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How do you measure and compare the spread of a data set?

Range, quartiles, interquartile range, percentiles, interpercentile and interdecile range; choosing an appropriate measure of spread; pairing a measure of spread with a measure of central tendency.

A focused answer to Edexcel GCSE Statistics on measures of spread, covering range, quartiles, interquartile range, percentiles, interpercentile and interdecile range, choosing an appropriate measure, and pairing a measure of spread with the right average.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The range
  3. Quartiles and the interquartile range
  4. Percentiles, interpercentile and interdecile range
  5. Choosing and pairing measures

What this dot point is asking

Edexcel codes 2c.01, 2c.04 and 2c.05 require you to calculate measures of spread: the range, quartiles, the interquartile range (IQR), percentiles, and (Higher tier) the interpercentile and interdecile range. You must choose an appropriate measure for a context and pair a measure of spread with a suitable measure of central tendency. (Standard deviation has its own page.) Spread questions appear constantly because every comparison of two data sets needs one.

The range

The range is quick to find and uses the full extent of the data, but it depends entirely on the two most extreme values, so a single outlier can make it misleading. It is best used as a rough measure or alongside a more robust one.

Quartiles and the interquartile range

The quartiles divide ordered data into four equal parts: Q1Q_1 (lower quartile) has a quarter of the data below it, Q2Q_2 is the median, and Q3Q_3 (upper quartile) has three quarters below it. For a small ordered list of nn values, locate Q1Q_1 at position n+14\frac{n+1}{4} and Q3Q_3 at 3(n+1)4\frac{3(n+1)}{4}.

Because it discards the lowest and highest quarters, the IQR is resistant to outliers, which is why Edexcel pairs it with the median (not the mean). Using the mean with the IQR is explicitly flagged as an inappropriate pairing.

Percentiles, interpercentile and interdecile range

Percentiles split ordered data into 100100 equal parts: the ppth percentile has p%p\% of the data below it (so Q1Q_1 is the 2525th percentile and the median is the 5050th). Deciles split it into ten parts. Higher tier measures of spread built from these:

  • The interpercentile range between two percentiles, for example the 1010th to 9090th interpercentile range =P90P10= P_{90} - P_{10}, the spread of the middle 80%80\%.
  • The interdecile range =D9D1= D_9 - D_1 (the 9090th minus the 1010th percentile), also the middle 80%80\%.

These exclude the most extreme 10%10\% at each end, giving a robust picture of spread while keeping more of the data than the IQR.

Choosing and pairing measures

Match the measure of spread to the measure of central tendency:

  • Median with IQR (or interpercentile / interdecile range) for skewed data or data with outliers.
  • Mean with standard deviation for roughly symmetric data (see the standard deviation page).

A correct pairing is examined directly, and quoting an average without an appropriate measure of spread loses marks in comparison questions.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 1ST0 20204 marksThe waiting times, in minutes, of 1111 patients in order are: 2,4,5,7,8,10,12,15,18,22,302, 4, 5, 7, 8, 10, 12, 15, 18, 22, 30. Find (a) the range, (b) the median, (c) the interquartile range.
Show worked answer →

(a) Range =302=28= 30 - 2 = 28 minutes.

(b) With 1111 values the median is the 11+12=6\frac{11+1}{2} = 6th value =10= 10 minutes.

(c) The lower quartile is the 11+14=3\frac{11+1}{4} = 3rd value =5= 5; the upper quartile is the 3(11+1)4=9\frac{3(11+1)}{4} = 9th value =18= 18. So IQR=185=13IQR = 18 - 5 = 13 minutes.

Markers reward the range, the median by position, and the IQR as UQLQUQ - LQ with the quartiles correctly located.

Edexcel 1ST0 20213 marksA data set of test marks has a lower quartile of 4242, an upper quartile of 5858, a 1010th percentile of 3030 and a 9090th percentile of 7474. (a) Work out the interquartile range. (b) Work out the 1010th to 9090th interpercentile range, and explain what it represents.
Show worked answer →

(a) IQR=UQLQ=5842=16IQR = UQ - LQ = 58 - 42 = 16 marks.

(b) The 1010th to 9090th interpercentile range =7430=44= 74 - 30 = 44 marks. It is the spread of the middle 80%80\% of the data (it ignores the lowest 10%10\% and the highest 10%10\%), so it measures spread while excluding the most extreme values.

Markers reward the IQR, the interpercentile range, and the explanation that it covers the middle 80%80\%.

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