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How do you recognise and solve direct and inverse proportion problems?

Recognising direct and inverse proportion, setting up and using proportion equations with a constant, and interpreting their graphs.

A focused answer to the AQA GCSE Mathematics content on direct and inverse proportion, covering recognising each type, setting up and using proportion equations with a constant of proportionality, and interpreting their graphs.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Recognising the type
  3. Setting up the proportion equation
  4. Interpreting the graphs
  5. Worded problems
  6. The constant of proportionality has meaning
  7. Combining proportion with graphs

What this dot point is asking

AQA wants you to recognise whether a relationship is direct or inverse proportion, set up the proportion equation with a constant of proportionality kk, use it to find unknown values, and interpret the graphs of each type. At Higher tier this extends to proportion involving squares, cubes and roots. The skill is finding kk from a given pair, then using the resulting formula.

Recognising the type

Direct proportion: doubling one quantity doubles the other, and their ratio is constant. Examples are cost and quantity, or distance and time at constant speed. Inverse proportion: doubling one quantity halves the other, and their product is constant. Examples are speed and time for a fixed journey, or the number of workers and the time to finish a job. Reading the words carefully decides which model applies.

Setting up the proportion equation

The method is always the same three steps: write the proportion equation with kk, substitute a known pair to find kk, then use the completed formula. The symbol \propto means "is proportional to", so "yy is proportional to x3x^3" becomes y=kx3y = kx^3.

Interpreting the graphs

The graph of y=kxy = kx is a straight line through the origin with gradient kk; a straight line not through the origin is not direct proportion. The graph of y=kxy = \dfrac{k}{x} is a reciprocal curve with two branches that approach but never touch the axes. A square-law relationship y=kx2y = kx^2 gives a parabola through the origin. Recognising the shape from a graph, or matching a graph to its equation, is a common short question.

Worded problems

Many proportion questions are dressed as recipes, currency, fuel use or physics. Decide direct or inverse from the wording, find kk from the data, and answer with the formula. If a quantity is shared inversely, more parts means a smaller share each, so the product of share and number stays fixed.

The constant of proportionality has meaning

The constant kk is not just an algebraic device; it often has a real interpretation. In cost=k×quantity\text{cost} = k \times \text{quantity}, the constant kk is the price per item. In distance=k×time\text{distance} = k \times \text{time}, the constant is the speed. When you find kk from given data, it pays to say what it represents, because a question may ask you to interpret it. A larger kk in a direct relationship means a steeper line, so the dependent quantity grows faster for each unit of the other.

Combining proportion with graphs

The graph of a relationship reveals the model at a glance, which examiners exploit. A straight line through the origin is direct proportion, and its gradient is kk. A curve that drops steeply then levels toward the axes is inverse proportion. A parabola through the origin signals a square law, y=kx2y = kx^2. Being asked to match a sketch to one of these models, or to explain why a given graph cannot represent direct proportion (because it does not pass through the origin), is a recurring style of question that rewards knowing each shape.

Exam-style practice questions

Practice questions written in the style of AQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AQA 20194 marksyy is directly proportional to xx. When x=6x = 6, y=15y = 15. Find a formula for yy in terms of xx, and use it to find yy when x=10x = 10. (Higher tier, Paper 2, calculator.)
Show worked answer →

Direct proportion means y=kxy = kx. Substitute x=6x = 6, y=15y = 15: 15=6k15 = 6k, so k=2.5k = 2.5.

The formula is y=2.5xy = 2.5x.

When x=10x = 10: y=2.5×10=25y = 2.5 \times 10 = 25.

Markers reward writing y=kxy = kx, finding kk, the formula, and the final value. Skipping the formula and using a single ratio loses method marks when the question demands an equation.

AQA 20214 marksPP is inversely proportional to the square of QQ. When Q=2Q = 2, P=9P = 9. Find PP when Q=3Q = 3. (Higher tier, Paper 1, non-calculator.)
Show worked answer →

Inverse proportion to the square means P=kQ2P = \dfrac{k}{Q^2}. Substitute Q=2Q = 2, P=9P = 9: 9=k49 = \dfrac{k}{4}, so k=36k = 36.

The formula is P=36Q2P = \dfrac{36}{Q^2}.

When Q=3Q = 3: P=369=4P = \dfrac{36}{9} = 4.

Markers reward the correct model, finding kk, and the final value. Using kQ\dfrac{k}{Q} instead of kQ2\dfrac{k}{Q^2} is the common error.

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