How do we name organic compounds and represent the different ways their atoms can be arranged?
Formulae (empirical, molecular, general, structural, displayed and skeletal), homologous series and functional groups, IUPAC nomenclature, and isomerism (structural and E/Z stereoisomerism with Cahn-Ingold-Prelog priority).
An OCR H432 module 4 answer on the basics of organic chemistry: the six types of formula, homologous series and functional groups, IUPAC nomenclature, and structural and E/Z stereoisomerism using Cahn-Ingold-Prelog priority rules.
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What this topic is asking
OCR specification point 4.1.1 wants you to use the different types of formula, explain what a homologous series and a functional group are, name organic compounds by IUPAC rules, and recognise the two families of isomerism: structural (chain, position and functional group) and stereoisomerism (E/Z, decided by Cahn-Ingold-Prelog priority). This is the language that every later organic topic uses.
Types of formula
Skeletal formulae are the workhorse of organic chemistry because they are quick to draw and make functional groups stand out. Each line end or vertex is a carbon, and enough hydrogens are assumed to give each carbon four bonds.
Homologous series and functional groups
The Module 4 series are the alkanes, alkenes, alcohols and haloalkanes. An alkyl group has the general formula (methyl, ethyl, propyl) and appears as a branch.
IUPAC nomenclature
To name a compound:
- Find the longest carbon chain containing the functional group; this gives the stem (meth, eth, prop, but, pent).
- Add the suffix for the main functional group (-ane, -ene, -ol).
- Add prefixes for substituents (methyl, chloro) with locant numbers, chosen to give the lowest set of locants.
- Use di, tri, tetra for repeated groups and list substituents alphabetically.
So is 2-methylpropane and is but-2-ene.
Isomerism
E/Z isomerism needs two conditions: a double bond that restricts rotation, and two different groups on each carbon of the double bond.
Examples in context
Example 1. Why nomenclature matters in industry. A single molecular formula such as covers butane and 2-methylpropane (isobutane), which have different boiling points and uses (isobutane is a refrigerant). Systematic naming removes ambiguity so chemists worldwide describe the same molecule.
Example 2. E/Z isomerism in vision and fats. Restricted rotation about bonds underlies the cis-to-trans switch of retinal in the eye and the difference between cis (healthier) and trans (less healthy) fats, both direct consequences of the geometric isomerism introduced here.
Try this
Q1. State what is meant by a homologous series. [2 marks]
- Cue. A series of compounds with the same functional group and general formula, differing by , with similar chemical properties and a gradual change in physical properties.
Q2. Give the molecular formula of the alkene with empirical formula and three carbon atoms, and name it. [2 marks]
- Cue. , propene.
Exam-style practice questions
Practice questions written in the style of OCR exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
OCR 20193 marksA hydrocarbon has the empirical formula and a relative molecular mass of . (a) Determine its molecular formula. (b) Draw the skeletal formula of one possible position isomer that is an alkene.Show worked answer β
(a) The empirical formula mass of is . Dividing , so the molecular formula is (1).
(b) as an alkene is butene. A valid skeletal formula shows a four-carbon chain with the double bond drawn between carbons 1 and 2 (but-1-ene) or carbons 2 and 3 (but-2-ene) (1). Carbon atoms sit at the ends and bends of the lines and hydrogens on carbon are omitted (1).
Markers reward the correct molecular formula, an alkene skeletal structure with four carbons, and the skeletal convention applied correctly.
OCR 20212 marksState, with a reason, whether but-2-ene shows E/Z isomerism, and name the two stereoisomers.Show worked answer β
But-2-ene does show E/Z isomerism (1), because the double bond restricts rotation and each carbon of the double bond carries two different groups (a and an H), the requirement for E/Z isomerism.
The two isomers are E-but-2-ene (the two methyl groups on opposite sides) and Z-but-2-ene (the two methyl groups on the same side) (1).
Markers reward the correct decision plus the restricted-rotation and different-groups reason, and the correct E and Z names.
Related dot points
- Structure and bonding of alkanes (sigma bonds, tetrahedral carbon), boiling-point trends, complete and incomplete combustion, pollutants, and free-radical substitution with halogens (initiation, propagation, termination).
An OCR H432 module 4 answer on alkanes: sigma bonding and tetrahedral shape, boiling-point trends from London forces, complete and incomplete combustion and pollutants, and the free-radical substitution mechanism with halogens.
- Structure and bonding of alkenes (sigma and pi bonds, trigonal planar carbon), E/Z isomerism, electrophilic addition (hydrogen, halogens, hydrogen halides and steam), Markownikoff's rule, and addition polymerisation.
An OCR H432 module 4 answer on alkenes: pi bonding and trigonal planar shape, electrophilic addition with hydrogen, halogens, hydrogen halides and steam, Markownikoff's rule via the more stable carbocation, and addition polymerisation.
- Classification and properties of alcohols (hydrogen bonding), combustion, oxidation by acidified dichromate (primary to aldehyde and carboxylic acid, secondary to ketone, tertiary not oxidised), dehydration to alkenes, and substitution to haloalkanes.
An OCR H432 module 4 answer on alcohols: classification and hydrogen bonding, combustion, oxidation by acidified potassium dichromate to aldehydes, ketones and carboxylic acids, dehydration to alkenes, and conversion to haloalkanes.
- Polarity of the carbon-halogen bond, nucleophilic substitution (with hydroxide, cyanide and ammonia), the trend in hydrolysis rate with carbon-halogen bond enthalpy, elimination to alkenes, and the role of CFCs in ozone depletion.
An OCR H432 module 4 answer on haloalkanes: the polar carbon-halogen bond, nucleophilic substitution with hydroxide, cyanide and ammonia, the hydrolysis-rate trend with bond enthalpy, elimination to alkenes, and CFCs and ozone depletion.
- Planning multi-step synthesis routes between functional groups using practical techniques (reflux, distillation, purification), and the analytical techniques of infrared spectroscopy (functional-group absorptions) and mass spectrometry (molecular ion and fragmentation).
An OCR H432 module 4 answer on organic synthesis and analysis: building multi-step reaction routes between functional groups, practical techniques, infrared spectroscopy for functional groups, and mass spectrometry for relative molecular mass and fragmentation.
Sources & how we know this
- OCR A-Level Chemistry A (H432) specification β OCR (2015)