How do the properties of the elements repeat across the periodic table, and why?
Periodicity of atomic radius, ionisation energy and melting temperature across Periods 2 and 3, the s, p and d blocks, and the trends explained by electronic structure and nuclear charge.
An Eduqas A-Level Chemistry C1.6 answer on periodicity across Periods 2 and 3: trends in atomic radius, ionisation energy and melting temperature, the s, p and d blocks, and their explanation from electronic structure.
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What this topic is asking
Eduqas topic C1.6 covers periodicity: the repeating pattern of properties across periods, focusing on atomic radius, first ionisation energy and melting temperature across Periods 2 and 3. You must describe each trend and, crucially, explain it in terms of electronic structure, nuclear charge, shielding and the type of structure and bonding.
Blocks of the periodic table
Trend in atomic radius
Across a period, atomic radius decreases. Each successive element has one more proton, so the nuclear charge increases, but the added electron enters the same outer shell, so shielding barely changes. The stronger net attraction pulls the outer shell closer to the nucleus, so the atoms get smaller from left to right.
Trend in first ionisation energy
First ionisation energy rises across a period for the same reason: greater nuclear charge and smaller radius hold the outer electrons more tightly. The trend is not smooth, however; Eduqas expects the two characteristic dips to be explained.
Trend in melting temperature
Melting temperature across Period 3 reflects the structure of each element. The metals (Na, Mg, Al) have rising melting points as the metallic bonding strengthens (more delocalised electrons, smaller ions). Silicon, a giant covalent solid, has the highest melting point of all because covalent bonds must be broken. Then the simple molecular elements (, , ) and monatomic argon have low melting points set only by weak van der Waals forces.
Why periodicity matters
Examples in context
Example 1. Reactivity trends follow ionisation energy. Group 1 metals become more reactive down the group because the outer electron is further from the nucleus and more shielded, so the first ionisation energy falls and the electron is lost more readily.
Example 2. The diagonal high point of silicon. Across every short period the melting-temperature maximum sits at the Group 4 element, because that is where the giant covalent structure appears (carbon in Period 2, silicon in Period 3), a clear illustration of structure-controlled periodicity.
Try this
Q1. State and explain the trend in atomic radius down Group 2. [2 marks]
- Cue. Atomic radius increases down the group because each element has an additional electron shell, increasing shielding and distance from the nucleus, which outweighs the rising nuclear charge.
Q2. Identify the block of the periodic table for an element with configuration . [1 mark]
- Cue. The d-block (its highest-energy electrons are in the sub-shell); this element is iron.
Exam-style practice questions
Practice questions written in the style of WJEC Eduqas exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
Eduqas 20194 marksDescribe and explain the trend in first ionisation energy across Period 3 from sodium to argon.Show worked answer →
The general trend is an increase across the period (1). This is because nuclear charge increases while electrons are added to the same outer shell, so the outer electrons are held more strongly and harder to remove; the atomic radius also decreases (1).
There are two dips: aluminium is lower than magnesium because its outer electron is in a higher-energy sub-shell, easier to remove (1); sulfur is lower than phosphorus because its configuration has two electrons paired in one orbital, and the repulsion between them makes one easier to remove (1).
Eduqas 20213 marksExplain why the melting temperature of silicon is very high, but the melting temperature falls sharply from silicon to phosphorus across Period 3.Show worked answer →
Silicon has a giant covalent structure, so melting requires breaking many strong covalent bonds, giving a very high melting temperature (1).
Phosphorus exists as simple molecules held only by weak van der Waals forces (1). Far less energy is needed to overcome these intermolecular forces than to break the covalent network of silicon, so the melting temperature falls sharply (1).
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Sources & how we know this
- WJEC Eduqas GCE A Level Chemistry specification (from 2015) — WJEC Eduqas (2015)