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What are the basic electronic components, and how is Ohm's law used in a circuit?

Electronic components and quantities: conductors and insulators, resistors, capacitors, diodes and LEDs, and using Ohm's law V = I R.

A CCEA GCSE Technology and Design answer on basic electronics: conductors and insulators, resistors, capacitors, diodes and LEDs, current, voltage and resistance, and using Ohm's law V = I R including a current-limiting resistor calculation.

Generated by Claude Opus 4.812 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
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What this dot point is asking

CCEA wants you to know the basic electronic components - conductors and insulators, resistors, capacitors, diodes and LEDs - the quantities current, voltage and resistance, and how to use Ohm's law, V = I R, including working out a current-limiting resistor for an LED. This is the electrical foundation of the topic.

The answer

Conductors and insulators

Current, voltage and resistance

Common components

Ohm's law

Why an LED needs a resistor

Worked example: sizing a current-limiting resistor

Examples in context

Example 1. A wire and its insulation
Copper conducts the current along the wire; the plastic sleeve insulates it so it is safe to touch - conductor and insulator in one component.
Example 2. An LED indicator on a device
A small series resistor sets the LED current from the supply, using Ohm's law, so the LED is bright but not damaged.
Example 3. A potential divider in a sensor
A fixed resistor and a sensor resistor share the supply voltage, and Ohm's law explains how the voltage splits - the link to input subsystems.

Being able to use Ohm's law and size an LED resistor lets you answer both the straight calculation questions and the applied resistor-design questions.

Try this

Q1. Give one example of a conductor and one example of an insulator. [2 marks]

  • Cue. Conductor: copper (or any metal). Insulator: plastic, rubber or glass.

Q2. State Ohm's law. [1 mark]

  • Cue. V=IRV = I R (voltage = current x resistance).

Q3. A 12 V supply drives 0.04 A through a resistor. Calculate its resistance. [2 marks]

  • Cue. R=V/I=12/0.04=300 ΩR = V/I = 12/0.04 = 300\ \Omega.

Q4. Why does an LED need a series resistor? [2 marks]

  • Cue. To limit the current to a safe value; without it the LED would draw too much current and be destroyed.

Q5. What is the function of a diode? [1 mark]

  • Cue. It allows current to flow in one direction only.

Exam-style practice questions

Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

CCEA style3 marksA resistor has a voltage of 6 V across it and a current of 0.02 A through it. Calculate its resistance.
Show worked answer →

Rearrange Ohm's law for resistance: R=VIR = \dfrac{V}{I} (1).

R=60.02=300 ΩR = \dfrac{6}{0.02} = 300\ \Omega (1).

So the resistance is 300 ohms (1).

CCEA style4 marksAn LED needs 2 V across it and 20 mA through it from a 9 V supply. Calculate the value of the series resistor needed.
Show worked answer →

The resistor must drop the remaining voltage: 92=7 V9 - 2 = 7\ \text{V} (1).

The current is 20 mA=0.02 A20\ \text{mA} = 0.02\ \text{A} (1).

R=VI=70.02=350 ΩR = \dfrac{V}{I} = \dfrac{7}{0.02} = 350\ \Omega (1).

So a 350 ohm resistor (or the nearest standard value, e.g. 360 ohm) is needed to protect the LED (1).

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