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How are characteristics inherited, and how does evolution happen?

Monohybrid and dihybrid inheritance, sex linkage, the sources of variation, natural selection and speciation.

A focused answer to WJEC A-Level Biology Unit 4, covering monohybrid and dihybrid crosses, codominance and sex linkage, the sources of genetic variation, natural selection, and the formation of new species.

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  1. What this dot point is asking
  2. Monohybrid and dihybrid inheritance
  3. Codominance and sex linkage
  4. Variation, selection and speciation
  5. Examples in context
  6. Try this

What this dot point is asking

WJEC wants you to carry out and interpret monohybrid and dihybrid crosses, explain codominance and sex linkage, describe the sources of variation, and explain natural selection and speciation.

Monohybrid and dihybrid inheritance

When writing a cross, set out the parental phenotypes and genotypes, the gametes, the Punnett square of offspring genotypes, and finally the phenotype ratio. A test cross (crossing an unknown dominant with a homozygous recessive) reveals whether the dominant individual is homozygous or heterozygous.

Codominance and sex linkage

Variation, selection and speciation

Variation arises from mutation (the ultimate source of new alleles), the independent assortment and crossing over of meiosis, and random fertilisation. In natural selection, a selection pressure means individuals with favourable alleles survive and reproduce more, so the frequency of those alleles increases over generations. Speciation happens when two populations become reproductively isolated (often geographically) and accumulate genetic differences through selection until they can no longer interbreed to produce fertile offspring.

Examples in context

Example 1. Peppered moth industrial melanism. Before industrialisation the pale form of the peppered moth was camouflaged on lichen-covered trees; soot darkened the trees, so the dark allele became favourable and its frequency rose sharply. As pollution fell, the pale form recovered. This is the classic British example of natural selection changing allele frequency.

Example 2. ABO blood groups and codominance. The IA\text{I}^A and IB\text{I}^B alleles are codominant, so an IAIB\text{I}^A\text{I}^B person has blood group AB and makes both antigens, while IO\text{I}^O is recessive. This shows codominance and multiple alleles in one familiar human example examiners often use.

Try this

Q1. State the expected phenotype ratio from crossing two heterozygotes for a single gene. [1 mark]

  • Cue. 3:13:1 (dominant to recessive).

Q2. Explain why colour blindness is more common in males than females. [2 marks]

  • Cue. The allele is recessive and X-linked; males have only one X, so a single recessive allele is expressed, whereas females need two.

Q3. A dihybrid cross AaBb×AaBbAaBb \times AaBb produces 160160 offspring. Calculate how many are expected to show both recessive traits. [2 marks]

  • Cue. The double recessive fraction is 116\frac{1}{16}; 116×160=10\frac{1}{16} \times 160 = 10.

Exam-style practice questions

Practice questions written in the style of WJEC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

WJEC 20184 marksExplain how natural selection can lead to a change in the allele frequency of a population over time.
Show worked answer →

Mutation and meiosis create genetic variation, so individuals in a population differ in their alleles.

A selection pressure (such as a predator, disease or limited food) means individuals with a favourable allele are more likely to survive and reproduce.

These individuals pass on the favourable allele to their offspring, so its frequency increases in the population over many generations, while less favourable alleles become rarer.

Markers reward variation from mutation, differential survival and reproduction due to a selection pressure, and the resulting change in allele frequency.

WJEC 20215 marksIn pea plants, tall (T) is dominant to short (t) and round seed (R) is dominant to wrinkled (r). A plant heterozygous for both genes is crossed with another heterozygous for both. State the expected ratio of phenotypes and calculate how many of 320 offspring would be tall with round seeds.
Show worked answer →

A dihybrid cross of two double heterozygotes (TtRr x TtRr) gives the standard 9:3:3:1 ratio of phenotypes: 9 tall round, 3 tall wrinkled, 3 short round, 1 short wrinkled.

The fraction that are tall with round seeds is 916\frac{9}{16}.

Number of tall round offspring =916×320=9×20=180= \frac{9}{16} \times 320 = 9 \times 20 = 180.

Markers reward the 9:3:3:1 ratio, the 916\frac{9}{16} fraction, and the correct value of 180.

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