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How do you expand brackets, factorise expressions and change the subject of a formula?

Simplify and manipulate algebraic expressions: collect like terms, expand single and double brackets, factorise (common factors, quadratics and the difference of two squares), and rearrange formulae to change the subject.

A focused answer to the Eduqas GCSE Mathematics algebra content on manipulating expressions, covering collecting like terms, expanding single and double brackets, factorising, and changing the subject of a formula.

Generated by Claude Opus 4.811 min answer

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  1. What this dot point is asking
  2. Simplifying and the index laws
  3. Expanding brackets
  4. Factorising
  5. Changing the subject
  6. Why manipulation matters

What this dot point is asking

The Eduqas algebra content opens with manipulation: the toolkit of simplifying, expanding, factorising and rearranging that every later topic depends on. You must collect like terms, expand single and double brackets, factorise by taking out common factors and by reversing a double expansion (including the difference of two squares), and change the subject of a formula. Manipulation appears on both components and at both tiers, and weak manipulation leaks marks across geometry, ratio and the rest of algebra, so fluency here is the single highest-value investment in the course.

Simplifying and the index laws

Collecting like terms is adding the coefficients of terms with identical letters and powers: 4a+7ba+2b=3a+9b4a + 7b - a + 2b = 3a + 9b. Only like terms combine, so 3x3x and 3x23x^2 stay separate. When you multiply algebraic terms, multiply the numbers and add the indices.

Expanding brackets

To expand a single bracket, multiply each inside term by the term outside: 3(2x5)=6x153(2x - 5) = 6x - 15. For two brackets, multiply every term in the first by every term in the second. FOIL (First, Outer, Inner, Last) is a way to track the four products.

So (x+4)(x2)=x22x+4x8=x2+2x8(x + 4)(x - 2) = x^2 - 2x + 4x - 8 = x^2 + 2x - 8. Squaring a bracket is a double expansion, not just squaring each term: (x+3)2=(x+3)(x+3)=x2+6x+9(x + 3)^2 = (x+3)(x+3) = x^2 + 6x + 9, where the 6x6x middle term is the one most often dropped.

Factorising

Factorising is the reverse of expanding. Always look first for a common factor in every term.

For x2+7x+12x^2 + 7x + 12, two numbers multiply to 1212 and add to 77: those are 33 and 44, so it factorises as (x+3)(x+4)(x + 3)(x + 4). A special case is the difference of two squares, which has no middle term: x225=(x+5)(x5)x^2 - 25 = (x + 5)(x - 5) and 9x216=(3x+4)(3x4)9x^2 - 16 = (3x + 4)(3x - 4).

Changing the subject

Rearranging a formula uses the same balancing as solving an equation: do the same operation to both sides, undoing operations in reverse order.

When the new subject appears more than once, gather its terms on one side, factorise it out, then divide. For example to make xx the subject of ax=bx+cax = bx + c, write axbx=cax - bx = c, factorise to x(ab)=cx(a - b) = c, and divide to get x=cabx = \dfrac{c}{a - b}. This factorise-then-divide pattern is the Higher-tier twist examiners use to separate strong candidates, so practise spotting when the subject is hidden inside two or more terms.

Why manipulation matters

Every algebraic technique downstream depends on this one. Solving equations needs expanding and rearranging; the quadratic formula needs a quadratic in standard form; straight-line and proportion work needs the subject changed; even geometry proofs are written in manipulated algebra. Because Eduqas weights reasoning (AO2) and problem solving (AO3) at half the marks, questions often hide the manipulation inside a context, so recognising when to factorise or rearrange is as important as the mechanics.

Exam-style practice questions

Practice questions written in the style of WJEC Eduqas exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Eduqas 20193 marksExpand and simplify (2x+3)(x4)(2x + 3)(x - 4). (Foundation, Component 1, non-calculator.)
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Multiply every term in the first bracket by every term in the second (FOIL).

(2x)(x)=2x2(2x)(x) = 2x^2, (2x)(4)=8x(2x)(-4) = -8x, (3)(x)=3x(3)(x) = 3x, (3)(4)=12(3)(-4) = -12.

Collect the like terms 8x+3x=5x-8x + 3x = -5x, giving 2x25x122x^2 - 5x - 12.

Markers award a mark for a correct expansion of all four products, a mark for collecting the middle terms, and a mark for the fully simplified answer. Forgetting the 12-12 or mishandling the sign of 8x-8x are the usual slips.

Eduqas 20213 marksMake rr the subject of the formula A=πr2A = \pi r^2. (Higher, Component 2, calculator.)
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Isolate r2r^2 first by dividing both sides by π\pi: Aπ=r2\dfrac{A}{\pi} = r^2.

Then take the positive square root of both sides: r=Aπr = \sqrt{\dfrac{A}{\pi}}.

Markers give a mark for dividing by π\pi, a mark for the square root, and a mark for the correct final form. A common error is to square root only AA, writing r=Aπr = \dfrac{\sqrt{A}}{\pi}, which is wrong because the whole right-hand side must be rooted.

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