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What is density, and how do we measure it for solids and liquids?

Density as mass per unit volume, the equation rho = m / V, and experiments to measure the density of regular solids, irregular solids and liquids.

A CCEA GCSE Physics answer on density as mass per unit volume, the equation rho = m / V, and the methods used to measure the density of regular solids, irregular solids and liquids.

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  1. What this dot point is asking
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What this dot point is asking

CCEA wants you to define density as mass per unit volume, use and rearrange the equation rho = m / V, and describe experiments to measure the density of regular solids, irregular solids and liquids. Density is also a practical-skills topic, so the methods are examined.

The answer

What density is

Water has a density of 1000 kg/m31000\ \text{kg/m}^3, which is the same as 1.0 g/cm31.0\ \text{g/cm}^3. Rearranging the equation gives m=ρVm = \rho V and V=m/ρV = m / \rho.

Measuring the density of a regular solid

For a regular solid such as a cube or cylinder:

  1. Measure the mass on a balance.
  2. Measure the dimensions with a ruler or vernier calliper and calculate the volume (for example length times width times height for a cuboid).
  3. Use ρ=m/V\rho = m / V.

Measuring the density of an irregular solid

For an awkward shape such as a stone, the volume is found by displacement:

Measure the mass with a balance, find the volume by displacement, then use ρ=m/V\rho = m / V.

Measuring the density of a liquid

  1. Measure the mass of an empty measuring cylinder.
  2. Pour in a known volume of the liquid and read the level (at eye level, bottom of the meniscus).
  3. Measure the mass of the cylinder and liquid, and subtract to find the mass of the liquid.
  4. Use ρ=m/V\rho = m / V.

Worked example: density of an oil

Examples in context

Example 1. Floating and sinking
An object floats if it is less dense than the fluid around it. Ice (density about 0.92 g/cm30.92\ \text{g/cm}^3) floats on water, while a steel nail sinks because steel is far denser than water.
Example 2. Choosing materials
Aircraft use low-density metals such as aluminium and titanium alloys so they are strong but light, reducing the weight that must be lifted.
Example 3. Hot-air and helium balloons
A balloon rises when the gas inside it is less dense than the surrounding air. Heating the air inside a hot-air balloon lowers its density; a party balloon filled with helium, which is naturally far less dense than air, floats upward for the same reason.

A common source of error in density experiments is reading the measuring cylinder inaccurately, or trapping air bubbles on an irregular solid when it is submerged. To improve reliability, take repeat readings, ensure the object is fully under water, and read the scale at eye level from the bottom of the meniscus.

Try this

Q1. Write the equation for density and state the unit of each quantity in SI units. [2 marks]

  • Cue. ρ=m/V\rho = m / V; density in kg/m cubed, mass in kg, volume in m cubed.

Q2. A 0.50 kg0.50\ \text{kg} block has a volume of 0.00025 m30.000\,25\ \text{m}^3. Find its density. [2 marks]

  • Cue. ρ=0.50/0.00025=2000 kg/m3\rho = 0.50 / 0.000\,25 = 2000\ \text{kg/m}^3.

Q3. How would you find the volume of an irregular stone? [1 mark]

  • Cue. By displacement: the rise in water level when the stone is fully submerged.

Exam-style practice questions

Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

CCEA style3 marksA block of metal has a mass of 270 g and measures 2.0 cm by 3.0 cm by 5.0 cm. Calculate its density in g per cubic cm and state, with a reason, whether it is aluminium (density 2.7 g per cubic cm).
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Volume of the block:

V=2.0×3.0×5.0=30 cm3.V = 2.0 \times 3.0 \times 5.0 = 30\ \text{cm}^3.

Density:

ρ=mV=27030=9.0 g/cm3.\rho = \dfrac{m}{V} = \dfrac{270}{30} = 9.0\ \text{g/cm}^3.

The calculated density is 9.0 g per cubic cm, which is much larger than 2.7, so the block is not aluminium.

Markers reward the volume, the density equation, the value 9.0, and a correct conclusion that it is not aluminium.

CCEA style4 marksDescribe how you would measure the density of an irregularly shaped stone using a balance and a measuring cylinder.
Show worked answer →

Measure the mass of the stone on a balance.

Part-fill a measuring cylinder with water and record the volume. Lower the stone in fully and record the new volume. The volume of the stone is the increase in water level (volume after minus volume before).

Calculate density using density = mass / volume.

Markers reward: mass from a balance; volume by displacement (difference in water levels); and dividing mass by volume.

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