Skip to main content
Northern IrelandMotor Vehicle & Road User StudiesSyllabus dot point

How do you calculate the speed, distance or time of a journey, and convert between units?

Using the speed-distance-time relationship to find any one quantity, average speed, and converting between mph and km/h and between hours and minutes.

A CCEA GCSE Motor Vehicle and Road User Studies answer on calculating speed, distance and time using the speed-distance-time triangle, finding average speed, and converting between units.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

CCEA wants you to use the speed-distance-time relationship to find any one of the three quantities, to calculate an average speed, and to convert between units (minutes to hours, and mph to km/h). Motoring mathematics is a whole content area of Unit 1, and speed-distance-time is the most common calculation.

The answer

The speed-distance-time relationship

A useful memory aid is the D-S-T triangle: with D on top and S and T below. Cover the quantity you want: cover D to get S×TS \times T; cover S to get D÷TD \div T; cover T to get D÷SD \div S.

Average speed

average speed=total distancetotal time.\text{average speed} = \frac{\text{total distance}}{\text{total time}}.

Getting the units right

The single biggest source of errors is time:

  • 40 minutes is not 0.40 hours. Convert minutes to hours by dividing by 60: 40÷60=23 h0.667 h40 \div 60 = \tfrac{2}{3}\ \text{h} \approx 0.667\ \text{h}.
  • 2 h 30 min =2.5 h= 2.5\ \text{h}; 2 h 15 min =2.25 h= 2.25\ \text{h}.

To convert speeds, use the approximate rule 5 miles ≈ 8 kilometres, so to change mph to km/h multiply by 85=1.6\tfrac{8}{5} = 1.6, and to change km/h to mph divide by 1.6. For distances the same rule applies: 10 miles is about 16 km.

Reading a time as hours and minutes

Calculations often give a decimal time that you must turn back into hours and minutes. The decimal part is a fraction of an hour, so multiply it by 60 to get the minutes. For example, 2.25 h2.25\ \text{h} is 2 hours and 0.25×60=150.25 \times 60 = 15 minutes, and 1.5 h1.5\ \text{h} is 1 hour 30 minutes. A time of 0.75 h0.75\ \text{h} is 0.75×60=450.75 \times 60 = 45 minutes.

Worked example: a journey in two parts

Worked example: finding the time for a journey

Examples in context

Example 1. Planning arrival time. Travelling 120 miles at an average of 48 mph takes 120÷48=2.5120 \div 48 = 2.5 hours, so a driver leaving at 09:00 arrives about 11:30.

Example 2. Reading a speed in km/h. A 50 km/h limit is about 50÷1.63150 \div 1.6 \approx 31 mph, close to the 30 mph urban limit.

Try this

Q1. A car travels 80 miles in 2 hours. What is its average speed? [1 mark]

  • Cue. 80÷2=4080 \div 2 = 40 mph.

Q2. Convert 1 hour 15 minutes into hours. [1 mark]

  • Cue. 1.25 hours.

Q3. A car travels at 60 km/h for 30 minutes. How far does it go? [2 marks]

  • Cue. 60×0.5=3060 \times 0.5 = 30 km.

Exam-style practice questions

Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

CCEA style3 marksA car travels 150 km in 2 hours 30 minutes. Calculate its average speed in kilometres per hour.
Show worked answer →

Average speed =distancetime= \dfrac{\text{distance}}{\text{time}}.

First write the time in hours: 2 h 30 min=2.5 h2\ \text{h}\ 30\ \text{min} = 2.5\ \text{h}.

average speed=1502.5=60 km/h.\text{average speed} = \frac{150}{2.5} = 60\ \text{km/h}.

Markers reward converting the time to 2.5 h, using speed = distance / time, and the answer 60 km/h.

CCEA style3 marksA driver travels at an average speed of 45 mph for 40 minutes. Calculate the distance travelled, in miles.
Show worked answer →

Distance =speed×time= \text{speed} \times \text{time}.

Convert the time to hours: 40 min=4060=23 h40\ \text{min} = \dfrac{40}{60} = \dfrac{2}{3}\ \text{h}.

distance=45×23=30 miles.\text{distance} = 45 \times \frac{2}{3} = 30\ \text{miles}.

Markers reward converting 40 minutes to two-thirds of an hour, using distance = speed × time, and the answer 30 miles.

Related dot points

Sources & how we know this