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How do you find a resultant force, and how can a single force be resolved into components?

Resolving and resultant forces: combining forces into a resultant, using scale vector diagrams, and resolving a single force into perpendicular components.

A focused answer to Edexcel GCSE Physics 9.3, covering how to find the resultant of forces, adding forces along a line, using scale vector diagrams (the parallelogram or tip-to-tail method) for forces at an angle, and resolving a single force into perpendicular components.

Generated by Claude Opus 4.89 min answer

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  1. What this dot point is asking
  2. The resultant force
  3. Forces at an angle: scale vector diagrams
  4. Resolving a force into components
  5. How Edexcel examines this
  6. Try this

What this dot point is asking

Edexcel statement 9.3 wants you to use vector diagrams to illustrate the resolution of forces, the addition of forces to find a resultant, and the conditions for equilibrium. You should be able to combine forces along a line and at an angle, and resolve a single force into two perpendicular components.

The resultant force

Finding the resultant is the first step in almost any forces problem, because it is the resultant that goes into Newton's second law (F=maF = ma). For forces acting along the same straight line, you simply add or subtract: forces in the same direction add, and forces in opposite directions subtract, with the resultant pointing the way of the larger force.

Forces at an angle: scale vector diagrams

The tip-to-tail (or parallelogram) method turns vector addition into a drawing. Choosing a sensible scale (for example 1 cm=1 N1\,\text{cm} = 1\,\text{N}) and drawing accurately are the keys to marks. For two perpendicular forces, you can also calculate the size of the resultant using Pythagoras, F12+F22\sqrt{F_1^2 + F_2^2}, which is quicker and exact.

Resolving a force into components

Resolving is useful when a force acts at an awkward angle, for example a sledge pulled by a rope at an angle to the ground. The pull can be resolved into a horizontal component (which moves the sledge along) and a vertical component (which tends to lift it). At GCSE you usually resolve using a scale diagram by drawing the perpendicular components that add tip-to-tail to give the original force.

How Edexcel examines this

This dot point is examined on both tiers. Forces along a line are a reliable two or three mark calculation, where the mark scheme rewards adding same-direction forces and subtracting opposite ones and stating the direction of the resultant; the classic error is adding forces that oppose each other. Forces at an angle are examined with a scale vector diagram: you are asked to draw the forces tip-to-tail to a stated scale, identify the resultant as the closing arrow, and measure its size and direction. For perpendicular forces, examiners accept (and often expect) Pythagoras for the size and a protractor measurement for the direction. Resolving a single force into perpendicular components appears as a diagram task, rewarding components that are at right angles and add back to the original. Accuracy in drawing, a clearly stated scale, and correct use of subtraction for opposing forces are the main mark-earners, so set diagrams out carefully and label the resultant.

Try this

Q1. Two forces of 9 N9\,\text{N} and 4 N4\,\text{N} act in opposite directions along a line. Calculate the resultant. [2 marks]

  • Cue. 9βˆ’4=5 N9 - 4 = 5\,\text{N} in the direction of the 9 N9\,\text{N} force.

Q2. State what is meant by the resultant force. [1 mark]

  • Cue. The single force with the same effect as all the forces combined.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20203 marksTwo forces act on an object in the same straight line: 12 N12\,\text{N} to the right and 5 N5\,\text{N} to the left. Calculate the resultant force, and state its direction.
Show worked answer β†’

For forces along the same line, subtract when they act in opposite directions: resultant =12βˆ’5=7 N= 12 - 5 = 7\,\text{N} (2 marks). The resultant acts to the right (the direction of the larger force) (1 mark). Markers reward subtracting the opposing forces and stating the direction of the resultant. Adding the two forces (getting 17 N17\,\text{N}) is the usual error when they act in opposite directions.

Edexcel 20224 marksTwo forces act on a point at right angles to each other: 3 N3\,\text{N} to the east and 4 N4\,\text{N} to the north. Describe how to find the resultant force using a scale vector diagram, and state the size of the resultant.
Show worked answer β†’

Draw the two forces tip-to-tail (or as two sides of a rectangle) to a chosen scale, for example 1 cm1\,\text{cm} to 1 N1\,\text{N} (1 mark). The resultant is the arrow from the start of the first force to the end of the second (the diagonal of the rectangle), and its length is measured and converted back using the scale (1 mark). For perpendicular forces the size can also be found using Pythagoras: 32+42=9+16=25=5 N\sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5\,\text{N} (2 marks). Markers reward drawing the forces to scale tip-to-tail, identifying the resultant as the closing arrow, and a resultant of 5 N5\,\text{N}. The direction can be measured with a protractor.

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