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How do alleles pass from parents to offspring, and how do we predict the ratios in a genetic cross?

Alleles, dominant and recessive, genotype and phenotype, homozygous and heterozygous, monohybrid crosses and Punnett squares, the inheritance of sex by the X and Y chromosomes, and single-gene inherited disorders such as cystic fibrosis and polydactyly.

A focused answer to the OCR Gateway GCSE Biology A topic B5 on genetic inheritance, covering alleles, dominant and recessive, genotype and phenotype, homozygous and heterozygous, monohybrid crosses with Punnett squares, the inheritance of sex, and single-gene inherited disorders such as cystic fibrosis and polydactyly.

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  1. What this dot point is asking
  2. The language of inheritance
  3. Monohybrid crosses and Punnett squares
  4. Inheritance of sex
  5. Single-gene inherited disorders

What this dot point is asking

OCR wants you to define alleles, genotype, phenotype, homozygous and heterozygous, complete monohybrid crosses using Punnett squares to predict genotypes and ratios, explain how the X and Y chromosomes determine sex, and explain single-gene inherited disorders.

The language of inheritance

Two more terms you must use precisely:

  • Homozygous: the two alleles are the same (for example BB or bb).
  • Heterozygous: the two alleles are different (for example Bb).

By convention a dominant allele is written as a capital letter and the matching recessive allele as the same letter in lower case (B and b). An organism inherits one allele of each gene from each parent, one on each chromosome of a pair.

Monohybrid crosses and Punnett squares

A monohybrid cross follows the inheritance of a single gene. A Punnett square is the tool that predicts the genotypes and the ratio of offspring.

To use one: write one parent's possible gametes along the top, the other parent's down the side, and fill each box by combining the alleles.

Ratios are predictions of probability, not guarantees. A 3:1 ratio means each offspring has a 34\dfrac{3}{4} chance of the dominant phenotype, not that exactly three in every four will show it. With small numbers the actual results often differ from the predicted ratio.

Inheritance of sex

The sex chromosomes are the 23rd pair in humans. Females are XX and males are XY.

  • All egg cells carry an X chromosome.
  • Sperm carry either an X or a Y, in roughly equal numbers.

So the sperm determines the sex of the baby: an X sperm gives XX (female), a Y sperm gives XY (male). A Punnett square of XX ×\times XY gives XX, XX, XY, XY, a 1 : 1 ratio, which is why about half of babies are each sex.

Single-gene inherited disorders

Some disorders are caused by a fault in a single gene, and Punnett squares are used to work out the chance of inheriting them.

  • Cystic fibrosis is caused by a recessive allele, so a person needs two recessive alleles (ff) to have the disorder. Heterozygous people (Ff) are healthy carriers who can still pass the allele on.
  • Polydactyly (extra fingers or toes) is caused by a dominant allele, so just one copy is enough to cause it, and an affected person usually has an affected parent.

Knowing whether the allele is dominant or recessive tells you how the disorder runs through a family tree and lets you predict the probability for future children.

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20184 marksCystic fibrosis is caused by a recessive allele f. A man who is a carrier (Ff) has children with a woman who is a carrier (Ff). Draw a Punnett square for this cross and state the probability that a child will have cystic fibrosis.
Show worked answer →

A B5 genetic-cross calculation.

Method: draw a 2×22 \times 2 Punnett square with the man's gametes (F and f) along the top and the woman's gametes (F and f) down the side. Filling in gives the four offspring genotypes: FF, Ff, Ff and ff.

Cystic fibrosis only appears when both alleles are recessive (ff), which is one of the four boxes. So the probability that a child has cystic fibrosis is 14\dfrac{1}{4}, or 25%25\%. Markers award the correct gametes, the four genotypes, and the probability of 14\dfrac{1}{4}. A common slip is to forget that the two Ff children are carriers who do not have the disorder.

OCR 20213 marksExplain how the sex of a human baby is determined at fertilisation, using the X and Y chromosomes, and state why roughly half of babies are male and half female.
Show worked answer →

A short B5 question on sex determination.

Females have two X chromosomes (XX) and males have one X and one Y (XY). All egg cells carry an X chromosome. Sperm carry either an X or a Y, in equal numbers. If an X sperm fertilises the egg, the baby is XX (female); if a Y sperm fertilises the egg, the baby is XY (male).

Because half the sperm carry X and half carry Y, there is a roughly 50%50\% chance of each, so about half of babies are male and half female. Reward the XX and XY genotypes, that the sperm determines the sex, and the 1:1 ratio. A Punnett square of XX by XY showing XX, XX, XY, XY gains full credit.

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