total resistance of a 220Ω220\,\Omega resistor in series with a 330Ω330\,\Omega resistor, and then of the same two resistors in parallel.
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A Component 1 Calculate question on combining resistors. In series, total resistance adds: R=220+330=550ΩR = 220 + 330 = 550\,\Omega (1 mark). In parallel, use 1R=1220+1330\dfrac{1}{R} = \dfrac{1}{220} + \dfrac{1}{330}. This gives 1R=0.004545+0.003030=0.007576\dfrac{1}{R} = 0.004545 + 0.003030 = 0.007576, so R=10.007576=132ΩR = \dfrac{1}{0.007576} = 132\,\Omega (2 marks for the reciprocal method and the value). Markers reward the series sum and the parallel reciprocal calculation. A common error is to add the parallel resistances or to forget the final reciprocal.

Eduqas style3 marksA resistor is marked with the colour bands red, red, brown, gold. State its resistance and tolerance, and explain what the tolerance means.
Show worked answer →

A Component 1 colour-code question. Red is 2, red is 2, brown is the multiplier ×10\times 10: so the value is 22×10=220Ω22 \times 10 = 220\,\Omega (1 mark). The gold band is a tolerance of ±5%\pm 5\% (1 mark). The tolerance means the actual resistance may differ from 220Ω220\,\Omega by up to ±5%\pm 5\% (that is, between about 209Ω209\,\Omega and 231Ω231\,\Omega), because resistors are mass-produced to preferred values rather than exact ones (1 mark). Markers reward the value, the tolerance and the meaning. A common error is to misread the band order or to ignore the multiplier.

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