How do forces change motion, what is the difference between mass and weight, and what affects stopping distance?
Balanced and unbalanced forces, Newton's first and second laws and F equals ma, the difference between mass and weight, terminal velocity, and the thinking, braking and stopping distances of a vehicle.
A focused CCEA GCSE Single Award Science answer on forces, covering balanced and unbalanced forces, Newton's first and second laws and F equals ma, the difference between mass and weight, terminal velocity, and the thinking, braking and stopping distances of a vehicle.
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What this dot point is asking
CCEA wants you to explain balanced and unbalanced forces, use Newton's first and second laws and , distinguish mass and weight, explain terminal velocity, and describe the thinking, braking and stopping distances of a vehicle.
Balanced and unbalanced forces
Newton's second law
The bigger the resultant force, the bigger the acceleration; the bigger the mass, the smaller the acceleration for the same force.
Mass, weight and terminal velocity
A falling object reaches terminal velocity when air resistance equals weight, so the resultant force is zero and (by Newton's first law) it falls at a constant maximum speed.
Stopping distances
Examples in context
Example 1. Why a skydiver reaches a steady speed. When a skydiver jumps, only weight acts at first, so they accelerate. As they speed up, air resistance grows until it equals their weight; the resultant force is then zero and they fall at a constant terminal velocity. Opening the parachute increases air resistance sharply, so they slow to a new, lower terminal velocity safe for landing. This is Newton's first law applied to falling.
Example 2. Why braking distance rises so steeply with speed. Doubling a car's speed does not double the braking distance, it roughly quadruples it, because the kinetic energy that the brakes must remove depends on the speed squared. This is why speed limits matter so much, and why CCEA asks you to explain that braking distance increases more than thinking distance as speed rises.
Try this
Q1. State Newton's second law as an equation. [1 mark]
- Cue. (resultant force equals mass times acceleration).
Q2. Calculate the weight of a 3 kg object where g is 9.8 N/kg. [1 mark]
- Cue. N.
Exam-style practice questions
Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
CCEA SAS 20213 marksA car of mass 1200 kg has a resultant force of 3600 N acting on it. Calculate its acceleration.Show worked answer →
Three marks for the formula, the rearrangement and the answer.
Use Newton's second law: resultant force equals mass times acceleration, F equals ma.
Rearrange to find acceleration: a equals F divided by m.
a equals 3600 divided by 1200, which equals 3 m/s squared.
So the acceleration is 3 m/s squared. Markers reward the correct formula, the rearrangement, and the answer with units.
CCEA SAS 20194 marksExplain the difference between mass and weight, and calculate the weight of a 5 kg object on Earth where g is 9.8 N/kg.Show worked answer →
Four marks for the two definitions and the calculation.
Mass is the amount of matter in an object, measured in kilograms, and is the same everywhere.
Weight is the force of gravity on an object, measured in newtons, and changes with the gravitational field strength.
Use weight equals mass times gravitational field strength: W equals mg.
W equals 5 times 9.8, which equals 49 N. Markers reward mass as matter in kg, weight as a force in N, and the correct calculation of 49 N.
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Sources & how we know this
- CCEA GCSE Science: Single Award specification — CCEA (2017)