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How do you find the nth term of linear and quadratic sequences, and recognise special sequences?

Sequences: generating terms, finding the nth term of a linear (arithmetic) sequence and a quadratic sequence (Higher tier), and recognising geometric, triangular, square, cube and Fibonacci sequences.

A focused answer to the Edexcel GCSE Mathematics algebra content on sequences, covering generating terms, finding the nth term of linear and quadratic sequences, and recognising special sequences such as geometric, triangular and Fibonacci.

Generated by Claude Opus 4.89 min answer

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  1. What this dot point is asking
  2. Linear (arithmetic) sequences
  3. Quadratic sequences (Higher)
  4. Special sequences to recognise
  5. Geometric sequences
  6. Using the nth term
  7. Try this

What this dot point is asking

A sequence is an ordered list of numbers that follow a rule. Edexcel expects you to generate terms from a rule, find the nth term of a linear (arithmetic) sequence, find the nth term of a quadratic sequence at Higher tier, and recognise special sequences such as geometric, triangular, square, cube and Fibonacci. The nth term is powerful because it lets you find any term, however far along, without listing them all.

Linear (arithmetic) sequences

A linear sequence goes up or down by the same amount each time. That constant is the first difference.

For 7,12,17,227, 12, 17, 22, the difference is 55, so the nth term is 5n+c5n + c. Since 5×1=55 \times 1 = 5 and the first term is 77, you add 22, giving 5n+25n + 2. A negative difference works the same way: for 20,17,14,1120, 17, 14, 11 the nth term is 3n+23-3n + 23.

The nth term lets you answer "is 103103 a term?" Set 5n+2=1035n + 2 = 103, solve to get n=20.2n = 20.2; because nn is not a whole number, 103103 is not in the sequence.

Quadratic sequences (Higher)

A quadratic sequence has a first difference that itself changes, but the second difference is constant.

Special sequences to recognise

Some sequences appear so often that you should know them on sight: square numbers 1,4,9,16,1, 4, 9, 16, \ldots (nth term n2n^2); cube numbers 1,8,27,64,1, 8, 27, 64, \ldots (nth term n3n^3); triangular numbers 1,3,6,10,15,1, 3, 6, 10, 15, \ldots (nth term n(n+1)2\tfrac{n(n+1)}{2}); and the Fibonacci sequence 1,1,2,3,5,8,1, 1, 2, 3, 5, 8, \ldots, where each term is the sum of the two before it.

Geometric sequences

A geometric sequence multiplies by a constant ratio rather than adding. For 2,6,18,542, 6, 18, 54 the ratio is 33, so each term is three times the previous one. Geometric sequences can include fractional or negative ratios, such as 80,40,20,1080, 40, 20, 10 with ratio 12\tfrac{1}{2}, and surd ratios appear at Higher tier. A negative ratio makes the terms alternate in sign, as in 3,6,12,243, -6, 12, -24 with ratio 2-2.

Using the nth term

The nth term is most powerful for answering questions without listing terms. To find the 5050th term of 5n+25n + 2, substitute n=50n = 50: 5(50)+2=2525(50) + 2 = 252. To test whether a value belongs to a sequence, set the nth term equal to it and solve: for 5n+2=875n + 2 = 87, you get n=17n = 17, a whole number, so 8787 is the 1717th term; but 5n+2=905n + 2 = 90 gives n=17.6n = 17.6, which is not a whole number, so 9090 is not in the sequence. This "is it a term?" reasoning is a frequent exam question and is only quick once you have the nth term.

Try this

Q1. Find the nth term of the linear sequence 9,13,17,219, 13, 17, 21. [2 marks]

  • Cue. The difference is 44, so it starts with 4n4n. Since 4×1=44 \times 1 = 4 and the first term is 99, add 55: the nth term is 4n+54n + 5.

Q2. Find the 1010th term of a sequence with nth term n21n^2 - 1. [1 mark]

  • Cue. Substitute n=10n = 10: 1021=9910^2 - 1 = 99.

Exam-style practice questions

Practice questions written in the style of Pearson Edexcel exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Edexcel 20192 marksHere are the first four terms of a sequence: 5,8,11,145, 8, 11, 14. Find an expression, in terms of nn, for the nnth term. (Paper 1, non-calculator.)
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The sequence goes up by 33 each time, so the common difference is 33 and the nnth term starts with 3n3n.

Compare 3n3n with the sequence: 3n3n gives 3,6,9,123, 6, 9, 12, which is 22 less than the sequence each time.

So the nnth term is 3n+23n + 2.

Markers award a mark for 3n3n (the correct multiple) and a mark for the full expression 3n+23n + 2. Writing n+3n + 3 (using the difference as a "plus" each term) is the classic mistake.

Edexcel 20213 marksFind the nnth term of the quadratic sequence 3,8,15,24,353, 8, 15, 24, 35. (Higher tier, Paper 2, calculator.)
Show worked answer →

Find the second difference. First differences: 5,7,9,115, 7, 9, 11. Second differences: 2,2,22, 2, 2.

The second difference is 22, so the n2n^2 coefficient is 22=1\tfrac{2}{2} = 1; the sequence starts with n2n^2.

Subtract n2n^2 (1,4,9,16,251, 4, 9, 16, 25) from the sequence: 2,4,6,8,102, 4, 6, 8, 10. This linear part has nnth term 2n2n.

So the nnth term is n2+2nn^2 + 2n.

Markers award a mark for the n2n^2 coefficient, a mark for the linear part, and a mark for the full expression. Halving the second difference is the step most often missed.

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