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How can we identify carbonate, halide and sulfate ions in a sample?

Tests for negative ions (anions): the carbonate test with acid, the halide test with silver nitrate, and the sulfate test with barium chloride, including the observations and ionic equations.

A focused answer to OCR Gateway GCSE Chemistry A topic C4.2 on tests for negative ions, covering the carbonate test using dilute acid, the halide test using silver nitrate, and the sulfate test using barium chloride, with observations and ionic equations.

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  1. What this dot point is asking
  2. Test for carbonate ions
  3. Test for halide ions
  4. Test for sulfate ions
  5. Why you acidify first
  6. A full analysis: combining the tests

What this dot point is asking

OCR wants you to describe the chemical tests for three common negative ions (anions): carbonate (using dilute acid), halide (chloride, bromide and iodide, using silver nitrate), and sulfate (using barium chloride), including the observations and the ionic equations. These complete the qualitative analysis toolkit alongside the cation and gas tests.

Test for carbonate ions

Test for halide ions

The ionic equation for chloride is Ag+(aq)+Clβˆ’(aq)β†’AgCl(s)\text{Ag}^+(\text{aq}) + \text{Cl}^-(\text{aq}) \rightarrow \text{AgCl}(\text{s}). The corresponding equations for bromide and iodide are Ag+(aq)+Brβˆ’(aq)β†’AgBr(s)\text{Ag}^+(\text{aq}) + \text{Br}^-(\text{aq}) \rightarrow \text{AgBr}(\text{s}) and Ag+(aq)+Iβˆ’(aq)β†’AgI(s)\text{Ag}^+(\text{aq}) + \text{I}^-(\text{aq}) \rightarrow \text{AgI}(\text{s}). The nitric acid is added first to remove carbonate ions, which would otherwise form a silver carbonate precipitate and give a false positive. These are precipitation reactions: two solutions are mixed and an insoluble solid (the silver halide) forms because the silver ion and the halide ion combine into a compound that does not dissolve.

Test for sulfate ions

Why you acidify first

Adding the acid first in the halide and sulfate tests removes carbonate ions, which would otherwise react to form their own precipitate and give a false positive. This makes the test specific to the halide or sulfate. The right acid matters: for the halide test you add nitric acid (not hydrochloric, which would add chloride ions and give a false positive), while for the sulfate test you add hydrochloric acid (not sulfuric, which would add sulfate ions).

A full analysis: combining the tests

In an exam you may be asked to fully identify an unknown salt by combining the cation and anion tests. The usual order is to identify the positive ion first (a flame test, or sodium hydroxide for a coloured precipitate), then identify the negative ion using the carbonate, halide and sulfate tests above. For example, a green flame plus a white precipitate with barium chloride after acidifying would indicate copper sulfate. Always describe both the reagent and the observed result, because the result is what earns the mark.

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20194 marksDescribe the chemical test for carbonate ions and the chemical test for sulfate ions, giving the reagent used and the positive result for each.
Show worked answer β†’

A C4.2 structured question. Reward: for carbonate ions, add a dilute acid (such as dilute hydrochloric acid) to the sample; if carbonate ions are present, the mixture fizzes and gives off carbon dioxide, which turns limewater cloudy. For sulfate ions, add dilute hydrochloric acid and then barium chloride solution; if sulfate ions are present, a white precipitate (of barium sulfate) forms. Markers credit dilute acid producing carbon dioxide (cloudy limewater) for carbonate, and barium chloride giving a white precipitate for sulfate. A common slip is to forget to acidify first, or to mix up the reagents.

OCR 20224 marksA solution may contain chloride, bromide or iodide ions. Describe the test using silver nitrate solution, give the colour of the precipitate for each halide, and write the ionic equation for the formation of the chloride precipitate.
Show worked answer β†’

A Higher tier halide test question. Reward: add dilute nitric acid, then silver nitrate solution; a precipitate of the silver halide forms. The colours are: chloride gives a white precipitate, bromide gives a cream precipitate, and iodide gives a yellow precipitate. The ionic equation for the chloride is Ag+(aq)+Clβˆ’(aq)β†’AgCl(s)\text{Ag}^+(\text{aq}) + \text{Cl}^-(\text{aq}) \rightarrow \text{AgCl}(\text{s}). Markers credit silver nitrate (with nitric acid) as the reagent, the three precipitate colours (white chloride, cream bromide, yellow iodide), and the correct balanced ionic equation. A common error is to mix up the cream and yellow colours, or to leave out the state symbols and charges in the equation.

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