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How are DNA and RNA structured, and how is DNA copied and used?

The structure of nucleotides, DNA and RNA, the base-pairing rules, semi-conservative DNA replication, and the role of ATP as the energy currency of the cell.

A CCEA A-Level Biology answer on the structure of nucleotides, DNA and RNA, complementary base pairing, semi-conservative DNA replication, and the role of ATP as the cell's energy currency.

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  1. What this dot point is asking
  2. Nucleotide and DNA structure
  3. Semi-conservative replication
  4. ATP
  5. Examples in context
  6. Try this

What this dot point is asking

CCEA wants you to describe the structure of a nucleotide and of DNA and RNA, state the complementary base-pairing rules, explain how DNA replicates semi-conservatively, and describe the structure and role of ATP as the energy currency of the cell.

Nucleotide and DNA structure

DNA is a double helix of two antiparallel polynucleotide strands (running in opposite directions). The bases pair by hydrogen bonding: adenine with thymine (two hydrogen bonds) and cytosine with guanine (three hydrogen bonds). This complementary base pairing means the two strands are exact templates of each other, and the amount of adenine equals thymine and cytosine equals guanine (Chargaff's rule). RNA is single-stranded, contains ribose instead of deoxyribose, and uses uracil in place of thymine. Messenger RNA carries the code from the nucleus to the ribosomes.

Semi-conservative replication

This mechanism was confirmed by the Meselson and Stahl experiment, which grew bacteria in heavy nitrogen (15N^{15}\text{N}) then light nitrogen (14N^{14}\text{N}) and used density centrifugation to show that after one round of replication every molecule was a hybrid of one heavy and one light strand, exactly as semi-conservative replication predicts.

ATP

ATP (adenosine triphosphate) is a phosphorylated nucleotide made of adenine, ribose and three phosphate groups. When the terminal phosphate is removed by hydrolysis, ATP becomes ADP plus inorganic phosphate (Pi\text{P}_\text{i}) and releases a small, usable amount of energy. ATP is the immediate energy currency of the cell because it is quickly made and broken down, releasing energy in small manageable amounts to power processes such as active transport, muscle contraction and synthesis. It is constantly recycled: ADP is re-phosphorylated to ATP using energy from respiration.

Examples in context

Example 1. Why a mutation can change a protein. During replication, a mismatched base may slip past proofreading, changing one base in a gene. Because base pairing is specific, that error is then copied faithfully into both daughter strands and all future cells. If the change alters a codon, it can change one amino acid in the protein (as in sickle-cell anaemia, where a single base change replaces glutamic acid with valine in haemoglobin). This shows how the very accuracy of base pairing also locks in any error that escapes repair.

Example 2. ATP turnover in a sprinting muscle. A working muscle uses ATP faster than respiration can supply it, so the small store is exhausted in seconds and must be regenerated continuously. The muscle uses creatine phosphate to rephosphorylate ADP almost instantly, then anaerobic and aerobic respiration to keep the ATP pool topped up. This illustrates why ATP, not glucose, is the immediate energy currency: it releases energy in small, fast, usable amounts exactly where and when it is needed.

Try this

Q1. State the base-pairing rules in DNA and the number of hydrogen bonds in each pair. [2 marks]

  • Cue. Adenine with thymine (two hydrogen bonds); cytosine with guanine (three hydrogen bonds).

Q2. Explain why DNA replication is described as semi-conservative. [2 marks]

  • Cue. Each new molecule has one original (conserved) strand and one newly synthesised strand.

Q3. A DNA molecule contains 18 percent guanine. Calculate the percentage of adenine. [2 marks]

  • Cue. Guanine equals cytosine (18 percent each, total 36 percent), so adenine plus thymine make 64 percent; adenine equals thymine, so adenine is 32 percent.

Exam-style practice questions

Practice questions written in the style of CCEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

CCEA 20196 marksDescribe the process of semi-conservative DNA replication and explain how the structure of DNA makes accurate copying possible.
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A 6-mark answer should give the ordered steps and link the base-pairing rules to accuracy.

DNA helicase unwinds the double helix and breaks the hydrogen bonds between the bases, so the two strands separate.

Each strand acts as a template. Free DNA nucleotides line up against the exposed bases following the complementary base-pairing rules (adenine with thymine, cytosine with guanine).

DNA polymerase joins adjacent nucleotides by forming phosphodiester bonds, building a new complementary strand on each template.

Each new DNA molecule has one original strand and one new strand, which is why replication is called semi-conservative.

Accuracy: because base pairing is specific (A only with T, C only with G), each template specifies exactly one complementary sequence, so the new strand is an exact copy. Polymerase also proofreads.

Markers reward helicase unwinding, template strands, complementary base pairing, polymerase joining nucleotides, and the link from specific pairing to accuracy.

CCEA 20214 marksA DNA sample contains 23 percent adenine. Using base-pairing rules, calculate the percentage of each of the other three bases, and explain the reasoning.
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A 4-mark answer needs the values and the rule that pairs are equal.

In DNA, adenine pairs with thymine and cytosine pairs with guanine, so the amount of adenine equals the amount of thymine, and cytosine equals guanine (Chargaff's rule).

If adenine is 23 percent, then thymine is also 23 percent.

Adenine plus thymine make 23+23=4623 + 23 = 46 percent, so cytosine plus guanine make 10046=54100 - 46 = 54 percent.

Since cytosine equals guanine, each is 542=27\frac{54}{2} = 27 percent.

So thymine 23 percent, cytosine 27 percent, guanine 27 percent.

Markers reward A equals T and C equals G, the subtraction to find the remaining 54 percent, and halving it.

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