Skip to main content
Northern IrelandPhysicsSyllabus dot point

How do physicists measure quantities and check that equations make sense?

Physical quantities, SI base and derived units, prefixes and standard form, homogeneity of equations, and estimating and handling uncertainties.

A CCEA A-Level Physics answer on physical quantities, SI base and derived units, prefixes and standard form, checking the homogeneity of equations by units, and handling absolute, fractional and percentage uncertainties.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

CCEA wants you to know the SI base quantities and units, build derived units from them, use prefixes and standard form, check whether an equation is homogeneous by comparing units on each side, and estimate and combine uncertainties in measured quantities. Homogeneity proofs and uncertainty combination are tested almost every series.

The answer

Base and derived units

A derived unit is a combination of base units. For example, the newton is 1 N=1 kg m s21\ \text{N} = 1\ \text{kg m s}^{-2} from F=maF = ma, and the joule is 1 J=1 kg m2s21\ \text{J} = 1\ \text{kg m}^2\,\text{s}^{-2}. Use prefixes (such as k\text{k} for 10310^{3}, m\text{m} for 10310^{-3}, μ\mu for 10610^{-6}) and standard form to keep numbers manageable.

Homogeneity of equations

For example, in v=u+atv = u + at each term has units of m s1\text{m s}^{-1}, so the equation is homogeneous and could be correct.

Uncertainties

The absolute uncertainty is the ±\pm range on a single measurement, often taken as half the smallest scale division or the spread of repeated readings.

Worked example: percentage uncertainty in a density

Examples in context

Example 1. Designing an experiment to minimise uncertainty. Because percentage uncertainties add, a CCEA student measuring the Young modulus picks the quantity with the largest percentage uncertainty (often the small extension) and improves it first, by using a longer wire so the extension is larger relative to its reading error.

Example 2. Sanity-checking a derived formula. Faced with a half-remembered equation in an exam, a quick homogeneity check on the base units catches a slip such as writing v2=u2+2atv^2 = u^2 + 2at (units of m2s2\text{m}^2\,\text{s}^{-2} versus m s1\text{m s}^{-1}) instead of the correct v2=u2+2asv^2 = u^2 + 2as, saving marks before any number is substituted.

Try this

Q1. Show that the unit of energy, the joule, is equivalent to kg m2s2\text{kg m}^2\,\text{s}^{-2}. [2 marks]

  • Cue. Use Ek=12mv2E_k = \tfrac{1}{2}mv^2, so units are kg×(m s1)2=kg m2s2\text{kg} \times (\text{m s}^{-1})^2 = \text{kg m}^2\,\text{s}^{-2}.

Q2. A length is measured as 0.250 m0.250\ \text{m} with an absolute uncertainty of 0.005 m0.005\ \text{m}. State its percentage uncertainty. [1 mark]

  • Cue. 0.0050.250×100=2%\frac{0.005}{0.250} \times 100 = 2\%.

Q3. A current of 0.50 A±2%0.50\ \text{A} \pm 2\% flows through a resistor of 12 Ω±3%12\ \Omega \pm 3\%. Find the percentage uncertainty in the power dissipated, given P=I2RP = I^2 R. [2 marks]

  • Cue. P=I2RP = I^2 R, so add 2×2%+3%=7%2 \times 2\% + 3\% = 7\%.

Exam-style practice questions

Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

CCEA 20195 marksThe period T of a mass m oscillating on a spring of spring constant k is suggested to be T equals 2 pi root of m over k. By writing each quantity in SI base units, show that this equation is homogeneous. Explain why a homogeneity check cannot confirm the factor of 2 pi.
Show worked answer →

The left-hand side, period TT, has the base unit of the second, s.

On the right, 2π2\pi is a dimensionless number. The spring constant kk has units of N per metre, and since 11 N =1= 1 kg m per second squared, kk has base units kg m s to the minus 2 per metre, which is kg s to the minus 2.

So mk\frac{m}{k} has units kgkg s2=s2\frac{\text{kg}}{\text{kg s}^{-2}} = \text{s}^2, and mk\sqrt{\frac{m}{k}} has units s2=s\sqrt{\text{s}^2} = \text{s}.

Both sides have the base unit of the second, so the equation is homogeneous.

A homogeneity check compares only units; the factor 2π2\pi is dimensionless, so it does not appear in the unit analysis. Any dimensionless constant (1, 2, 2π2\pi, and so on) would give the same units, so the check cannot confirm its value.

Markers reward base units for kk, reducing m/km/k to seconds squared, the square root giving seconds, and the dimensionless-constant explanation.

CCEA 20215 marksA student measures the diameter of a wire as 0.38 mm plus or minus 0.01 mm and its length as 1.250 m plus or minus 0.002 m. The resistance is measured as 4.5 ohm plus or minus 0.1 ohm. Calculate the percentage uncertainty in the resistivity, given that resistivity equals R A over L and the area depends on the diameter squared.
Show worked answer →

Resistivity is ρ=RAL\rho = \frac{RA}{L} with A=πd24A = \frac{\pi d^2}{4}, so ρRd2L\rho \propto \frac{R d^2}{L}.

Percentage uncertainty in RR: 0.14.5×100=2.2%\frac{0.1}{4.5} \times 100 = 2.2\%.

Percentage uncertainty in dd: 0.010.38×100=2.6%\frac{0.01}{0.38} \times 100 = 2.6\%. Because the diameter is squared, this contributes 2×2.6=5.2%2 \times 2.6 = 5.2\%.

Percentage uncertainty in LL: 0.0021.250×100=0.16%\frac{0.002}{1.250} \times 100 = 0.16\%.

For products, quotients and powers the percentage uncertainties add:

2.2+5.2+0.16=7.6%2.2 + 5.2 + 0.16 = 7.6\% (about 8%8\%).

Markers reward each percentage uncertainty, doubling the diameter's because it is squared, and adding them to give the total.

Related dot points

Sources & how we know this