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How do you work with composite and inverse functions, domain and range, and graph transformations?

Use function notation: form composite functions, find inverse functions, state domain and range, and apply transformations to the graphs of functions.

A CCEA GCSE Further Mathematics answer on functions and graphs, covering composite and inverse functions, domain and range, and the translations, reflections and stretches that transform graphs in the compulsory Pure unit.

Generated by Claude Opus 4.812 min answer

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  1. What this dot point is asking
  2. Composite functions
  3. Inverse functions
  4. Domain and range
  5. Transforming graphs
  6. Why this matters

What this dot point is asking

A function is a rule that takes an input and produces exactly one output, and CCEA GCSE Further Mathematics uses function notation seriously. You must form composite functions (applying one after another), find inverse functions (the rule that undoes a function), state the domain and range, and transform graphs by translating, reflecting and stretching them. These skills tie together the algebra and the graph work of the whole unit.

Composite functions

A composite function chains two functions, and the order is crucial. The notation fg(x)fg(x) means substitute g(x)g(x) into ff, so gg acts first. Read it from right to left, like layers of brackets.

For example, with f(x)=x+3f(x) = x + 3 and g(x)=2xg(x) = 2x, fg(x)=f(2x)=2x+3fg(x) = f(2x) = 2x + 3, whereas gf(x)=g(x+3)=2(x+3)=2x+6gf(x) = g(x + 3) = 2(x + 3) = 2x + 6. The two are different, which is exactly why the order matters in the exam.

Inverse functions

The inverse f1f^{-1} reverses the action of ff: if ff turns 33 into 77, then f1f^{-1} turns 77 back into 33. To find it, set y=f(x)y = f(x), rearrange to make xx the subject, then rewrite with xx as the input.

A useful check is that ff1(x)=xff^{-1}(x) = x, because doing a function and then undoing it returns the original input. Graphically, the inverse is the reflection of the function in the line y=xy = x, which swaps each (a,b)(a, b) for (b,a)(b, a).

Domain and range

The domain is the set of inputs a function is allowed to take, and the range is the set of outputs it produces. Some functions restrict the domain naturally: you cannot divide by zero, and you cannot take the square root of a negative number.

For f(x)=x2f(x) = \sqrt{x - 2}, the domain is x2x \ge 2 so the root is defined, and the range is f(x)0f(x) \ge 0 because a square root is never negative. Stating domain and range correctly is often worth marks in its own right, and a quick sketch makes the range easy to read.

Transforming graphs

Transformations move or reshape a graph in predictable ways. The rules split into changes outside the function (which affect yy) and inside the function (which affect xx, and act in the opposite sense to what you might expect).

Why this matters

Functions are the formal language for everything that follows: logarithms and exponentials are functions with their own inverses, trigonometric functions have ranges you must respect when solving equations, and calculus studies how a function changes. Graph transformations let you sketch new curves quickly from known ones, which saves time across the paper and supports the coordinate-geometry and trigonometry topics.

Exam-style practice questions

Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

CCEA Unit 1 (style)4 marksGiven f(x)=3x2f(x) = 3x - 2 and g(x)=x2+1g(x) = x^2 + 1, find fg(x)fg(x) and gf(x)gf(x).
Show worked answer →

For fg(x)fg(x), apply gg first then ff: fg(x)=f(g(x))=f(x2+1)=3(x2+1)2=3x2+1fg(x) = f(g(x)) = f(x^2 + 1) = 3(x^2 + 1) - 2 = 3x^2 + 1.

For gf(x)gf(x), apply ff first then gg: gf(x)=g(f(x))=g(3x2)=(3x2)2+1=9x212x+4+1=9x212x+5gf(x) = g(f(x)) = g(3x - 2) = (3x - 2)^2 + 1 = 9x^2 - 12x + 4 + 1 = 9x^2 - 12x + 5.

Marks are for the correct order in each composite and for the algebra. The most common error is doing them in the wrong order, since fgfg means gg acts first.

CCEA Unit 1 (style)3 marksFind the inverse function f1(x)f^{-1}(x) where f(x)=2x+15f(x) = \dfrac{2x + 1}{5}.
Show worked answer →

Write y=2x+15y = \dfrac{2x + 1}{5} and rearrange to make xx the subject.

Multiply by 55: 5y=2x+15y = 2x + 1. Subtract 11: 5y1=2x5y - 1 = 2x. Divide by 22: x=5y12x = \dfrac{5y - 1}{2}.

Swap the variable back: f1(x)=5x12f^{-1}(x) = \dfrac{5x - 1}{2}.

Marks are for rearranging correctly and for writing the inverse in function notation. A frequent slip is to stop before isolating xx, or to forget to rename yy as xx at the end.

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