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How do we sample a population fairly, and how do we present and interpret the data we collect?

Populations and samples, random and non-random sampling methods, and presenting and interpreting data with measures of location, spread, histograms and box plots.

A focused answer to WJEC AS Unit 2 statistics, covering populations and samples, random and non-random sampling methods, measures of location and spread, and presenting data with histograms and box plots.

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
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What this dot point is asking

WJEC wants you to distinguish a population from a sample, to describe and compare sampling methods (random, systematic, stratified, quota, opportunity), and to present and interpret data using measures of location (mean, median, mode), measures of spread (range, interquartile range, standard deviation), histograms and box plots. This is the descriptive backbone of the statistics section before the probability and distribution work.

The answer

Populations and samples

A census measures every member of a population; a sample measures a subset. Sampling is used when a census is too costly, too slow, or destroys the item tested. A good sample should be representative so that conclusions generalise to the population.

Sampling methods

Stratified sampling is the one most often calculated: find the sampling fraction sample sizepopulation\dfrac{\text{sample size}}{\text{population}} and apply it to each stratum.

Measures of location and spread

The mean is xˉ=xn\bar{x} = \dfrac{\sum x}{n}; the median is the middle value when ordered; the mode is the most frequent. For spread, the range is max minus min, the interquartile range is Q3Q1Q_3 - Q_1 (resistant to outliers), and the standard deviation measures typical distance from the mean.

Histograms and box plots

A histogram displays continuous grouped data with bars whose area equals the frequency, so the vertical axis is frequency density =frequencyclass width= \dfrac{\text{frequency}}{\text{class width}}. A box plot marks the five-number summary and makes outliers and skew visible at a glance.

Examples in context

Example 1. Comparing two box plots. Two classes sit the same test. Class A has median 5858 and IQR 1414; class B has median 6262 and IQR 2626. Class B scored higher on average but was far more spread out, so its results were less consistent. Box plots let you compare centre and spread in one picture.

Example 2. A biased frame. A council surveys residents using the electoral roll, which omits people under 1818 and the unregistered. Conclusions about "all residents" are biased because the sampling frame is incomplete. Identifying the gap between frame and population is a standard exam discussion point.

Try this

Q1. A factory takes every 50th item off a production line for testing. Name this sampling method. [1 mark]

  • Cue. Systematic sampling (every kkth unit from a start point).

Q2. A class of 30 has x=1500\sum x = 1500 for a test. Find the mean. [1 mark]

  • Cue. xˉ=150030=50\bar{x} = \dfrac{1500}{30} = 50.

Q3. A histogram class spans 1010 to 2020 with frequency 3535. Find the frequency density. [2 marks]

  • Cue. Class width is 1010, so frequency density =3510=3.5= \dfrac{35}{10} = 3.5.

Exam-style practice questions

Practice questions written in the style of WJEC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

WJEC AS style4 marksA school has 1200 students. A researcher wants a sample of 60. Describe how to obtain a stratified sample if there are 720 in the lower school and 480 in the upper school.
Show worked answer →

A stratified sample takes from each group in proportion to its size.

Sampling fraction: 601200=120\dfrac{60}{1200} = \dfrac{1}{20}.

Lower school: 720×120=36720 \times \dfrac{1}{20} = 36 students.
Upper school: 480×120=24480 \times \dfrac{1}{20} = 24 students.

Within each stratum, select the required number at random (for example by numbering the students and using random numbers). This gives 36+24=6036 + 24 = 60 in total.

Markers reward computing the sampling fraction, applying it to each stratum to get 3636 and 2424, and stating that the selection within each group is random. Forgetting the random selection within strata is a common omission.

WJEC AS style3 marksA histogram has a class of width 5 and frequency density 8. State what the area of this bar represents and find the frequency of the class.
Show worked answer →

In a histogram the area of a bar represents the frequency of that class.

Frequency == frequency density ×\times class width =8×5=40= 8 \times 5 = 40.

So the area of the bar (and the frequency of the class) is 4040.

Markers reward stating that area equals frequency, and multiplying frequency density by class width to get 4040. Reading the height as the frequency, rather than the frequency density, is the usual error in histogram questions.

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