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How do you recognise, plot and interpret quadratic, cubic, reciprocal and other graphs?

Plot and recognise quadratic, cubic, reciprocal and exponential graphs, read roots and turning points, use graphs to solve equations, and recognise the equation of a circle and real-life graphs (Higher tier for non-linear).

A CCEA GCSE Mathematics answer on graphs and functions, covering quadratic cubic reciprocal and exponential graphs, reading roots and turning points, solving equations graphically, the equation of a circle, and interpreting real-life graphs.

Generated by Claude Opus 4.811 min answer

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  1. What this dot point is asking
  2. Quadratic graphs
  3. Cubic, reciprocal and exponential graphs
  4. Solving equations from graphs
  5. The equation of a circle (Higher)
  6. Real-life graphs
  7. Why this matters

What this dot point is asking

Beyond straight lines, the CCEA Algebra strand expects you to recognise, plot and interpret a family of curves. You must plot and recognise quadratic, cubic, reciprocal and (at Higher tier) exponential graphs, read off roots and turning points, use graphs to solve equations, recognise the equation of a circle, and interpret real-life graphs such as distance-time and rate graphs. Recognising a graph's shape from its equation, and reading information back from a graph, are the central skills.

Quadratic graphs

A quadratic equation plots as a parabola, a symmetrical U-shape. If the x2x^2 coefficient is positive the parabola opens upwards with a minimum; if negative it opens downwards with a maximum. The graph is made from a table of values, plotting the points and joining them with a smooth curve, never straight segments.

The key features are the roots (where the curve crosses the xx-axis, which are the solutions of y=0y = 0), the yy-intercept (where x=0x = 0, the constant term), and the turning point (the lowest or highest point, found from completing the square or symmetry).

Cubic, reciprocal and exponential graphs

A cubic y=ax3+…y = ax^3 + \ldots has a characteristic S-shape and can cross the xx-axis up to three times. A reciprocal y=kxy = \tfrac{k}{x} has two separate branches that approach but never touch the axes (asymptotes), in opposite quadrants. An exponential y=axy = a^x (with a>1a > 1) passes through (0,1)(0, 1) and increases more and more steeply; it models growth such as compound interest and populations. Recognising these shapes from the equation is examined directly.

Solving equations from graphs

A graph turns an equation into a picture, so solutions can be read off where curves cross.

The equation of a circle (Higher)

A circle centred at the origin with radius rr has equation x2+y2=r2x^2 + y^2 = r^2. So x2+y2=25x^2 + y^2 = 25 is a circle of radius 55 centred at (0,0)(0, 0). You should be able to write down the centre and radius from the equation, and recognise this graph among the others. CCEA also links this to the line-and-circle simultaneous case.

Real-life graphs

Graphs model real situations: a distance-time graph has gradient equal to speed (a horizontal section means stationary), and a conversion graph turns one quantity into another by reading across. Interpreting the gradient as a rate of change, and reading values from the axes, are the AO2 skills examined here.

Why this matters

Recognising and interpreting graphs connects every part of algebra: roots link to quadratic equations, intersections link to simultaneous equations, and gradient links to rates of change in measures and science. CCEA tests both drawing curves accurately from a table and extracting meaning from a given graph, so practise the smooth-curve technique and the reading-off method together.

Exam-style practice questions

Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

CCEA 20204 marksDraw the graph of y=x2βˆ’2xβˆ’3y = x^2 - 2x - 3 for βˆ’2≀x≀4-2 \le x \le 4 and use it to solve x2βˆ’2xβˆ’3=0x^2 - 2x - 3 = 0. (Calculator.)
Show worked answer β†’

Make a table of values: at x=βˆ’2,βˆ’1,0,1,2,3,4x = -2, -1, 0, 1, 2, 3, 4 the yy values are 5,0,βˆ’3,βˆ’4,βˆ’3,0,55, 0, -3, -4, -3, 0, 5.

Plot the points and join them with a smooth parabola (U-shaped), with the lowest point at (1,βˆ’4)(1, -4).

The solutions of x2βˆ’2xβˆ’3=0x^2 - 2x - 3 = 0 are where the curve crosses the xx-axis: x=βˆ’1x = -1 and x=3x = 3.

Marks are for the table, a smooth correct curve, and reading both roots. Joining the points with straight segments instead of a smooth curve loses a mark.

CCEA 20212 marksWrite down the centre and radius of the circle x2+y2=36x^2 + y^2 = 36. (Higher, non-calculator.)
Show worked answer β†’

The equation of a circle centred at the origin is x2+y2=r2x^2 + y^2 = r^2.

Comparing, r2=36r^2 = 36, so r=6r = 6.

The centre is the origin (0,0)(0, 0) and the radius is 66.

One mark is for the centre and one for the radius. A common error is to give the radius as 3636 instead of taking the square root.

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