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Why is mass conserved in reactions, and what is the mole?

Conservation of mass and balanced symbol equations; relative formula mass; the mole and the Avogadro constant; apparent changes in mass in reactions involving gases.

A focused answer to AQA GCSE Chemistry 4.3.1 and 4.3.2, covering conservation of mass and balanced equations, relative formula mass, the mole and the Avogadro constant, and why mass can appear to change in reactions involving gases.

Generated by Claude Opus 4.89 min answer

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  1. What this dot point is asking
  2. Conservation of mass
  3. Relative formula mass
  4. The mole and the Avogadro constant
  5. Apparent changes in mass
  6. Try this

What this dot point is asking

AQA wants you to state and explain conservation of mass, balance symbol equations, calculate relative formula mass, define the mole and the Avogadro constant, and explain why mass can appear to increase or decrease in reactions that involve a gas. These ideas are the foundation of the whole quantitative chemistry topic: every reacting-mass and yield calculation relies on the fact that mass is conserved and that a balanced equation conserves atoms.

Conservation of mass

A balanced equation has the same number of each type of atom on both sides. You balance only by changing the big numbers in front of formulae, never the small numbers inside them, because changing a subscript would change the substance itself. For example, in CH4+2O2CO2+2H2OCH_4 + 2O_2 \rightarrow CO_2 + 2H_2O there is one carbon, four hydrogens and four oxygens on each side. A useful check is to count each element on both sides before trusting the balancing.

Relative formula mass

The relative formula mass (MrM_r) of a compound is the sum of the relative atomic masses (ArA_r) of all the atoms in its formula. For example, for CO2CO_2, Mr=12+(2×16)=44M_r = 12 + (2 \times 16) = 44, and for calcium hydroxide Ca(OH)2Ca(OH)_2, Mr=40+2×(16+1)=74M_r = 40 + 2 \times (16 + 1) = 74 (note the bracket multiplies both the oxygen and the hydrogen).

The mole and the Avogadro constant

So one mole of carbon (12) has a mass of 1212 g, and one mole of water (18) has a mass of 1818 g. The mole is what lets chemists count particles by weighing: because reacting particles combine in fixed whole-number ratios, measuring amount in moles (rather than grams) is what makes the balancing numbers directly useful.

Apparent changes in mass

Mass can appear to change in a reaction in an unsealed container:

  • If a gas is given off (for example CO2CO_2 in a thermal decomposition) and escapes, the mass of the remaining solid appears to decrease.
  • If a gas from the air is taken in (for example oxygen when a metal burns), the mass of the solid appears to increase.

The total mass is still conserved if you include the gas. In a sealed container the balance reading would not change at all, which is the clearest demonstration that no mass is truly lost or gained.

Try this

Q1. Calculate the relative formula mass of H2OH_2O (ArA_r: H = 1, O = 16). [1 mark]

  • Cue. (2×1)+16=18(2 \times 1) + 16 = 18.

Q2. Explain why the mass of a metal increases when it burns in air in an open dish. [2 marks]

  • Cue. It combines with oxygen from the air, so the oxygen's mass is added to the product.

Q3. Calculate the relative formula mass of magnesium nitrate, Mg(NO3)2Mg(NO_3)_2 (ArA_r: Mg = 24, N = 14, O = 16). [2 marks]

  • Cue. 24+2×(14+3×16)=24+2×62=14824 + 2 \times (14 + 3 \times 16) = 24 + 2 \times 62 = 148.

Exam-style practice questions

Practice questions written in the style of AQA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AQA 20184 marksA student heats 5.05.0 g of copper in an open crucible. The copper reacts with oxygen to form copper oxide, 2Cu+O22CuO2Cu + O_2 \rightarrow 2CuO. Explain why the mass of solid in the crucible increases, and state the law that still applies. Then calculate the mass of oxygen that reacts if the final mass of copper oxide is 6.36.3 g.
Show worked answer →

A 4-mark Paper 1 question combining an explanation with a conservation-of-mass calculation.

Explanation (2 marks): the copper combines with oxygen from the air; the oxygen atoms are now part of the solid copper oxide, so the solid gains the mass of the oxygen. The law of conservation of mass still applies because no atoms are created or destroyed, the system just gains oxygen from the air.

Calculation (2 marks): mass of oxygen =mass of productmass of copper=6.35.0=1.3= \text{mass of product} - \text{mass of copper} = 6.3 - 5.0 = 1.3 g.

Markers reward the idea that oxygen mass is added, not created, and the correct subtraction.

AQA 20213 marksCalcium carbonate decomposes when heated: CaCO3CaO+CO2CaCO_3 \rightarrow CaO + CO_2. A student heats 25.025.0 g of calcium carbonate in an open container until no further change occurs. Explain why the mass measured at the end is less than 25.025.0 g, and name the substance lost. Calculate the relative formula mass of calcium carbonate. Relative atomic masses: Ca = 40, C = 12, O = 16.
Show worked answer →

A 3-mark question testing apparent mass change plus an MrM_r calculation.

Explanation (1 mark): carbon dioxide gas is given off and escapes from the open container, so the mass of solid left behind is lower. Total mass including the gas is still conserved.

Substance lost (already in the explanation): carbon dioxide.

MrM_r of CaCO3=40+12+(3×16)=100CaCO_3 = 40 + 12 + (3 \times 16) = 100 (2 marks). Markers want the gas named and the statement that mass is only apparently lost.

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