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How do you calculate and compare averages and measures of spread?

Finding the mean, median, mode and range, averages from frequency tables, and the median and interquartile range from grouped data at Higher tier.

A focused answer to the AQA GCSE Mathematics statistics content on averages and spread, covering the mean, median, mode and range, averages from frequency tables, and the median and interquartile range from grouped data at Higher tier.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The four basic measures
  3. Averages from a frequency table
  4. Grouped data at Higher tier
  5. Interquartile range and comparison
  6. Choosing the right average
  7. Finding the modal class and the effect of changes

What this dot point is asking

AQA wants you to calculate the mean, median, mode and range, find averages from frequency tables, and at Higher tier estimate the mean and find the median and interquartile range from grouped data. Beyond the calculations, AQA wants you to compare two data sets using an average and a measure of spread together, which is where the interpretation marks lie.

The four basic measures

For the data 3,5,5,8,93, 5, 5, 8, 9: the mean is 305=6\dfrac{30}{5} = 6, the median is the third value 55, the mode is 55, and the range is 93=69 - 3 = 6. With an even number of values, the median is the mean of the two middle values. The mean uses every value (so it is affected by outliers), the median is resistant to outliers, and the mode is the only average usable for non-numerical data.

Averages from a frequency table

When data is given as values with frequencies, the mean is the sum of each value times its frequency, divided by the total frequency. Add a "value times frequency" column, total it, and divide by the total of the frequency column. The mode is the value with the highest frequency, and the median is found by counting through the cumulative frequencies to the middle position.

Grouped data at Higher tier

When data is grouped into class intervals, individual values are lost, so the mean can only be estimated using the midpoint of each class.

Interquartile range and comparison

The interquartile range (IQR) is the upper quartile minus the lower quartile, the spread of the middle half of the data. For ordered data the lower quartile is the value a quarter of the way through and the upper quartile three quarters through; the median is the halfway value. The IQR ignores the extreme values, so it is more reliable than the range when outliers are present. When comparing two data sets, quote one average (usually the median or mean) and one spread (range or IQR) and interpret both in context.

Choosing the right average

Part of the skill is knowing which average suits the data. The mean uses every value and is best for symmetric data with no extreme outliers, but a single very large value drags it up, making it misleading. The median ignores the actual size of extreme values and so represents skewed data, such as house prices or incomes, more fairly. The mode is the only average that works for categorical data (the most popular colour) and is useful when the most common value matters, such as the most frequent shoe size to stock. Exam questions often ask which average is most appropriate and why, so a one-line justification is worth rehearsing.

Finding the modal class and the effect of changes

For grouped data you cannot give a single mode; instead you state the modal class, the interval with the highest frequency. A subtle exam point is how changes to the data affect the averages: adding a constant to every value raises the mean, median and mode by that constant but leaves the range and IQR unchanged, while an extra outlier shifts the mean noticeably but the median barely at all. Reasoning about these effects, rather than just computing, is increasingly common in the reformed specification.

Exam-style practice questions

Practice questions written in the style of AQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AQA 20183 marksSeven students score 4,7,7,8,9,11,124, 7, 7, 8, 9, 11, 12 in a test. Find the median and the range. (Foundation tier, Paper 1, non-calculator.)
Show worked answer →

The data is already in order. With seven values, the median is the fourth value: 88.

The range is the largest minus the smallest: 124=812 - 4 = 8.

Markers award a mark for ordering or identifying the middle, a mark for the median, and a mark for the range. Confusing range with the median, or averaging the two middle values when there is an odd count, are the usual errors.

AQA 20214 marksA frequency table records the number of goals scored in 2020 matches: 00 goals in 55 matches, 11 goal in 88 matches, 22 goals in 44 matches, 33 goals in 33 matches. Work out the mean number of goals per match. (Higher tier, Paper 2, calculator.)
Show worked answer →

Multiply each value by its frequency and sum: (0×5)+(1×8)+(2×4)+(3×3)=0+8+8+9=25(0 \times 5) + (1 \times 8) + (2 \times 4) + (3 \times 3) = 0 + 8 + 8 + 9 = 25.

Divide by the total frequency: 2520=1.25\dfrac{25}{20} = 1.25 goals per match.

Markers reward the products, the total, and the division by 2020. Dividing by the number of rows (44) instead of the total frequency is the classic error.

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