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How do we plan a route to a target molecule, and how do infrared and mass spectra reveal structure?

Planning multi-step synthesis routes between functional groups using practical techniques (reflux, distillation, purification), and the analytical techniques of infrared spectroscopy (functional-group absorptions) and mass spectrometry (molecular ion and fragmentation).

An OCR H432 module 4 answer on organic synthesis and analysis: building multi-step reaction routes between functional groups, practical techniques, infrared spectroscopy for functional groups, and mass spectrometry for relative molecular mass and fragmentation.

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  1. What this topic is asking
  2. Planning a synthesis
  3. Infrared spectroscopy
  4. Mass spectrometry
  5. Examples in context
  6. Try this

What this topic is asking

OCR specification points 4.2.3 and 4.2.4 want you to plan multi-step synthesis routes between the functional groups of Module 4 using the correct reagents, conditions and practical techniques, and to identify functional groups and structures from infrared spectra and mass spectra. This is where the separate reactions become a connected reaction map and where instruments confirm what you have made.

Planning a synthesis

To plan a route, identify the functional groups in the starting material and target, then choose a chain of conversions connecting them, stating the reagent, conditions and mechanism type at each step. Shorter routes with higher atom economy are preferred.

Infrared spectroscopy

Key absorptions to recognise:

  • O-H\text{O-H} in an alcohol: broad, about 32003200 to 3550 cm13550\ \text{cm}^{-1}.
  • O-H\text{O-H} in a carboxylic acid: very broad, about 25002500 to 3300 cm13300\ \text{cm}^{-1}.
  • C=O\text{C=O} in aldehydes, ketones, acids and esters: sharp, about 16801680 to 1750 cm11750\ \text{cm}^{-1}.
  • C-H\text{C-H} in alkanes: about 28502850 to 2960 cm12960\ \text{cm}^{-1}.

Infrared absorption by atmospheric CO2\text{CO}_2, H2O\text{H}_2\text{O} and CH4\text{CH}_4 is also the molecular basis of the greenhouse effect.

Mass spectrometry

Examples in context

Example 1. Quality control in a pharmaceutical plant. Infrared and mass spectra are run on every batch of a drug intermediate to confirm the functional groups and relative molecular mass match the target, exactly the structure-determination skill tested here.

Example 2. Forensic identification. A mass spectrum of an unknown sample is matched against a database of fragmentation patterns to identify substances, relying on the same molecular-ion and fragment reasoning.

Try this

Q1. State what the molecular ion peak in a mass spectrum tells you. [1 mark]

  • Cue. Its m/zm/z value equals the relative molecular mass of the compound.

Q2. A compound absorbs strongly at 1715 cm11715\ \text{cm}^{-1} but shows no broad band above 3000 cm13000\ \text{cm}^{-1}. State the functional group present. [1 mark]

  • Cue. A carbonyl group C=O\text{C=O} (an aldehyde or ketone, since there is no O-H\text{O-H}).

Exam-style practice questions

Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

OCR 20194 marksDescribe a two-step synthesis of propan-1-ol starting from propene, giving the reagents and conditions for each step.
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Step 1: react propene with hydrogen bromide to form a bromopropane by electrophilic addition (1). (1-bromopropane is needed, so the anti-Markownikoff product; in practice the question accepts forming a bromopropane.)

Step 2: warm the bromopropane with aqueous sodium (or potassium) hydroxide (1); nucleophilic substitution replaces the bromine with -OH\text{-OH} to give propan-1-ol (1).

A valid route: propene to bromopropane (HBr, electrophilic addition), then bromopropane to propan-1-ol (warm aqueous NaOH, nucleophilic substitution) (1).

Markers reward two sensible steps with correct reagents and conditions, and the correct mechanism type at each stage.

OCR 20214 marksA compound X has a molecular ion peak at m/z=60m/z = 60 in its mass spectrum and a strong, broad absorption at 3000 cm13000\ \text{cm}^{-1} together with a sharp absorption at 1715 cm11715\ \text{cm}^{-1} in its infrared spectrum. Suggest the identity of X and justify your answer.
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The molecular ion at m/z=60m/z = 60 gives a relative molecular mass of 6060 (1). The broad absorption around 25002500 to 3300 cm13300\ \text{cm}^{-1} and the sharp peak at 1715 cm11715\ \text{cm}^{-1} indicate the O-H\text{O-H} and C=O\text{C=O} of a carboxylic acid group (1).

A carboxylic acid with Mr=60M_r = 60 is ethanoic acid, CH3COOH\text{CH}_3\text{COOH} (1)(1).

Markers reward reading MrM_r from the molecular ion, identifying the carboxylic acid from the two infrared absorptions, and combining them to give ethanoic acid.

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